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Science Forum Index » Statistics - Math Forum » Tough probability question. Your help needed!
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| Guest |
Posted: Tue Apr 29, 2008 9:51 pm |
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The gene for haemophilia (the inability of blood to clot) produces no
symptom in females, but a female who carries the gene will pass it on
to each of her children independently with probability ½ in each case.
Assume throughout this question that males with haemophilia
(haemophiliacs) do not marry or have children.
Mrs Smith is expecting her first child (a son), and it is known that
Mrs Smith's maternal uncle (the only brother of Mrs Smith's mother) is
a haemophiliac. Explain clearly why, in the light of this information,
the probability that Mrs Smith's son will be a haemophiliac is 1/8.
What would be the probability if instead it is known that Mrs Smith's
mother has four brothers, only one of whom is a haemophiliac? |
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| Nick |
Posted: Wed Apr 30, 2008 3:09 am |
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Guest
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hoolash@gmail.com wrote:
Quote: The gene for haemophilia (the inability of blood to clot) produces no
symptom in females, but a female who carries the gene will pass it on
to each of her children independently with probability ½ in each case.
Assume throughout this question that males with haemophilia
(haemophiliacs) do not marry or have children.
Mrs Smith is expecting her first child (a son), and it is known that
Mrs Smith's maternal uncle (the only brother of Mrs Smith's mother) is
a haemophiliac. Explain clearly why, in the light of this information,
the probability that Mrs Smith's son will be a haemophiliac is 1/8.
What would be the probability if instead it is known that Mrs Smith's
mother has four brothers, only one of whom is a haemophiliac?
Mrs Smith's Mother's Mother must be haemophiliac.
So Mrs Smith's Mother carries the gene with prob 1/2.
Mrs Smith carries gene with prob 1/2 * 1/2 = 1/4.
Mrs Smith passes on gene with prob 1/4/* 1/2 = 1/8.
The probability remains the same if only one of Mrs Smith's mother's
brothers is a haemophiliac. This is because Mrs Smith's mother is
haemophiliac if any of them are haemophiliac hence the odds don't change. |
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| Guest |
Posted: Wed Apr 30, 2008 10:25 am |
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| jojo |
Posted: Thu May 01, 2008 3:34 pm |
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| Ray Johnstone |
Posted: Fri May 02, 2008 12:46 am |
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On Wed, 30 Apr 2008 09:09:05 +0100, Nick <Nick.Spam@yahoo.co.uk>
wrote:
Quote: hoolash@gmail.com wrote:
The gene for haemophilia (the inability of blood to clot) produces no
symptom in females, but a female who carries the gene will pass it on
to each of her children independently with probability ½ in each case.
Assume throughout this question that males with haemophilia
(haemophiliacs) do not marry or have children.
Mrs Smith is expecting her first child (a son), and it is known that
Mrs Smith's maternal uncle (the only brother of Mrs Smith's mother) is
a haemophiliac. Explain clearly why, in the light of this information,
the probability that Mrs Smith's son will be a haemophiliac is 1/8.
What would be the probability if instead it is known that Mrs Smith's
mother has four brothers, only one of whom is a haemophiliac?
Mrs Smith's Mother's Mother must be haemophiliac.
I think you mean that she is a carrier, not a haemophiliac.
If she were, which is extremely rare, both her X chromosomes would be
affected and all her children would be certain to have a defective X.
Quote:
So Mrs Smith's Mother carries the gene with prob 1/2.
Mrs Smith carries gene with prob 1/2 * 1/2 = 1/4.
Mrs Smith passes on gene with prob 1/4/* 1/2 = 1/8.
The probability remains the same if only one of Mrs Smith's mother's
brothers is a haemophiliac. This is because Mrs Smith's mother is
haemophiliac if any of them are haemophiliac hence the odds don't change. |
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