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JackSarfatti
Posted: Wed Nov 08, 2006 8:19 pm
Joined: 06 Oct 2005 Posts: 602 Location: Toon Town
We do not need Diff(4) in its full generality. it is the stumbling block
to finite quantum gravity. We only need specialized cases of it with
constraints like local T4 tensor transformations.

Also Einstein's gravity as a local gauge theory with its "substratum"
tetrads and spin connections is a renormalizable spin 1 quantum field
theory. There is no need to go directly to the spin 2 composite
geometrodynamic level when quantizing in presence of vacuum ODLRO (like
superconducting Green's functions).

The only problem worth working on here is Edelen's claim supported by
Waldyr that locally gauging T4 ONLY gives torsion with zero curvature. I
think that's wrong for the following reasons:

1. Global gauge transformations of T4 on non-gravity source actions give
the symmetric stress-energy tensors of the source fields with

Tuv(source)^,v = 0 Minkowsku flat.

2. Local gauging of T4 changes that to (LC) covariant

Tuv(source)^;v = 0

3. Tuv(source) symmetric

4. Kibble says Tuv(source) non-symmetric with torsion, i.e. locally
gauging O(1,3).

5. You get Einstein's

Guv(geometry) = kTuv(source) from localizing T4 not O(1,3) so how can
you say no curvature?

5. Locally gauging only T4 gives the nontrivial tetrads A^a

e^ = I^a(flat) + A^a(warp)

6. Imposing zero torsion means

S^a = De^a = 0 zero Shipov torsion 2-form

i.e.

dA^a + W^ab/\e^b = 0

i.e. in component form

16 partial differential equations in A^au for 24 NONDYNAMICAL "Ricci
coefficient" effective spin connection fields

W^a^bu = - W^b^au

This leaves 8 undetermined phase "gauge" degrees of freedom SAME as the
number in my vacuum ODLRO Goldstone phase model

Theta^a, Phi^a

that gives world hologram (anyon gravity on boundaries of volume) &
quantization of area (Bekenstein) from DeRham integrals around a point
defect of the SINGLE-VALUED vacuum ODLRO residual inflation field where
the two contracted Goldstone phases Theta & Phi are undefined.

That is, we get 1916 GR Riemann curvature as torsionless (LC) connection
geodesic deviation by locally gauging only T4 in source field action from

(LC)^luv = e^la(d/dx^u)e^av = (&^la + A^la)(dA^av/dx^u)

Obviously this Levi-Civita connection has no NON-ZERO local T4 tensor part

d/dx^u is a Lie algebra generator of T4 and LC is a global T4 tensor
though not a local T4 tensor

Ruvw^l = e^la[(d/dx^u)(d/dx^v) - (d/dx^v)(d/dx^u)]e^aw = local T4
induced curvature

Now when we also localize O(1,3) we get 24 more independent W*^a^bu
which add to the "curvature" and make

S^a =/= 0

And now Tuv(source) has SHIPOV TORSION terms that make it non-symmetric
- hence

PROPELLANTLESS PROPULSION NOT FORBIDDEN (C. Lanzcos)

More details anon.
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Bob Kolker
Posted: Wed Nov 08, 2006 9:53 pm
Guest
Jack Sarfatti wrote:
Quote:

And now Tuv(source) has SHIPOV TORSION terms that make it non-symmetric
- hence

PROPELLANTLESS PROPULSION NOT FORBIDDEN (C. Lanzcos)

More details anon.

So why haven't the Russians gotten to the Moon?

Bob Kolker
Bob Kolker
Posted: Wed Nov 08, 2006 11:05 pm
Guest
W. Dale Hall wrote:
Quote:


Bob Kolker wrote:

Jack Sarfatti wrote:


And now Tuv(source) has SHIPOV TORSION terms that make it
non-symmetric - hence

PROPELLANTLESS PROPULSION NOT FORBIDDEN (C. Lanzcos)

More details anon.



So why haven't the Russians gotten to the Moon?

Bob Kolker


Because they also discovered stationary travel.

That surely is reactionless propulsion. Just stay where you are.

Bob Kolker
 
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