| |
 |
|
|
Science Forum Index » Electronics - Design Forum » A problem that I need help with
Page 1 of 1
|
| Author |
Message |
| Guest |
Posted: Wed Feb 14, 2007 7:51 pm |
|
|
|
|
Hello everyone,
I have a quick questions and was wondering if anyone can offer some
help. My problem is I have a circuit with an inverted op amp where one
voltage (1V) is going into the negative input and another voltage (4V)
is going into the positive input. On the output RL = 10K Ohms. I have
to determine Vo, not Vout. Aol is equal to 100,000, Io(max) is equal
to 25ma and Vout is equal to 12V. How would I figure out Vo? |
|
|
| Back to top |
|
| D from BC |
Posted: Wed Feb 14, 2007 10:27 pm |
|
|
|
Guest
|
On 14 Feb 2007 15:51:11 -0800, mexican2020@gmail.com wrote:
Quote: Hello everyone,
I have a quick questions and was wondering if anyone can offer some
help. My problem is I have a circuit with an inverted op amp where one
voltage (1V) is going into the negative input and another voltage (4V)
is going into the positive input. On the output RL = 10K Ohms. I have
to determine Vo, not Vout. Aol is equal to 100,000, Io(max) is equal
to 25ma and Vout is equal to 12V. How would I figure out Vo?
What node is Vo..? Or Vo is on what?
D from BC |
|
|
| Back to top |
|
| mkaras |
Posted: Thu Feb 15, 2007 12:09 am |
|
|
|
Guest
|
On Feb 14, 3:51 pm, mexican2...@gmail.com wrote:
Quote: Hello everyone,
I have a quick questions and was wondering if anyone can offer some
help. My problem is I have a circuit with an inverted op amp where one
voltage (1V) is going into the negative input and another voltage (4V)
is going into the positive input. On the output RL = 10K Ohms. I have
to determine Vo, not Vout. Aol is equal to 100,000, Io(max) is equal
to 25ma and Vout is equal to 12V. How would I figure out Vo?
Is the Vo that you are striving to understand the 'offset voltage' ?
If so this is the voltage between the opamp inputs needed to set the
output voltage to zero. (Of course this definition will make the mose
sense on a layman level when the opamp is powered by bipolar +/-
supplies.
- mkaras |
|
|
| Back to top |
|
| |
|
Page 1 of 1
All times are GMT - 5 Hours
The time now is Wed Dec 03, 2008 10:56 pm
|
|