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Science Forum Index » Physics - Electromagnetic Forum » Neutron, electrostatic fields and strong force
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| Steersman |
 Posted: Mon Dec 11, 2006 1:50 pm |
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Guest
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Using basic electrostatic field theory, I did a numerical integration
over all space of the interaction between the electrostatic fields of
two electrons, which agreed (as expected) with Coulomb's Law. But I
found out that there is a spherical region between the two electrons
which is attractive - this region has only about 1/5th of the force
associated with the rest of the field, so the net effect remains
repulsive, and agrees with Coulomb's Law.
This region of attraction interested me, so I tried truncating the
field at a certain radius "r" from the electron, and found that:-
1. for separations greater than "2 r" there is no interaction between
the two electrons.
2. as the separation falls from "2 r" to "r" the attractive force
increases until the separation falls to about "1.05 r" then drops to
zero at "r" - a <NULL> point.
3. below "r" the force increases rapidly.
The force/separation curve looks just like the "nuclear strong force"
curve. So if the neutron had a positive electric field that followed
the inverse-square-law but was truncated at a radius of roughly 0.35
femtometers, and the "unit charge" of the field was 13 times that of
the electron, would it give the strong force? Such a neutron would sit
at the null point at a separation of "r" from its neighbours, and they
would tend to form something like a face-centred-cubic matrix.
I put a detailed graphical explanation at...
http://uk.geocities.com/steersman@btinternet.com/neutron_electric_field.html
Anyone got any more ideas on this? |
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| Autymn D. C. |
| Posted: Mon Dec 11, 2006 4:18 pm |
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| "It's turtles all the way down!" |
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