Is there an error in this contracted calculation...

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Is there an error in this contracted calculation...

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Jay R. Yablon...

Posted: Sun Oct 18, 2009 9:25 pm

Guest

I have attempted to obtain a contracted version of the relationship:

R^a_buv A_a = [&;_u, &;_v]A_b (2)

which defines the Riemann tensor. The calculation is in the one-page
file

http://jayryablon.files.wordpress.com/2009/10/can-you-find-the-error-in-this-calculation.pdf

The contracted result I end up with is:

R_au A^a = [&;_a, &;u] A^a (2)

where R_au is the Ricci tensor, but the mixed symmetry and antisymmetry
strikes me funny. I would like to know if this is a correct
calculation, and if I am missing anything.

Thanks,

Jay
____________________________
Jay R. Yablon
Email: jyablon at (no spam) nycap.rr.com
co-moderator: sci.physics.foundations
Weblog: http://jayryablon.wordpress.com/
Web Site: http://home.roadrunner.com/~jry/FermionMass.htm

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