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Science Forum Index » Physics - Research Forum » Exact value of Hydrogen line?...
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| Jay Bala... |
Posted: Sat Jul 12, 2008 4:35 pm |
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A few simple questions:
1) Whats the exact value of Hydrogen line?
2) And under what condition(s) is this value holds true?
Regards,
Jay Bala. |
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| Chalky... |
Posted: Sun Jul 13, 2008 11:42 am |
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On Jul 13, 3:35 am, Jay Bala <jay1b... at (no spam) aol.com> wrote:
Quote: A few simple questions:
1) Whats the exact value of Hydrogen line?
2) And under what condition(s) is this value holds true?
There are lots of them. See eg http://en.wikipedia.org/wiki/Hydrogen_spectral_series
If you mean the H-alpha line, it is given to 6 sig. fig. at
http://en.wikipedia.org/wiki/H-alpha
Exact value would be what you would expect to see if emitter and
detector are in the same state of motion at essentially the same
location. |
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| Uncle Al... |
Posted: Sun Jul 13, 2008 11:42 am |
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| Jay Bala... |
Posted: Wed Jul 16, 2008 3:52 am |
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Lets take the hyperfine, appears to be a basic and simpler model,
c/f= gives just a little over 21 cm right?
Also, what is the measurement error of this frequency?
Considering the time (seconds) and length (meters) are man made
numbers, is there some measurements or ratios that expresses these
values where these units cancel?
Regards,
Jay Bala.
On Jul 13, 5:42 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
> The "21 cm" hyperfine transition is 1.4204057517667 GHz. |
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| Richard Saam... |
Posted: Fri Jul 18, 2008 1:07 am |
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Jay Bala wrote:
Quote: Lets take the hyperfine, appears to be a basic and simpler model,
c/f= gives just a little over 21 cm right?
Also, what is the measurement error of this frequency?
Considering the time (seconds) and length (meters) are man made
numbers, is there some measurements or ratios that expresses these
values where these units cancel?
Regards,
Jay Bala.
On Jul 13, 5:42 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
The "21 cm" hyperfine transition is 1.4204057517667 GHz.
The "natural width" is determined by Heisenberg Uncertainty
delta E delta t => h/(4pi)
delta (h*f/2) * delta t => h/(4pi)
delta (f) * delta t => 1/(2pi)
delta t is the life time of the excited state
delta E is energy of transition
which is extremely long in case of the 21 cm line
as observed in the astrophysical context
making its "natural width" very small
as Uncle Al's number would imply.
Richard D. Saam |
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| Chalky... |
Posted: Fri Jul 18, 2008 9:32 am |
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On Jul 18, 12:07 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Quote: Jay Bala wrote:
Lets take the hyperfine, appears to be a basic and simpler model,
c/f= gives just a little over 21 cm right?
Also, what is the measurement error of this frequency?
Considering the time (seconds) and length (meters) are man made
numbers, is there some measurements or ratios that expresses these
values where these units cancel?
Regards,
Jay Bala.
On Jul 13, 5:42 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
The "21 cm" hyperfine transition is 1.4204057517667 GHz.
The "natural width" is determined by Heisenberg Uncertainty
delta E delta t => h/(4pi)
delta (h*f/2) * delta t => h/(4pi)
delta (f) * delta t => 1/(2pi)
delta t is the life time of the excited state
delta E is energy of transition
This doesn't sound right.
Delta t relates to the length of the wave train, hence the duration of
the transition, not the lifetime of the excited state, before it
relaxes.
Delta E relates to the spread of frequencies in the wave train, not to
the energy of the transition (which determines the centre frequency)
It is probably also worth mentioning that this "tight" uncertainty
constraint of h/(4pi) applies when the uncertainty is defined as the
standard deviation (sigma) for each component. Hence a more
conservatively meaningful interpretation of the duration of the wave
train would be 2 sigma....wouldn't it? You would then have nearly a
70% (fighting) chance of finding it somewhere in the range where you
think it is. |
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| Richard Saam... |
Posted: Thu Jul 24, 2008 9:25 am |
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Chalky wrote:
Quote: On Jul 18, 12:07 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Jay Bala wrote:
Lets take the hyperfine, appears to be a basic and simpler model,
c/f= gives just a little over 21 cm right?
Also, what is the measurement error of this frequency?
Considering the time (seconds) and length (meters) are man made
numbers, is there some measurements or ratios that expresses these
values where these units cancel?
Regards,
Jay Bala.
On Jul 13, 5:42 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
The "21 cm" hyperfine transition is 1.4204057517667 GHz.
The "natural width" is determined by Heisenberg Uncertainty
delta E delta t => h/(4pi)
delta (h*f/2) * delta t => h/(4pi)
delta (f) * delta t => 1/(2pi)
delta t is the life time of the excited state
delta E is energy of transition
This doesn't sound right.
Delta t relates to the length of the wave train, hence the duration of
the transition, not the lifetime of the excited state, before it
relaxes.
Delta E relates to the spread of frequencies in the wave train, not to
the energy of the transition (which determines the centre frequency)
In terms of the 21 cm hydrogen line,
http://en.wikipedia.org/wiki/Hydrogen_line#Cause_of_the_hydrogen_line
"This transition is highly forbidden with an extremely small probability
of 2.9E−15 /sec. This means that the time for a single isolated atom of
neutral hydrogen to undergo this transition is 1/2.9E−15 or 3.4E14 seconds"
from above:
delta f * delta t => 1/(2pi)
delta f * 3.4E14 => 1/(2pi)
delta f => 4.68E-16 Hz
The above observed significant digit frequency
1.4204057517667 GHz = 1,420,405,751.7667 Hz
Apparently other effects (doppler )
are broadening the width beyond the
natural lifetime Heisenberg uncertainty line width.
Richard D. Saam |
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| Chalky... |
Posted: Fri Jul 25, 2008 4:46 am |
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On Jul 24, 8:25 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Quote: Chalky wrote:
On Jul 18, 12:07 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Jay Bala wrote:
Lets take the hyperfine, appears to be a basic and simpler model,
c/f= gives just a little over 21 cm right?
Also, what is the measurement error of this frequency?
Considering the time (seconds) and length (meters) are man made
numbers, is there some measurements or ratios that expresses these
values where these units cancel?
Regards,
Jay Bala.
On Jul 13, 5:42 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
The "21 cm" hyperfine transition is 1.4204057517667 GHz.
The "natural width" is determined by Heisenberg Uncertainty
delta E delta t => h/(4pi)
delta (h*f/2) * delta t => h/(4pi)
delta (f) * delta t => 1/(2pi)
delta t is the life time of the excited state
delta E is energy of transition
This doesn't sound right.
Delta t relates to the length of the wave train, hence the duration of
the transition, not the lifetime of the excited state, before it
relaxes.
Delta E relates to the spread of frequencies in the wave train, not to
the energy of the transition (which determines the centre frequency)
In terms of the 21 cm hydrogen line,
http://en.wikipedia.org/wiki/Hydrogen_line#Cause_of_the_hydrogen_line
"This transition is highly forbidden with an extremely small probability
of 2.9E-15 /sec. This means that the time for a single isolated atom of
neutral hydrogen to undergo this transition is 1/2.9E-15 or 3.4E14 seconds"
from above:
delta f * delta t => 1/(2pi)
delta f * 3.4E14 => 1/(2pi)
delta f => 4.68E-16 Hz
The above observed significant digit frequency
1.4204057517667 GHz = 1,420,405,751.7667 Hz
Apparently other effects (doppler )
are broadening the width beyond the
natural lifetime Heisenberg uncertainty line width.
The observed error margin is ~ 5 E-5
The theoretical error margin is ~ 5 E-16
Just as the theoretical error margin requires an emission time of ~ 10
million years, the same applies for the required detection time. The
difference between the 2 error margins is ~ E 11 corresponding to a
required detection time of ~ 1 hour. This sounds reasonable. |
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| Richard Saam... |
Posted: Tue Jul 29, 2008 12:59 pm |
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Chalky wrote:
Quote: On Jul 29, 2:43 am, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
On Jul 27, 7:51 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
The observed error margin is ~ 5 E-5
The theoretical error margin is ~ 5 E-16
Just as the theoretical error margin requires an emission time of ~ 10
million years, the same applies for the required detection time. The
difference between the 2 error margins is ~ E 11 corresponding to a
required detection time of ~ 1 hour. This sounds reasonable.
It would be interesting to know
if the observational error margin ~ 5 E-5 Hz
in the observed frequency of astrophysical hydrogen 21 cm
1.4204057517667 GHz = 1,420,405,751.7667 Hz
represents a limit
below which astrophysical electromagnetic frequencies
cannot be observed.
Are any electromagnetic waves observed below 5 E-5 Hz ?
In principle, yes, but we are now straying into areas of practical
eletronics. If it were possible to produce a sufficiently high Q tuned
filter to admit a still tighter pass band, then that would pick out
which ever frequency it was tuned to. However, you would still end up
with the pulse from fthe filter being ten times as long if the spread
was reduced by a factor of ten.
Yes "in principle" but such a long period
1/ 5 E-5 Hz = 20,000 seconds (333 minutes) (5.6 hours)
may be an extreme test of practical electronic instrumentation,
but given such practical electronic instrumentation:
Are any electromagnetic astrophysical waves observed below 5 E-5 Hz ?
Richard D. Saam
The point is that ALL frequencies within this range exist, via Fourier
analysis.
A 5.6 hour aperture for an astrophysical source would introduce
serious Doppler shifts due to the Earth's rotation. This would broaden
not narrow the spectrum (unless you, personally, are prepared to
finance a radio observatory at the South Pole)
Which brings up the point:
From where was the frequency range observed
(including the +/- 5 E-5 Hz)?
1.4204057517667 GHz = 1,420,405,751.7667 Hz
The fundamental question is:
What broadens the Heisenberg Uncertainty 5E-16 Hz to 5E-5 Hz? |
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| Chalky... |
Posted: Wed Jul 30, 2008 4:06 pm |
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Guest
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On Jul 29, 11:59 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Quote: Chalky wrote:
On Jul 29, 2:43 am, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
On Jul 27, 7:51 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
The observed error margin is ~ 5 E-5
The theoretical error margin is ~ 5 E-16
Just as the theoretical error margin requires an emission time of ~ 10
million years, the same applies for the required detection time. The
difference between the 2 error margins is ~ E 11 corresponding to a
required detection time of ~ 1 hour. This sounds reasonable.
It would be interesting to know
if the observational error margin ~ 5 E-5 Hz
in the observed frequency of astrophysical hydrogen 21 cm
1.4204057517667 GHz = 1,420,405,751.7667 Hz
represents a limit
below which astrophysical electromagnetic frequencies
cannot be observed.
Are any electromagnetic waves observed below 5 E-5 Hz ?
In principle, yes, but we are now straying into areas of practical
eletronics. If it were possible to produce a sufficiently high Q tuned
filter to admit a still tighter pass band, then that would pick out
which ever frequency it was tuned to. However, you would still end up
with the pulse from fthe filter being ten times as long if the spread
was reduced by a factor of ten.
Yes "in principle" but such a long period
1/ 5 E-5 Hz = 20,000 seconds (333 minutes) (5.6 hours)
may be an extreme test of practical electronic instrumentation,
but given such practical electronic instrumentation:
Are any electromagnetic astrophysical waves observed below 5 E-5 Hz ?
Richard D. Saam
The point is that ALL frequencies within this range exist, via Fourier
analysis.
A 5.6 hour aperture for an astrophysical source would introduce
serious Doppler shifts due to the Earth's rotation. This would broaden
not narrow the spectrum (unless you, personally, are prepared to
finance a radio observatory at the South Pole)
Which brings up the point:
From where was the frequency range observed
(including the +/- 5 E-5 Hz)?
1.4204057517667 GHz = 1,420,405,751.7667 Hz
The fundamental question is:
What broadens the Heisenberg Uncertainty 5E-16 Hz to 5E-5 Hz?- Hide quoted text -
I have already answered that. The limited time available to make the
observation. |
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| Chalky... |
Posted: Wed Jul 30, 2008 4:06 pm |
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Guest
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On Jul 29, 11:59 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Quote: Chalky wrote:
On Jul 29, 2:43 am, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
On Jul 27, 7:51 pm, Richard Saam <rds... at (no spam) att.net> wrote:
Chalky wrote:
The observed error margin is ~ 5 E-5
The theoretical error margin is ~ 5 E-16
Just as the theoretical error margin requires an emission time of ~ 10
million years, the same applies for the required detection time. The
difference between the 2 error margins is ~ E 11 corresponding to a
required detection time of ~ 1 hour. This sounds reasonable.
It would be interesting to know
if the observational error margin ~ 5 E-5 Hz
in the observed frequency of astrophysical hydrogen 21 cm
1.4204057517667 GHz = 1,420,405,751.7667 Hz
represents a limit
below which astrophysical electromagnetic frequencies
cannot be observed.
Are any electromagnetic waves observed below 5 E-5 Hz ?
In principle, yes, but we are now straying into areas of practical
eletronics. If it were possible to produce a sufficiently high Q tuned
filter to admit a still tighter pass band, then that would pick out
which ever frequency it was tuned to. However, you would still end up
with the pulse from fthe filter being ten times as long if the spread
was reduced by a factor of ten.
Yes "in principle" but such a long period
1/ 5 E-5 Hz = 20,000 seconds (333 minutes) (5.6 hours)
may be an extreme test of practical electronic instrumentation,
but given such practical electronic instrumentation:
Are any electromagnetic astrophysical waves observed below 5 E-5 Hz ?
Richard D. Saam
The point is that ALL frequencies within this range exist, via Fourier
analysis.
A 5.6 hour aperture for an astrophysical source would introduce
serious Doppler shifts due to the Earth's rotation. This would broaden
not narrow the spectrum (unless you, personally, are prepared to
finance a radio observatory at the South Pole)
Which brings up the point:
From where was the frequency range observed
(including the +/- 5 E-5 Hz)?
1.4204057517667 GHz = 1,420,405,751.7667 Hz
Given that hydrogen is the simplest thing to model theoretically, I
would not be too surprised if it turns out to have been derived from
theory.
Quote: The fundamental question is:
What broadens the Heisenberg Uncertainty 5E-16 Hz to 5E-5 Hz
Under that theoretical scenario, that would be the limit of accuracy
of the theoretical model. |
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