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Science Forum Index » Statistics - Math Forum » sampling without replacement, nonuniform distribution...
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| ldemanet... |
Posted: Sun Jul 20, 2008 4:25 am |
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Consider random sampling from a collection of N labeled objects,
without replacement. We draw the first object according to a
nonuniform distribution p_1, ..., p_N. Call the result X_1. We draw
the second object among the remaining N-1, from the obviously
renormalized distribution p_j / (sum_{k not X_1} p_k). And so forth
similarly until K objects are drawn, with K <= N. Can we show that the
probability of any particular object being drawn after K draws is
greater than K * p_min, where p_min is the minimum of the original
p_j?
This looks like a problem that could be covered in some textbooks, but
I haven't found it so far. A naive induction in K fails for some
reason, and the expression I get for the desired probability is too
complex for me to analyze. Any help would be greatly appreciated and
duly acknowledged. |
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| Paul Rubin... |
Posted: Sun Jul 20, 2008 8:53 pm |
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ldemanet wrote:
Quote: Consider random sampling from a collection of N labeled objects,
without replacement. We draw the first object according to a
nonuniform distribution p_1, ..., p_N. Call the result X_1. We draw
the second object among the remaining N-1, from the obviously
renormalized distribution p_j / (sum_{k not X_1} p_k). And so forth
similarly until K objects are drawn, with K <= N. Can we show that the
probability of any particular object being drawn after K draws is
greater than K * p_min, where p_min is the minimum of the original
p_j?
This looks like a problem that could be covered in some textbooks, but
I haven't found it so far. A naive induction in K fails for some
reason, and the expression I get for the desired probability is too
complex for me to analyze. Any help would be greatly appreciated and
duly acknowledged.
The proof is not too hard, but USENET is not conducive to math notation
and I'm not sure if my server will let me attach a PDF to a USENET
posting. I'll e-mail it to you directly.
/Paul |
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