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Science Forum Index » Energy - Hydrogen Forum » McCain proposes $300 million prize ?? Can I trust...
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| Spaceman... |
Posted: Sat Jul 19, 2008 7:02 pm |
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Galen Hekhuis wrote:
Quote: On Sat, 19 Jul 2008 19:12:28 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The heat is an effect, and also a cause of a drain of energy.
No, the heat does not cause a drain.
I would love to know how you could accomplish that.
I would be making heaters that would not need energy.
:)
Quote: Do you think a wire that gets hot will not be less efficient
than a wire that does not get hot?
That largely depends on your definition of "efficient." It also
depends on what you consider to be hot.
No,
It depends on how much heat is used "for" the system.
If the system does not use the heat itself for work, it is
a complete loss no matter what you might think it will be.
As in the case of a clock that is not designed to work
off the heat any wires may create.
Quote: I said the heat that is now being generated by
the resistance and to run the clock is an extra drain
than the clock alone would have.
Again my apologies. I thought otherwise. You are incorrect in
calling it a "drain," however.
No, it is an energy drain. the energy is not being used
for what it is supposed to be used for.
It is instead being used to heat the resistance spot.
That is a drain of the energy.
Quote: It would create a higher drain, absolutely. I don't know why one
would add a heating element to a clock, but if battery powered it
would absolutely increase the drain on the battery.
That is what I have said.
I said the loose connection (the resistance factor) would cause
a drain that would be higher than just the clock alone would be.
Quote: Not at all. You would quickly notice that heat isn't free at all if
you tried to heat your house with clocks, even if you designed heating
elements into them.
I am the one saying such.
I am the one saying the heat will drain more energy than the clock
alone would.
C,mon man!
What I am saying matches all known physics of electricity.
The loose connection causes a "resistance" and that resistance
is in turn a "heating element" and such will drain more power
than a clock circuit that has no extra resistance.
--
James M Driscoll Jr
Spaceman |
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| Galen Hekhuis... |
Posted: Sat Jul 19, 2008 7:18 pm |
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On Sat, 19 Jul 2008 18:47:02 -0500, AZ Nomad
<aznomad.3 at (no spam) PremoveOBthisOX.COM> wrote:
Quote: On Sat, 19 Jul 2008 19:06:51 -0400, Galen Hekhuis <ghekhuis at (no spam) earthlink.net> wrote:
On Sat, 19 Jul 2008 18:47:18 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The current decreases and the resistance increases
and the voltage drops.
Correct.
but then you have one silly thing that normally does not occur
that you seem to be leaving out when a resistance occurs.
and that is of course the heating element that is a "drain"
Not at all. Almost all resistance dissipates heat, to some extent.
The heat is an effect, not a cause.
Sorry. That's bullshit. High resistance means almost zero current,
hence almost zero power, zero heat.
No it isn't. By the way, you should have said almost zero heat,
rather than zero heat. All circuits have some resistance, all
circuits produce heat, to some extent. Even your high resistance
model produces *some* heat.
Quote: For a fixed resistance, power is
E^2/R. As R rises, power drops.
that is higher than a normal clock drain to begin with
Absolutely not. The clock drain does not change at all.
Again, bullshit.
An open circuit will mean little voltage to the clock circuit and almost no
power.
The clock "drain," or "load," does not change at all. When you open
a circuit containing a clock, the switch is in the wiring (power
supply), not the clock itself.
Quote: Or do you think that resistance does not produce heat at all
and cause more current drain?
Resistance almost always produces heat, which can be quite undesired
in many cases. It does not cause current drain, however.
bullshit. pure and simple bullshit.
Why don't you make an attempt to educate yourself before you spout
more nonsense.
Try googling for "ohm's law". This is *really* basic stuff.
Galen Hekhuis ghekhuis at (no spam) earthlink.net |
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| AZ Nomad... |
Posted: Sat Jul 19, 2008 7:44 pm |
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On Sat, 19 Jul 2008 20:18:27 -0400, Galen Hekhuis <ghekhuis at (no spam) earthlink.net> wrote:
Quote: On Sat, 19 Jul 2008 18:47:02 -0500, AZ Nomad
aznomad.3 at (no spam) PremoveOBthisOX.COM> wrote:
On Sat, 19 Jul 2008 19:06:51 -0400, Galen Hekhuis <ghekhuis at (no spam) earthlink.net> wrote:
On Sat, 19 Jul 2008 18:47:18 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The current decreases and the resistance increases
and the voltage drops.
Correct.
but then you have one silly thing that normally does not occur
that you seem to be leaving out when a resistance occurs.
and that is of course the heating element that is a "drain"
Not at all. Almost all resistance dissipates heat, to some extent.
The heat is an effect, not a cause.
Sorry. That's bullshit. High resistance means almost zero current,
hence almost zero power, zero heat.
No it isn't. By the way, you should have said almost zero heat,
rather than zero heat. All circuits have some resistance, all
circuits produce heat, to some extent. Even your high resistance
model produces *some* heat.
You said that "all most all resistance
dispates heat". That is basically false for high resistance. Generating a
ten thousanth of a degree F really doesn't count.
Quote: The clock "drain," or "load," does not change at all. When you open
a circuit containing a clock, the switch is in the wiring (power
supply), not the clock itself.
so fucking what? It isn't a signifigant load. A battery sitting unconnected
might take six weeks to self-discharge. Connect your horrible clock circuit,
through grubbly oxidized battery cables, and it might take a microsecond
longer to reach the same voltage level you consider to be a discharged
battery. It isn't worth considering. Meanshile you've got a shorted
alternator capable of draging down the whole mess in a five hours.
Again, why don't you educate your selfabout the relationship between
current, voltage, and resistance between you spout more nonsense? |
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| Galen Hekhuis... |
Posted: Sat Jul 19, 2008 7:54 pm |
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On Sat, 19 Jul 2008 20:02:02 -0400, "Spaceman"
<spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
Quote: Galen Hekhuis wrote:
On Sat, 19 Jul 2008 19:12:28 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The heat is an effect, and also a cause of a drain of energy.
No, the heat does not cause a drain.
I would love to know how you could accomplish that.
I would be making heaters that would not need energy.
How?
Quote: Do you think a wire that gets hot will not be less efficient
than a wire that does not get hot?
That largely depends on your definition of "efficient." It also
depends on what you consider to be hot.
No,
It depends on how much heat is used "for" the system.
If the system does not use the heat itself for work, it is
a complete loss no matter what you might think it will be.
As in the case of a clock that is not designed to work
off the heat any wires may create.
Like I said, it depends on your definition of "efficient."
Quote: I said the heat that is now being generated by
the resistance and to run the clock is an extra drain
than the clock alone would have.
Again my apologies. I thought otherwise. You are incorrect in
calling it a "drain," however.
No, it is an energy drain. the energy is not being used
for what it is supposed to be used for.
It is instead being used to heat the resistance spot.
That is a drain of the energy.
It is an undesired product. It is a waste. It is not a drain.
[if one were to add a heating element to a clock]
Quote: It would create a higher drain, absolutely. I don't know why one
would add a heating element to a clock, but if battery powered it
would absolutely increase the drain on the battery.
That is what I have said.
I said the loose connection (the resistance factor) would cause
a drain that would be higher than just the clock alone would be.
The loose connection is a higher resistance, which will decrease the
current in the circuit. A loose connection on the battery will not
increase the drain on the battery at all, but it may impede the
charging.
Think of the loose connection as a resistor, a current limiting
resistor. It will let small amounts of current pass, enough to run a
clock and thereby drain the battery. It will not, however, allow high
current to pass, such as a charge. What you have is a battery that
cannot be recharged but is constantly being discharged.
Quote:
Not at all. You would quickly notice that heat isn't free at all if
you tried to heat your house with clocks, even if you designed heating
elements into them.
I am the one saying such.
I am the one saying the heat will drain more energy than the clock
alone would.
C,mon man!
What I am saying matches all known physics of electricity.
The loose connection causes a "resistance" and that resistance
is in turn a "heating element" and such will drain more power
than a clock circuit that has no extra resistance.
Galen Hekhuis ghekhuis at (no spam) earthlink.net |
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| Spaceman... |
Posted: Sat Jul 19, 2008 7:58 pm |
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The Honorable Dr. Rocky Roads Presiding Judge wrote:
Quote: "Spaceman" <spaceman at (no spam) yourclockmalfunctioned.duh> wrote in message
news:yYudnT8mNvmToR_VnZ2dnUVZ_gmdnZ2d at (no spam) comcast.com...
Douglas W. "Popeye" Frederick wrote:
You are one arrogant bastard really.
LOL
Bullseye
Once Doug tried to tell me I was wrong about the "Dump Valve" on a
Spread Axle Trailer until he spoke to someone else that knows more
than he knows.
He truly shows he is one of those guys that is never wrong.
and you know and I know, that means he is wrong about at
"least one thing".
:)
--
James M Driscoll Jr
Spaceman |
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| Spaceman... |
Posted: Sat Jul 19, 2008 8:20 pm |
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Galen Hekhuis wrote:
Quote: On Sat, 19 Jul 2008 20:02:02 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
Galen Hekhuis wrote:
On Sat, 19 Jul 2008 19:12:28 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The heat is an effect, and also a cause of a drain of energy.
No, the heat does not cause a drain.
I would love to know how you could accomplish that.
I would be making heaters that would not need energy.
:)
How?
You are saying resistance will not cause extra energy needed
to overcome the resistance.
That would mean I could make clocks that have a lot
of resistance and heat the house while the clock keeps
the time and still use no extra energy.
:)
Quote: No, it is an energy drain. the energy is not being used
for what it is supposed to be used for.
It is instead being used to heat the resistance spot.
That is a drain of the energy.
It is an undesired product. It is a waste. It is not a drain.
It is a drain, if it is a waste at all.
Quote: The loose connection is a higher resistance, which will decrease the
current in the circuit. A loose connection on the battery will not
increase the drain on the battery at all, but it may impede the
charging.
Think of the loose connection as a resistor, a current limiting
resistor.
It is not a current limiting resistor.
Current limiting resistors are not designed by simply
making "bad connections"
If they were they would be made by the user instead of purchased.
It is a resistance that is creatign heat and losing energy.
Sometimes such is good,(heat sinks) and maybe even designed
into a system, but in a system where you don't want
such it is a drain no matter what you may think.
--
James M Driscoll Jr
Spaceman |
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| Galen Hekhuis... |
Posted: Sat Jul 19, 2008 8:25 pm |
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On Sat, 19 Jul 2008 19:44:23 -0500, AZ Nomad
<aznomad.3 at (no spam) PremoveOBthisOX.COM> wrote:
Quote: You said that "all most all resistance
dispates heat". That is basically false for high resistance. Generating a
ten thousanth of a degree F really doesn't count.
It's probably more than that. You can figure it out, by determining
the coefficient for your particular resistor. You can often get the
heat dissipation data for various resistors from the manufacturer.
Quote: The clock "drain," or "load," does not change at all. When you open
a circuit containing a clock, the switch is in the wiring (power
supply), not the clock itself.
so fucking what? It isn't a signifigant load. A battery sitting unconnected
might take six weeks to self-discharge.
My experience has been that it takes a bit longer.
Quote: Connect your horrible clock circuit,
through grubbly oxidized battery cables, and it might take a microsecond
longer to reach the same voltage level you consider to be a discharged
battery.
I think you mean to say it might take a shorter time, and the
difference would be much greater than a microsecond.
Quote: It isn't worth considering.
Granted.
Quote: Meanshile you've got a shorted
alternator capable of draging down the whole mess in a five hours.
As long as we're guessing, I don't think the original poster runs the
vehicle enough to recharge the battery, even with a perfect charging
system. That's where I'd start. Just run the thing longer. Less
than a mile in a week? And it is supposed to recharge from starting
the vehicle twice? Besides, that is the cheapest. Tighten up the
cables, check electrolyte in the battery, run the vehicle longer, and
maybe everything will be OK. Then again, it may be the charging
system. It could even be two (or more) things (customers always have
a hard time understanding that).
Quote: Again, why don't you educate your selfabout the relationship between
current, voltage, and resistance between you spout more nonsense?
Galen Hekhuis ghekhuis at (no spam) earthlink.net |
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| Douglas W. \"Popeye\" Frederick... |
Posted: Sat Jul 19, 2008 8:45 pm |
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Guest
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"Spaceman" <spaceman at (no spam) yourclockmalfunctioned.duh> wrote in message
news:Y5KdnTmQdOsAEB_VnZ2dnUVZ_jadnZ2d at (no spam) comcast.com...
Quote: The Honorable Dr. Rocky Roads Presiding Judge wrote:
"Spaceman" <spaceman at (no spam) yourclockmalfunctioned.duh> wrote in message
news:yYudnT8mNvmToR_VnZ2dnUVZ_gmdnZ2d at (no spam) comcast.com...
Douglas W. "Popeye" Frederick wrote:
You are one arrogant bastard really.
LOL
Bullseye
Once Doug tried to tell me I was wrong about the "Dump Valve" on a
Spread Axle Trailer until he spoke to someone else that knows more
than he knows.
At which time, I apologized, and stood myself corrected.
You've been caught wrong, or flat out lying (like about your CDL),
hundreds of times, and have never been man enough to admit it.
--
Popeye
"Best thing for him, really. His therapy
was going nowhere," -Hannibal Lector.
www.finalprotectivefire.com |
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| The Honorable Dr. Rocky Roads Presiding Judge... |
Posted: Sat Jul 19, 2008 8:51 pm |
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Guest
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"Spaceman" <spaceman at (no spam) yourclockmalfunctioned.duh> wrote in message
news:yYudnT8mNvmToR_VnZ2dnUVZ_gmdnZ2d at (no spam) comcast.com...
Quote: Douglas W. "Popeye" Frederick wrote:
You are one arrogant bastard really.
LOL
Bullseye
Once Doug tried to tell me I was wrong about the "Dump Valve" on a Spread
Axle Trailer until he spoke to someone else that knows more than he knows. |
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| Galen Hekhuis... |
Posted: Sat Jul 19, 2008 9:12 pm |
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On Sat, 19 Jul 2008 21:20:19 -0400, "Spaceman"
<spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
Quote: Galen Hekhuis wrote:
On Sat, 19 Jul 2008 20:02:02 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
Galen Hekhuis wrote:
On Sat, 19 Jul 2008 19:12:28 -0400, "Spaceman"
spaceman at (no spam) yourclockmalfunctioned.duh> wrote:
The heat is an effect, and also a cause of a drain of energy.
No, the heat does not cause a drain.
I would love to know how you could accomplish that.
I would be making heaters that would not need energy.
:)
How?
You are saying resistance will not cause extra energy needed
to overcome the resistance.
Not "overcome." Your clock doesn't "overcome" the increased
resistance, it "puts up" with it. If you measure the input voltage at
any of your accessories you will find it diminished by exactly the
amount of resistance added by the loose or corroded connection. In
other words, the voltage at the battery will measure higher than the
voltage at the cigarette lighter. If the accessory doesn't draw much
current itself, the voltage penalty imposed by the loose connection
will not be that great, and the accessory may still work. If,
however, the accessory draws a lot of current, the voltage penalty
will be severe, and the accessory may not work.
Quote: That would mean I could make clocks that have a lot
of resistance and heat the house while the clock keeps
the time and still use no extra energy.
No, you want *lower* resistance if you want heat. And you will use
more energy.
Quote: No, it is an energy drain. the energy is not being used
for what it is supposed to be used for.
It is instead being used to heat the resistance spot.
That is a drain of the energy.
It is an undesired product. It is a waste. It is not a drain.
It is a drain, if it is a waste at all.
If you wish to define "drain" as being "waste," fine, but a loose
terminal neither wastes nor drains electricity in the automotive
examples you give. The clock neither knows nor cares whether there is
a loose connection. It draws neither more nor less current whether it
is powered by a loose connection on a battery, a tight connection on a
battery, an A/C eliminator plugged into 110v A/C, whatever.
Quote: The loose connection is a higher resistance, which will decrease the
current in the circuit. A loose connection on the battery will not
increase the drain on the battery at all, but it may impede the
charging.
Think of the loose connection as a resistor, a current limiting
resistor.
It is not a current limiting resistor.
I know it isn't a current limiting resistor, but it acts like one.
Quote: Current limiting resistors are not designed by simply
making "bad connections"
If they were they would be made by the user instead of purchased.
It is a resistance that is creatign heat and losing energy.
It may be a waste, but your clock doesn't draw a even a smidgen more
power, current, what-have-you because of it. Remember E=IR. The
clock resistance stays constant, but in the case of the loose terminal
resistance in the circuit goes up. When resistance rises, current
*has* to go down, given a steady voltage. If you wish to take the
tiny decrease in battery voltage into account, then current decreases
even further.
Quote: Sometimes such is good,(heat sinks) and maybe even designed
into a system, but in a system where you don't want
such it is a drain no matter what you may think.
Galen Hekhuis ghekhuis at (no spam) earthlink.net |
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| marika... |
Posted: Sun Jul 20, 2008 7:43 am |
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"Douglas W. "Popeye" Frederick" <Popeye at (no spam) finalprotectivefire.com> wrote in
message news:ZpSdnUdQmYVAkx_VnZ2dnUVZ_g2dnZ2d at (no spam) supernews.com...
Quote:
Is there an electrical outlet anywhere near the car?
I know, I had thought about gettiing one of those rechargers. My car is
parked (assigned space) betweeen a post and the stairwell. I didn't see
anything close by but I am going to scope the walls near the elevator maybe
with an extenson cord? I'm skeptical though
mk5000
Jacques Grande: I'm going to make you a Quebec Pizza!
Prudence Roanoke: Oh, what is that?
Jacques Grande: Pop tart wid de ketchup. She's a good. --Love Guru |
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| marika... |
Posted: Sun Jul 20, 2008 7:52 am |
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"Spaceman" <spaceman at (no spam) yourclockmalfunctioned.duh> wrote in message
news:75SdnTyCKvtdgx_VnZ2dnUVZ_qXinZ2d at (no spam) comcast.com...
Quote:
It can when the power is trying to be used by something as simple
as the clock that is "always" on in pretty much every car made since
clocks were placed in cars..
I really think you should check such out.
The battery will drain faster when the circuit is not complete.
and it is a faster "drain".
The clock is a good theory for a drain. But what about the radio. I
haven't turned it on since it came back from the tune up in April. (I
haven't punched in the security code) If it's not on, is it still suspect?
mk5000
"you know, coz I'm on the road a lot, but I just love to get a card... Hey,
hey, hey, don't do that, that's my *tail*, that's my personal tail, you're
gonna tear it off! I don't give permission to... Hey, what're you gonna do
next? Oh, no, no, no, no... no! "--Shrek's Donkey |
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| marika... |
Posted: Sun Jul 20, 2008 7:54 am |
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Guest
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"Douglas W. "Popeye" Frederick" <Popeye at (no spam) finalprotectivefire.com> wrote in
message news:wK2dnbdDO5DJvh_VnZ2dnUVZ_uqdnZ2d at (no spam) supernews.com...
Quote:
I can't remember the last analog clock I saw in a car.
And yet! I have one. It's a 1995 car.
mk5000
"it didn't dawn on me til later that othr robots have laser eyes"--Andrew
Stanton |
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| marika... |
Posted: Sun Jul 20, 2008 7:59 am |
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"Douglas W. "Popeye" Frederick" <Popeye at (no spam) finalprotectivefire.com> wrote in
message news:oradnYrxgrOWrR_VnZ2dnUVZ_ofinZ2d at (no spam) supernews.com...
..
Quote:
"While high resistence in a connection can increased energy
consumption, that's not a "drain"."
I am sorry for forgetting the extra word in front of the word drain.
Shesh.
and I am sorry that a simple tightening of terminals can stop
such more than a few times in my experience with cars.
So just for thought, what do you do for a job and what experience
do you have in fixing cars?
See your other post.
I worked an autodealership as a bookkeeper. I guess that doesn't count.
However I am very good at consumption and draining
mk5000
" Time for lunch... in a cup! "-Ship's Computer: Wall-E |
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| marika... |
Posted: Sun Jul 20, 2008 8:03 am |
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Guest
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"Douglas W. "Popeye" Frederick" <Popeye at (no spam) finalprotectivefire.com> wrote in
message news:37qdnYbA5Mytqh_VnZ2dnUVZ_jmdnZ2d at (no spam) supernews.com...
Quote:
I didn't.
I said -you- were -trying- to.
A good example of a parasitic drain is a trunk or glovebox light that
doesn't shut off when the door-lid is closed.
Shorted voltage regulators in alternators, too.
The hardest one to find I ever saw was a used staple in the right read
door cigarette lighter of a Cadillac.
Aftermarket stereos incorrectly wired in is another regular criminal.
My old car an even older Saab had a bothersome drain. Took the guy a week
to find it. Turned out it was a loose wire in the dome light
mk5000
"C-3PO: No! We're not interested in the hyperdrive on the Millenium Falcon,
it's fixed!
[R2 beeps again]
C-3PO: Just open the door, you stupid lug! "--Star Wars, Empire Strikes Back |
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