John Larkin wrote:

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

One electron is -1.6e-19 coulomb. So if the coin is hit with one
electron, wouldn't there be a negative voltage of 1.6e-19 volt?

On Mon, 19 May 2008 21:59:23 -0700, "Green Xenon [Radium]"
glucegen1 at (no spam) excite.com> wrote:

Hi:

How many volts are generated by the difference of 1 electron? I would
imagine this value to be astronomically small.


Thanks,

Radium

Depends on what you dump it onto.

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

I repeat: you should take an elementary physics course and get
straight on basic stuff like this.

John

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

John Larkin wrote:


If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.


One electron is -1.6e-19 coulomb. So if the coin is hit with one electron,
wouldn't there be a negative voltage of 1.6e-19 volt?

John Larkin wrote:


If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.


One electron is -1.6e-19 coulomb.

electron, wouldn't there be a negative voltage of 1.6e-19 volt?

How many volts are generated by the difference of 1 electron?

In article <483339b3$0$7044$4c368... at (no spam) roadrunner.com>, Green Xenon



[Radium] wrote:
John Larkin wrote:

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

One electron is -1.6e-19 coulomb. So if the coin is hit with one
electron, wouldn't there be a negative voltage of 1.6e-19 volt?

  It would be 1.6e-19 volt divided by the coin's capacitance (to
ground) in farads.

  Charge in a capacitor is voltage times capacitance.  Voltage across a
capacitor is charge divided by capacitance.

  If you want some good reading, I totally recommend my favorite physics
textbook, "University Physics" by Sears, Zemansky and Young.  When I
was young, I often read that one when I had time to read, before I was
in highschool physics.  Any edition is good.  Libraries sometimes have it.

 - Don Klipstein (d... at (no spam) misty.com)

"Green Xenon [Radium]" wrote:

Hi:

How many volts are generated by the difference of 1 electron?

The question is meaningless.

An electron has CHARGE not voltage.

Graham

On May 21, 9:46 am, d... at (no spam) manx.misty.com (Don Klipstein) wrote:
In article <483339b3$0$7044$4c368... at (no spam) roadrunner.com>, Green Xenon



[Radium] wrote:
John Larkin wrote:

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

One electron is -1.6e-19 coulomb. So if the coin is hit with one
electron, wouldn't there be a negative voltage of 1.6e-19 volt?

  It would be 1.6e-19 volt divided by the coin's capacitance (to
ground) in farads.

  Charge in a capacitor is voltage times capacitance.  Voltage across a
capacitor is charge divided by capacitance.

  If you want some good reading, I totally recommend my favorite physics
textbook, "University Physics" by Sears, Zemansky and Young.  When I
was young, I often read that one when I had time to read, before I was
in highschool physics.  Any edition is good.  Libraries sometimes have it.

 - Don Klipstein (d... at (no spam) misty.com)

Good answer but not complete. Voltage is a measure of potential energy
and an electron can have as much energy as you wish if it is moving.
Your answer considers only the stationary charge component.

On Mon, 19 May 2008 21:59:23 -0700, "Green Xenon [Radium]"
glucegen1 at (no spam) excite.com> wrote:

Hi:

How many volts are generated by the difference of 1 electron? I would
imagine this value to be astronomically small.


Thanks,

Radium

Depends on what you dump it onto.

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

I repeat: you should take an elementary physics course and get
straight on basic stuff like this.

John

On May 19, 9:59 pm, "Green Xenon [Radium]" <gluceg... at (no spam) excite.com
wrote:
How many volts are generated by the difference of 1 electron?

In the context of 'electronics basics' this raises
a discussion of capacitance.

I prefer, however, the universal context, and the most
common items in the universe are hydrogen and stupidity.

So, a difference of one electron to a hydrogen atom is
my answer, the familiar 'ionization potential', 13.527 volts.

I can't think, right offhand, of a stupidity-based answer.

"John Larkin" <jjlarkin at (no spam) highNOTlandTHIStechnologyPART.com> wrote in message
news:26p5341m4p7gbu6bica3pgf0uu0mf9ogg6 at (no spam) 4ax.com...
On Mon, 19 May 2008 21:59:23 -0700, "Green Xenon [Radium]"
glucegen1 at (no spam) excite.com> wrote:

Hi:

How many volts are generated by the difference of 1 electron? I would
imagine this value to be astronomically small.


Thanks,

Radium

Depends on what you dump it onto.

If you hang a medium-sized coin from a string, it might have a
picofarad of capacitance to the world. Since

Q = C * V

and Qe, the charge on an electron, is -1.6e-19 colombs, then if you
whack the coin with one electron, the change in voltage is negative
about 160 nanovolts. Numbers like that aren't impossible to measure,
so it's feasible that some science-project level of effort could
measure single electron charges using Mouser-type parts.

I repeat: you should take an elementary physics course and get
straight on basic stuff like this.

John



I seem to recall an experiment by somebody named Millikan balancing oil
drops on a potential difference of several thousand volts. So, of course,
Wikipedia has an article on it, with pictures:

http://en.wikipedia.org/wiki/Oil-drop_experiment

(why remember anything these days?)

His experiment was fundamental in determining the charge on a single
electron, which is now thought to be

1.602176487(40) x 10?19

In order to generate a microvolt, that would need to be put on 1/6 of a
picofarad. So, your coin (which you measured later to be .4 picofarad) would
be high by a factor of 3. Maybe a dime would work?

BTW, how did you measure the capacitance of the quarter? It must be fun to
have all those cool toys laying around.

Regards,
Bob Monsen

Everybody should have one of these:

http://www.aade.com/lcmeter.htm

On Wed, 21 May 2008 21:38:09 -0700, John Larkin wrote:
...
Everybody should have one of these:

http://www.aade.com/lcmeter.htm


Well, one thing you have to admit, the guy selling them is certainly
entusastic!
^^^^^^^^^^

Cheers!
Rich