Main Page | Report this Page
 
   
Science Forum Index  »  Mathematics Forum  »  ^...
Page 1 of 1    
Author Message
Jon G....
Posted: Sat May 10, 2008 9:26 pm
Guest
Solve,

a_0*x^0 + a_1*x^1 + a_2*x^2 + ... +a_n*x^n = 0

x = ?

Let

Q=(a_0,a_1,a_2,...,a_n)
U=(1,1,1,...,1)
E=(1,1,1/2!,1/3!,1/4!,...,1/n!)
P=(1,x,x^2,x^3,....,x^n)

u=U/|U|

by vector analysis,

P*u=|Q|^2(E*P)/[(E*Q)(Q*u)]

express P as ratios of Q,U,E

qQ+rU+sE=P

dot both sides by Q,u,E and note that P*E=e^x.
Solve the matrix,

Q*Q Q*U Q*E | 0
Q*u U*u E*u | {|Q|^2/[(E*Q)(Q*u)]}e^x
Q*E E*U E*E | e^x

P/|P| = (s_0,s_1,s_2...) e^x cancels

P=P_u/s_0 because x^0=1

P=(p_0,p_1,p_2,p_3,...,p_n)=(1,x,x^2,x^3,..,x^n)

x=a+bi

(a+bi)^(1/n)
=
{a^2+b^2}^(.5/n)[cos((arctan(b/a)/n)] real
+{a^2+b^2}^(.5/n)[sin((arctan(b/a)/n)]i complex

by DeMoirve

x_n+1=x_n-
(a_0+a_1*x+a_2*x^2+a_3*x^3+...+a_n*x^n)
/
(a_1+2*a_2*x+3*a_3*x^2+...+n*a_n*x^(n-1) )

by Newton

This strategy has some flaws. You need n vectors to construct n dimensions,
but I only used 3. Also, it is only useful for large n in order to reflect
the contribution from E*U=e^x. It also generates numbers too large for
computing.

Its advantage is that it does produce some numbers to play around with
Newton's Method. Their initial values may or may not be accurate, but after
7 iterations and 50 repeats, does it really matter?

=(a_1+MMULT(s_2*TRANSPOSE(qd_2)*((r_iter_7d*TRANSPOSE(s_2))^TRANSPOSE(n_1_2))*COS(ang_iter_7d*TRANSPOSE(n_1_2)),n_2))
 
Page 1 of 1       All times are GMT - 5 Hours
The time now is Tue Oct 14, 2008 10:11 am