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Androcles
Posted: Thu May 01, 2008 7:07 am
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This message is brought to you by Androcles
http://www.androcles01.pwp.blueyonder.co.uk/

"Martin Hogbin" <goatNOSPAM1@hogbin.org> wrote in message
news:5_ydnfijPJdg4oTVnZ2dnUVZ8sGvnZ2d@bt.com...
| chaosfilter.com@gmail.com wrote:
| > On May 1, 11:54 am, "N:dlzc D:aol T:com \(dlzc\)" <dl...@cox.net>
| > wrote:
| >> Dearchaosfilter.com:
| >>
| >> <chaosfilter....@gmail.com> wrote in message
| >>
| >>
news:b6769dfb-f915-456b-a1b0-facb14e6eb09@k1g2000prb.googlegroups.com...
| >>
| >>> i'm just starting study in special relativity in an
| >>> undergrad course.
| >>> i can't quite figure this one out.
| >>> if i someone (A) is hurtling at a constant velocity
| >>> of -0.75c toward me, and from the other direction
| >>> someone else (A') is hurtling at a constant
| >>> velocity of 0.75 toward me. What is the velocity
| >>> of A' from the reference frame of A?
| >>> thanks in advance for any help on this
| >>
http://hermes.physics.adelaide.edu.au/~dkoks/Faq/Relativity/SR/veloci...
| >>
| >> ... and if you get stuck on something else
....http://hermes.physics.adelaide.edu.au/~dkoks/Faq/
| >>
| >> David A. Smith
| >
| > Thanks.
| >
| > I was using
| >
| > w - u
| > v = ---------
| > 1 - wu/c2
| >
| > when i should have been using (in the same axis)
| >
| > |u - v|
| > w = -------------
| > 1 - u v/c2
|
| Why?
|
Typical troll, totally clueless.
xxein
Posted: Thu May 01, 2008 1:54 pm
Guest
On Apr 30, 10:17 pm, chaosfilter....@gmail.com wrote:
Quote:
On May 1, 11:17 am,xxein<xxe...@bellsouth.net> wrote:





On Apr 30, 7:18 pm, chaosfilter....@gmail.com wrote:

i'm just starting study in special relativity in an undergrad course.

i can't quite figure this one out.

if i someone (A) is hurtling at a constant velocity of -0.75c toward
me, and from the other direction someone else (A') is hurtling at a
constant velocity of 0.75 toward me.  What is the velocity of A' from
the reference frame of A?

thanks in advance for any help on this

cf

xxein:  You will quickly come up to velocity addition in your studies
(if you haven't yet).  If you have and are still going nuts over this,
you can use logic and make a logical physics.  But in order to do so,
you will have to be very intelligent.  You will also need seasoning
(never enough).

I can't tell you how you will or should reason, but I can give you a
logic to understand this problem and solve it for a greater
satisfaction beyond the toutology you may encounter.

I should not give you a direct answer to your question because it may
allow you to give an answer to a test, but I will do so anyway.  It is
-0.96c.  I do so because I don't want you to fail a test and give it
all up.

You seem to be interested in physics-relativity (perhaps only in
general) and you are going to be taught a lot of things that won't
seem to make sense.  You will be taught formulae and relations that
that seem to come out of nowhere.  Well?  It's true.  It comes from
nowhere, but it seems to work.

It can only work because it does and you might be satisfied with
that.  But if you think as I do, it lacks logic in many ways ---
bigtime.  There is a major problem here in that that the logic we use
comes, not as a whole, but in separate packets.  Cosmology does not
give rise to relativity (except through c).  SR-GR does not create a
cosmology (it is baffled by galactic rotation).  QM  cannot recognise
a gravity.  Yet each is taught to be the 'science' you must learn in
order to progress to their level of understanding when they clearly
have none that unites to a logical sense.

So?  I may be bursting your bubble.  Fair or unfair?

The point here is that something seems to offend your rationality and
logic for velocity addition.  I can't blame you.  It's not you ---
it's the science that is taught.  It is not good enough to satisfy a
logic.

I'll post a reply to myself to give you some insight that you might
find usefull.

no bubble bursting...

i plugged the numbers into the formula listed on the page david posted
below, and got your answer.  p.s. wasn't an answer for a test, just my
own query (our text book had relative velocities in the same
direction, or without two being greater than 0.5).

for moi, instrumentally correct in the situations i am concerned with
will do for now Smile- Hide quoted text -

- Show quoted text -

xxein1: Good for you. But as you go along (unless you are stupid),
you will not be satisfied. Questions always remain that demand a
better logical understanding.

Until then, enjoy yourself.
xxein
Posted: Thu May 01, 2008 4:29 pm
Guest
On May 1, 1:48 am, "Androcles" <Headmas...@Hogwarts.physics> wrote:
Quote:
This message is brought to you by Androcles
 http://www.androcles01.pwp.blueyonder.co.uk/

chaosfilter....@gmail.com> wrote in message

news:b6769dfb-f915-456b-a1b0-facb14e6eb09@k1g2000prb.googlegroups.com...
| i'm just starting study in special relativity in an undergrad course.

Sure you are... but never mind that, anyone can ask.

| i can't quite figure this one out.
|
| if i someone (A) is hurtling at a constant velocity of -0.75c toward
| me, and from the other direction someone else (A') is hurtling at a
| constant velocity of 0.75 toward me.  What is the velocity of A' from
| the reference frame of A?

1.5c... but you knew that already, what you want to argue is the
crackpottery
Einstein wrote.

|
| thanks in advance for any help on this
|
| cf

xxein: "the reference frame of A" is what A will measure with his
clock and ruler. But this is dependent upon you (the central
measurer), being somehow stationary, who 'observes' -.75c for A and A'
converging from opposite directions.

But lightspeed does not depend upon your velocity, unless you fall
prey to the Einstein you hate.

What this means is that you have no guarantee that light is actually/
physically c to you. You may be traveling at .2c. In this case,
your judgement of the velocities of A and A' have already been
skewed. When you try to declare that their velocities are -.75c, it
is dependent upon your clock and ruler traveling at .2c.

This difference between you (.2c) and a stationary observer amounts to
a difference of how A observes A'. In this case, it is not an
objective reality of 1.5c -- it is 1.47314578005115c.
1.38461538461539c is how it reduced if you were traveling at .4c. You
don't have any idea of how to check this, do you?

How fast are you going right now? Let your cookie crumble but LET
will not. LET is more strictly principled than SR (this case scenario
of a flat space in the op's argument). Not that you adhere in any way
to SR, but that you'd better get more knowledgeable to LET.

And quit spewing your ill-founded garbage. You make a fool of
yourself to anyone of any considerate knowledge. Your 'theory' comes
across as saying something like to cure cancer, all you have to do
shove a printout of your 'theory' up your ass.

We all know your god is you.
Your space is psychedelic.
Your clockwork is orange.
Your brain is composed of inert matter.

Geez. Go to brainrot.com and leave us alone.
 
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