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Andrew Usher
Posted: Mon Apr 21, 2008 6:25 pm
Guest
On Apr 21, 4:06 pm, will...@cfa.harvard.edu (Steve Willner) wrote:

Quote:
If there's a simple explanation, I don't know it. The reason for the
general trend of shallower convective layers in hotter stars is the
one I gave in the previous post: hotter temperatures. Location of
convective zones is, of course, an output of any detailed model.

Degeneracy pressure, right? For a star to be convective all the way
down,
I believe it must have a source of support other than ideal gas
pressure or
it would be unstable. This is degeneracy in red dwarfs, and radiation
pressure in massive stars.

Andrew Usher
Crown-Horned Snorkack
Posted: Wed Apr 23, 2008 10:21 am
Guest
On 22 apr, 07:25, Andrew Usher <k_over_hb...@yahoo.com> wrote:
Quote:
On Apr 21, 4:06 pm, will...@cfa.harvard.edu (Steve Willner) wrote:

If there's a simple explanation, I don't know it. The reason for the
general trend of shallower convective layers in hotter stars is the
one I gave in the previous post: hotter temperatures. Location of
convective zones is, of course, an output of any detailed model.

Degeneracy pressure, right? For a star to be convective all the way
down,
I believe it must have a source of support other than ideal gas
pressure or
it would be unstable. This is degeneracy in red dwarfs, and radiation
pressure in massive stars.

I think that a star must have a source of support other than radiation

pressure to be stable. A star supported solely by radiation pressure
should be neutrally stable, however, so a minimal contribution of
perfect gas pressure would keep the star together.
Steve Willner
Posted: Thu Apr 24, 2008 11:53 am
Guest
In article <b80f3645-6a91-493f-87ae-bf685885f36a@24g2000hsh.googlegroups.com>,
Andrew Usher <k_over_hbarc@yahoo.com> writes:
Quote:
Degeneracy pressure, right?

Perhaps you are thinking of the stability of the entire star.
Degenerate cores are stable if their mass is below the "Chandrasekhar
limit" (about 1.4 solar masses) and unstable if more massive than
that. Stars supported entirely by radiation pressure (as very hot,
massive stars are) are also unstable.

Convective stability is a question of how energy is transferred in
each layer.

Quote:
For a star to be convective all the way down, I believe it must
have a source of support other than ideal gas pressure or it would
be unstable.

Nope. Red dwarfs are non-degenerate all the way down as long as
nuclear burning continues. So are massive stars burning hydrogen via
the carbon cycle.

--
Steve Willner Phone 617-495-7123 swillner@cfa.harvard.edu
Cambridge, MA 02138 USA
(Please email your reply if you want to be sure I see it; include a
valid Reply-To address to receive an acknowledgement. Commercial
email may be sent to your ISP.)
Crown-Horned Snorkack
Posted: Fri Apr 25, 2008 5:29 am
Guest
On 25 apr, 00:53, will...@cfa.harvard.edu (Steve Willner) wrote:
Quote:
In article <b80f3645-6a91-493f-87ae-bf685885f...@24g2000hsh.googlegroups.com>,
Andrew Usher <k_over_hb...@yahoo.com> writes:

Degeneracy pressure, right?

Perhaps you are thinking of the stability of the entire star.
Degenerate cores are stable if their mass is below the "Chandrasekhar
limit" (about 1.4 solar masses) and unstable if more massive than
that. Stars supported entirely by radiation pressure (as very hot,
massive stars are) are also unstable.

Convective stability is a question of how energy is transferred in
each layer.

For a star to be convective all the way down, I believe it must
have a source of support other than ideal gas pressure or it would
be unstable.

Nope. Red dwarfs are non-degenerate all the way down as long as
nuclear burning continues. So are massive stars burning hydrogen via
the carbon cycle.

Precisely how does "degenerate" matter differ from non-"degenerate"

liquid or solid?
Steve Willner
Posted: Mon Apr 28, 2008 11:31 am
Guest
In article <04281fea-a9ec-4e0c-85ba-fe0e976f078b@c58g2000hsc.googlegroups.com>,
Crown-Horned Snorkack <chornedsnorkack@hush.ai> writes:
Quote:
Precisely how does "degenerate" matter differ from non-"degenerate"
liquid or solid?

It's a matter of the "equation of state," which relates pressure to
temperature and density. In degenerate matter, the pressure comes
from the Fermi exclusion principle, either from electrons (in white
dwarfs and the cores of massive stars) or neutrons (in neutron
stars). Pressure depends on density but not at all on temperature.
In non-degenerate stars, pressure is given to a good approximation
by the ideal gas law and depends on both temperature and density.

There are probably more details on the web somewhere.

--
Steve Willner Phone 617-495-7123 swillner@cfa.harvard.edu
Cambridge, MA 02138 USA
(Please email your reply if you want to be sure I see it; include a
valid Reply-To address to receive an acknowledgement. Commercial
email may be sent to your ISP.)
Crown-Horned Snorkack
Posted: Tue Apr 29, 2008 10:04 am
Guest
On 29 apr, 00:31, will...@cfa.harvard.edu (Steve Willner) wrote:
Quote:
In article <04281fea-a9ec-4e0c-85ba-fe0e976f0...@c58g2000hsc.googlegroups.com>,
Crown-Horned Snorkack <chornedsnork...@hush.ai> writes:

Precisely how does "degenerate" matter differ from non-"degenerate"
liquid or solid?

It's a matter of the "equation of state," which relates pressure to
temperature and density. In degenerate matter, the pressure comes
from the Fermi exclusion principle, either from electrons (in white
dwarfs and the cores of massive stars) or neutrons (in neutron
stars).

And in liquids and solids, pressure comes from Fermi exclusion of
electrons.

Quote:
Pressure depends on density but not at all on temperature.

Compressing a solid or liquid changes its pressure a lot. Changing
temperature at constant pressure causes a small change of volume, and
changing temperature at constant volume causes small changes of
pressure, but small compared to the density dependence.

Quote:
In non-degenerate stars, pressure is given to a good approximation
by the ideal gas law and depends on both temperature and density.

And the pressure of light is independent of density.
Steve Willner
Posted: Wed Apr 30, 2008 9:57 am
Guest
In article <66aca9e2-db9c-4b06-9268-89a3387d6c44@34g2000hsf.googlegroups.com>,
Crown-Horned Snorkack <chornedsnorkack@hush.ai> writes:
Quote:
And in liquids and solids, pressure comes from Fermi exclusion of
electrons.

No, the pressure is from ordinary electromagnetic forces. White
dwarfs are a lot denser than ordinary liquids and solids.

Quote:
Compressing a solid or liquid changes its pressure a lot. Changing
temperature at constant pressure causes a small change of volume,

Yes.

Quote:
changing temperature at constant volume causes small changes of
pressure, but small compared to the density dependence.

No; it causes huge changes in pressure. Imagine heating the material
first at constant pressure, then trying to get the volume back to
where it was. That takes enormous pressure.

This is quite different behavior than degenerate matter.

Quote:
And the pressure of light is independent of density.

Light pressure depends on energy density, but I don't see what that
has to do with degenerate matter. In a star, the relevant pressure
is the sum of all forms of pressure. That includes magnetic
pressure, for example, but that would be trivally small in normal
stars.

--
Steve Willner Phone 617-495-7123 swillner@cfa.harvard.edu
Cambridge, MA 02138 USA
(Please email your reply if you want to be sure I see it; include a
valid Reply-To address to receive an acknowledgement. Commercial
email may be sent to your ISP.)
Andrew Usher
Posted: Wed Apr 30, 2008 10:29 am
Guest
On Apr 24, 3:53 pm, will...@cfa.harvard.edu (Steve Willner) wrote:
Quote:
In article <b80f3645-6a91-493f-87ae-bf685885f...@24g2000hsh.googlegroups.com>,
Andrew Usher <k_over_hb...@yahoo.com> writes:

Degeneracy pressure, right?

Perhaps you are thinking of the stability of the entire star.

No, I have worked it out.

Quote:
Convective stability is a question of how energy is transferred in
each layer.

Yes, convection occurs if the temperature gradient exceeds a critical
value; and because convection is so efficient, the gradient
practically does not exceed that value.

Quote:
For a star to be convective all the way down, I believe it must
have a source of support other than ideal gas pressure or it would
be unstable.

Nope. Red dwarfs are non-degenerate all the way down as long as
nuclear burning continues.

Wrong. A fully convective star must be described by a polytrope whose
index is equal to Cv - 3/2 for an ideal monoatomic gas. Therefore, it
is unstable against small changes in energy production (as long as Cv
is constant) and can hardly be expected to exist for a large fraction
of the main sequence. For a convective star to shrink further, its
core temperature would have to decrease, and thus its rate of fusion:
in sum, it will just keep contracting until degeneracy pressure
compensates for the deficiency in energy production.

Andrew Pliml
Crown-Horned Snorkack
Posted: Thu May 01, 2008 8:36 am
Guest
On 30 apr, 23:29, Andrew Usher <k_over_hb...@yahoo.com> wrote:
Quote:
On Apr 24, 3:53 pm, will...@cfa.harvard.edu (Steve Willner) wrote:

In article <b80f3645-6a91-493f-87ae-bf685885f...@24g2000hsh.googlegroups.com>,
Andrew Usher <k_over_hb...@yahoo.com> writes:

Degeneracy pressure, right?

Perhaps you are thinking of the stability of the entire star.

No, I have worked it out.

Convective stability is a question of how energy is transferred in
each layer.

Yes, convection occurs if the temperature gradient exceeds a critical
value; and because convection is so efficient, the gradient
practically does not exceed that value.

Agreed.


Quote:
For a star to be convective all the way down, I believe it must
have a source of support other than ideal gas pressure or it would
be unstable.

Nope. Red dwarfs are non-degenerate all the way down as long as
nuclear burning continues.

Wrong. A fully convective star must be described by a polytrope whose
index is equal to Cv - 3/2 for an ideal monoatomic gas. Therefore, it
is unstable against small changes in energy production (as long as Cv
is constant)

Explain why.

The temperature gradient in a convective star cannot be changed by
changes in energy production.
Crown-Horned Snorkack
Posted: Thu May 01, 2008 8:45 am
Guest
On 30 apr, 22:57, will...@cfa.harvard.edu (Steve Willner) wrote:
Quote:
In article <66aca9e2-db9c-4b06-9268-89a3387d6...@34g2000hsf.googlegroups.com>,
Crown-Horned Snorkack <chornedsnork...@hush.ai> writes:

And in liquids and solids, pressure comes from Fermi exclusion of
electrons.

No, the pressure is from ordinary electromagnetic forces.

No. Liquids and solids do not repel each other before their electrons
are brought to repel each other through Fermi repulsion.

Quote:
White
dwarfs are a lot denser than ordinary liquids and solids.

Compressing a solid or liquid changes its pressure a lot. Changing
temperature at constant pressure causes a small change of volume,

Yes.

changing temperature at constant volume causes small changes of
pressure, but small compared to the density dependence.

No; it causes huge changes in pressure. Imagine heating the material
first at constant pressure, then trying to get the volume back to
where it was. That takes enormous pressure.

If you heat water at 1 atm from 4 celsius to 100 celsius, its density

decreases from 1 to about 0,96. So, if you heat water at constant
density of 1,0 from 4 to 100 Celsius, the pressure changes by a
relatively large amount.

But compress water at 4 Celsius from density 1 to 2. It takes enormous
pressure.

Now heat it from 4 Celsius to 100 Celsius. The pressure would change -
but the change would be small compared to the huge pressure that is
already there.

Quote:
This is quite different behavior than degenerate matter.

And the pressure of light is independent of density.

Light pressure depends on energy density, but I don't see what that
has to do with degenerate matter. In a star, the relevant pressure
is the sum of all forms of pressure. That includes magnetic
pressure, for example, but that would be trivally small in normal
stars.

Sure. My point is that at low temperatures and high densities, it is

Fermi repulsion that dominates. At intermediate temperatures and
densities, it is gas pressure. At high temperatures and low densities,
it is light pressure.
Andrew Usher
Posted: Thu May 01, 2008 10:21 am
Guest
On May 1, 1:36 pm, Crown-Horned Snorkack <chornedsnork...@hush.ai>
wrote:

Quote:
For a star to be convective all the way down, I believe it must
have a source of support other than ideal gas pressure or it would
be unstable.

Nope. Red dwarfs are non-degenerate all the way down as long as
nuclear burning continues.

Wrong. A fully convective star must be described by a polytrope whose
index is equal to Cv - 3/2 for an ideal monoatomic gas. Therefore, it
is unstable against small changes in energy production (as long as Cv
is constant)

Explain why.

The temperature gradient in a convective star cannot be changed by
changes in energy production.

Not directly, but the radius can. If the star expands, the temperature
gradient
falls and it is no longer fully convective. If it shrinks, the central
temperature must
fall (due to convection) and therefore the star would continue
shrinking until
something catastrophic happened. Thus, it the absence of degeneracy,
it is
unstable.

Andrew Usher
 
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