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Science Forum Index » Mathematics Forum » Derivative of a circle
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| Guest |
 Posted: Thu May 01, 2008 2:36 pm |
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A circle is an unchanging curve therefor it cannot have a derivative.
Also it has no tangent. Tangents need to touch at two points to define
a slope. What is wrong is that a tangent cannot be found for one point
on a curve only two and that can only be approximated.
Mitch Raemsch |
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| porky_pig_jr@my-deja.com |
| Posted: Thu May 01, 2008 4:14 pm |
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On May 1, 8:36 pm, mitch.nicolas.raem...@gmail.com wrote:
Quote: A circle is an unchanging curve therefor it cannot have a derivative.
Also it has no tangent. Tangents need to touch at two points to define
a slope. What is wrong is that a tangent cannot be found for one point
on a curve only two and that can only be approximated.
Mitch Raemsch
the same crap, the same crap ... |
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| Ken Pledger |
| Posted: Thu May 01, 2008 8:15 pm |
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In article
<f01f6135-3ea2-4785-96e4-6acc2275b5c7@w4g2000prd.googlegroups.com>,
mitch.nicolas.raemsch@gmail.com wrote:
Quote: A circle is ....
Also it has no tangent....
Euclid thought it did, and his "Elements" III.16 & 17 don't use
any calculus.
Ken Pledger. |
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| Angus Rodgers |
| Posted: Thu May 01, 2008 8:42 pm |
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On Thu, 1 May 2008 17:36:19 -0700 (PDT),
mitch.nicolas.raemsch@gmail.com wrote:
Quote: A circle is an unchanging curve therefor it cannot have a derivative.
Also it has no tangent. Tangents need to touch at two points to define
a slope. What is wrong is that a tangent cannot be found for one point
on a curve only two and that can only be approximated.
There are no exact circles or straight lines or points anyway,
so we may as well all give up and go home. ;-)
--
Angus Rodgers
(twirlip@ eats spam; reply to angusrod@)
Contains mild peril |
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