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Student of Math
Posted: Thu Apr 24, 2008 7:12 am
Guest
On Apr 15, 5:00 pm, magi...@math.berkeley.edu (Arturo Magidin) wrote:
Quote:
In article <e05a3157-6fb1-4927-92ec-7a10f4a07...@b9g2000prh.googlegroups.com>,
Student of Math  <omar.hosse...@gmail.com> wrote:

   [...]

Where you have used ZF(C) in your proof?

There are STANDARD constructions of R using Q, Q using Z, Z using N,
and N using ZF (no choice needed at any stage), which show that
everything I did can be done in ZF. For example, you can see all of
these constructions (as well as the definitions required) in "Proof
and Fundamentals: A First Course in Abstract Mathematics" by Ethan
D. Bloch, Birkhauser Publ, 2000, Chapter 8 (pp 323-362). You construct
the naturals by using the Axiom of infinity. You construct the
integers as a set of equivalence classes of pairs of natural
numbers. You construct the rationals as a set of equivalence classes
of the set of all pairs (a,b) with a and b integers, b nonzero. Then
you construct the real numbers as pairs (L,R), where L and R are sets
of rationals satisfying certain properties. All is done at the level
of sets.

Now, how about ->your<- alleged argument for the Continuum Hypothesis?

--
=====================================================================> "It's not denial. I'm just very selective about
 what I accept as reality."
    --- Calvin ("Calvin and Hobbes" by Bill Watterson)
=====================================================================
Arturo Magidin
magidin-at-member-ams-org

I want to express it as soon as it possible.
Guest
Posted: Thu Apr 24, 2008 2:21 pm
On Apr 14, 5:29 am, Student of Math <omar.hosse...@gmail.com> wrote:
Quote:
Hi,
I think i have found a way to answer to Cantor's Continuum hypothesis
by using this
assumption : [0,1/3^n]={0} when n tends to the infinity.
If this assumption is from ZFC?

Regards,
Omar

.9 repeating plus the infinitely small equals one.

Infinite nonzero infinitesimals. Zero plus zero equals zero.

Mitch Raemsch
Arturo Magidin
Posted: Fri Apr 25, 2008 5:31 am
Guest
In article <dc56342a-5cf3-45b2-88c1-ccab6dabf732@i76g2000hsf.googlegroups.com>,
Student of Math <omar.hosseiny@gmail.com> wrote:
Quote:
On Apr 15, 5:00=A0pm, magi...@math.berkeley.edu (Arturo Magidin) wrote:

[...]

Quote:
Now, how about ->your<- alleged argument for the Continuum Hypothesis?

I want to express it as soon as it possible.

So... Who is stopping you?

--
======================================================================
"It's not denial. I'm just very selective about
what I accept as reality."
--- Calvin ("Calvin and Hobbes" by Bill Watterson)
======================================================================

Arturo Magidin
magidin-at-member-ams-org
James Dow Allen
Posted: Mon Apr 28, 2008 11:22 pm
Guest
On Apr 14, 8:59 pm, José Carlos Santos <jcsan...@fc.up.pt> wrote:
Quote:
On 14-04-2008 14:58, Student of Math wrote:
perhaps it maybe strang or impossible but, I think I have prove
Continuum Hypothesis
The Continuum Hypothesis can neither be proved nor disproved in ZFC.

Aren't you assuming ZFC is consistent?
Perhaps Student of Math has disproven that.

James
Tim Little
Posted: Tue Apr 29, 2008 2:51 am
Guest
On 2008-04-28, Student of Math <omar.hosseiny@gmail.com> wrote:
Quote:
What is your idea about this assumption:
There exists the smallest cardinal number |S_1| for which
aleph_0<|S_1| <=2^(aleph_0)

That one is true. So how does the proof use that to prove CH?


- Tim
Student of Math
Posted: Tue Apr 29, 2008 6:45 pm
Guest
On Apr 30, 5:00 am, hru...@odds.stat.purdue.edu (Herman Rubin) wrote:
Quote:
In article <03666749-9a48-4f82-8385-8e039d5a1...@a9g2000prl.googlegroups.com>,
James Dow Allen  <jdallen2...@yahoo.com> wrote:

On Apr 14, 8:59=A0pm, Jos=E9 Carlos Santos <jcsan...@fc.up.pt> wrote:
On 14-04-2008 14:58, Student of Math wrote:
perhaps it maybe strang or impossible but, I think I have prove
Continuum Hypothesis
The Continuum Hypothesis can neither be proved nor disproved in ZFC.
Aren't you assuming ZFC is consistent?
Perhaps Student of Math has disproven that.
James

The consistency of mathematics (ZF or NBG) is equivalent
to the consistency with either AC or not AC added, and
if AC is added, with CH or not CH added.w

If Student of Math has disproven that, we had better
change some of the axiomatization of set theory.
--
This address is for information only.  I do not claim that these views
are those of the Statistics Department or of Purdue University.
Herman Rubin, Department of Statistics, Purdue University
hru...@stat.purdue.edu         Phone: (765)494-6054   FAX: (765)494-0558

it is shameful, my proof was worng completely and, the struggle ended.
sorry for taking your valuable time.
Herman Rubin
Posted: Tue Apr 29, 2008 8:55 pm
Guest
In article <slrng1dkro.92b.tim@soprano.little-possums.net>,
Tim Little <tim@soprano.little-possums.net> wrote:
Quote:
On 2008-04-28, Student of Math <omar.hosseiny@gmail.com> wrote:
What is your idea about this assumption:
There exists the smallest cardinal number |S_1| for which
aleph_0<|S_1| <=2^(aleph_0)

That one is true. So how does the proof use that to prove CH?


Quote:
- Tim

I see no reason why it should be true without the Axiom
of Choice. With that axiom, it is aleph_1.
--
This address is for information only. I do not claim that these views
are those of the Statistics Department or of Purdue University.
Herman Rubin, Department of Statistics, Purdue University
hrubin@stat.purdue.edu Phone: (765)494-6054 FAX: (765)494-0558
Herman Rubin
Posted: Tue Apr 29, 2008 9:00 pm
Guest
In article <03666749-9a48-4f82-8385-8e039d5a14bf@a9g2000prl.googlegroups.com>,
James Dow Allen <jdallen2000@yahoo.com> wrote:
Quote:
On Apr 14, 8:59=A0pm, Jos=E9 Carlos Santos <jcsan...@fc.up.pt> wrote:
On 14-04-2008 14:58, Student of Math wrote:
perhaps it maybe strang or impossible but, I think I have prove
Continuum Hypothesis
The Continuum Hypothesis can neither be proved nor disproved in ZFC.

Aren't you assuming ZFC is consistent?
Perhaps Student of Math has disproven that.

James

The consistency of mathematics (ZF or NBG) is equivalent
to the consistency with either AC or not AC added, and
if AC is added, with CH or not CH added.w

If Student of Math has disproven that, we had better
change some of the axiomatization of set theory.
--
This address is for information only. I do not claim that these views
are those of the Statistics Department or of Purdue University.
Herman Rubin, Department of Statistics, Purdue University
hrubin@stat.purdue.edu Phone: (765)494-6054 FAX: (765)494-0558
Tim Little
Posted: Wed Apr 30, 2008 12:49 am
Guest
On 2008-04-30, Herman Rubin <hrubin@odds.stat.purdue.edu> wrote:
Quote:
I see no reason why it should be true without the Axiom of Choice.

True, "cardinal number" is potentially ambiguous notation. I
understood it to mean "initial ordinal" - in the absence of the axiom
of choice, not every set has a bijection with a cardinal number. As
opposed to more generic terminology such as "cardinality".


- Tim
MrKofner
Posted: Wed Apr 30, 2008 9:27 pm
Guest
On Apr 30, 9:59 am, magi...@math.berkeley.edu (Arturo Magidin) wrote:
Quote:
In article <83c7fc99-9293-4c3b-bed4-0510c8007...@y21g2000hsf.googlegroups.com>,
Student of Math <omar.hosse...@gmail.com> wrote:

it is shameful, my proof was worng completely and, the struggle ended.

Can't say I'm surprised.

sorry for taking your valuable time.

Had you presented your argument (with any caveats you wished) to begin
with instead of all that silly teasing and hedging and huffing, then
everyone's time (yours included) would have been better
served. Instead, you acted like a cheap strip-tease at a bad
vaudeville show.

--
======================================================================
"It's not denial. I'm just very selective about
what I accept as reality."
--- Calvin ("Calvin and Hobbes" by Bill Watterson)
======================================================================

Arturo Magidin
magidin-at-member-ams-org

Do remember though: he admitted he was wrong and did not stretch this
out into a 4000-post orgy. That counts for something.
 
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