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Science Forum Index » Energy Forum » Rotational KE of Earth
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| Guest |
 Posted: Wed Mar 19, 2008 7:25 pm |
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Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Bret Cahill |
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| Alex |
| Posted: Thu Mar 20, 2008 11:33 am |
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Guest
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On 20 Mar, 05:25, BretCah...@peoplepc.com wrote:
Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Try using exponential. Earth's mass is 6E24 kg.
Should this be under "Severn Tidal Barrage". |
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| Guest |
| Posted: Fri Mar 21, 2008 6:59 am |
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Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Try using exponential. Earth's mass is 6E24 kg.
Probably correct. I was too lazy to look it up.
Quote: Should this be under "Severn Tidal Barrage".
The gyro generator.
The axis of the gyro is oriented east west. Each time the earth
rotates the gyro revolves about a N-S axis.
Here's an Euler fun fact: Tape a book shut or other rectangularish
object that has sides with three different lengths, X,Y and Z.
Try to spin it about either of the two lower centroid axis.
Bret Cahill |
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| daestrom |
| Posted: Fri Mar 21, 2008 6:15 pm |
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Guest
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<BretCahill@peoplepc.com> wrote in message
news:7c315b1b-c9c4-482e-87fa-f1483ee15fba@s8g2000prg.googlegroups.com...
Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Not even the right formula. For rotating rigid bodies, you must use the
moment of inertia for the object. The formula you're using will tell you
the KE of a concentrated mass rotating not around it's own diameter, but
around a point in space R distance away from the mass.
The moment of inertia for a perfect sphere of uniform density (which the
earth is neither perfectly spherical, nor uniform density) would be....
I=2/5 mR^2
Google says the mass is 5.97e24 kg and the radius is about 6.370e6 m. so...
I = 2/5 * 5.97e24 * (6.37e6)^2 = 9.7e37 kg-m^2
KE = 1/2 I omega^2 = 1/2 *9.08e55* (7.3e-5)^2 = 2.56e29 Joules or 2.56e11
ExaJoules.
Now, go 'do it' if you can!
daestrom |
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| Guest |
| Posted: Sun Mar 23, 2008 5:08 pm |
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Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Not even the right formula. �
Next time you think you can out drink Boris Yeltsin just let me know.
Quote: For rotating rigid bodies, you must use the
moment of inertia for the object. �
Whatever.
Quote: The formula you're using will tell you
the KE of a concentrated mass rotating not around it's own diameter, but
around a point in space R distance away from the mass.
Who cares? The sun will burn out in < million years anyway.
Quote: The moment of inertia for a perfect sphere of uniform density (which the
earth is neither perfectly spherical, nor uniform density) would be....
I=2/5 mR^2
PROVE IT!
And NO, I will NOT take wikipedia as as reference.
Quote: Google says the mass is 5.97e24 kg and the radius is about 6.370e6 m. so....
Or Google.
Quote: I = 2/5 * 5.97e24 * (6.37e6)^2 = 9.7e37 kg-m^2
KE = 1/2 I omega^2 = 1/2 *9.08e55* (7.3e-5)^2 = 2.56e29 Joules or 2.56e11
ExaJoules.
Now, go 'do it' if you can!
Do we have any other choice?
Bret Cahill |
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| Bret Cahill |
| Posted: Sun Mar 23, 2008 8:31 pm |
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Guest
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Was it anything you can remember?
Bret Cahill |
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| Dan Bloomquist |
| Posted: Mon Mar 24, 2008 1:18 am |
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Guest
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BretCahill@peoplepc.com wrote:
Quote:
For rotating rigid bodies, you must use the
moment of inertia for the object. �
Whatever.
You have snipped that daestrom is posting. How convenient.
You don't know what moment of inertia is. Why do you play the man?
I'll cross post to all your favorite groups. You are an idiot. You
really need more plonking.... |
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| dedanoe |
| Posted: Mon Mar 24, 2008 3:47 am |
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Guest
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On Mar 24, 7:18 am, Dan Bloomquist <publi...@lakeweb.com> wrote:
Quote: BretCah...@peoplepc.com wrote:
For rotating rigid bodies, you must use the
moment of inertia for the object. �
Whatever.
You have snipped that daestrom is posting. How convenient.
You don't know what moment of inertia is. Why do you play the man?
I'll cross post to all your favorite groups. You are an idiot. You
really need more plonking....
it's not EARTH but AEART <=> A. IS ART <=> A.'s ART <=> The ART Of A. |
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| Bret Cahill |
| Posted: Mon Mar 24, 2008 5:33 am |
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Guest
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Quote: For rotating rigid bodies, you must use the
moment of inertia for the object. �
Whatever.
You have snipped that daestrom is posting. How convenient.
You don't know what moment of inertia is. Why do you play the man?
I'll cross post to all your favorite groups. You are an idiot. You
really need more plonking....
it's not EARTH but AEART <=> A. IS ART <=> A.'s ART <=> The ART Of A..
Exactly what I was trying to tell them.
Bret Cahill |
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| daestrom |
| Posted: Mon Mar 24, 2008 4:58 pm |
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Guest
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Quote: BretCahill@peoplepc.com> wrote in message
news:87919b20-7bf9-4410-8e19-2d073cb59e88@i29g2000prf.googlegroups.com...
Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Not even the right formula. ?
Next time you think you can out drink Boris Yeltsin just let me know.
Ah, that explains your posting, been trying to drink someone under the
table???
Quote:
For rotating rigid bodies, you must use the
moment of inertia for the object. ?
Whatever.
The formula you're using will tell you
the KE of a concentrated mass rotating not around it's own diameter, but
around a point in space R distance away from the mass.
Who cares? The sun will burn out in < million years anyway.
The moment of inertia for a perfect sphere of uniform density (which the
earth is neither perfectly spherical, nor uniform density) would be....
I=2/5 mR^2
PROVE IT!
Try...
"Applied Physics, 2nd Edition" 1978 Tippens, Paul E, McGraw-Hill
Pages 156-159
My daughter is currently using...
"College Physics, fifth edition", 2003, Wilson and Buffa, Prentice Hall.
Page 274 - 278
Or maybe just a high-school textbook would be more your speed....
"Physics, 2nd Edition" 1965 , D.C. Heath and Company, Boston
Since you can't be bothered with simple physics textbooks, I'm sure if I
were to derive the formula directly (requires calculus), it would also go
right over your head.
Quote:
And NO, I will NOT take wikipedia as as reference.
Who cares what YOU will 'take'. Just shows your closed-minded ignorance.
You might try...
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
But then you'd have to admit how ignorant you are, and we know you can't do
that. So I'm sure you'll try to discredit that citation as well.
Quote:
Google says the mass is 5.97e24 kg and the radius is about 6.370e6 m.
so...
Or Google.
Too bad. There are several references on-line you *could* avail yourself of
including some that show how the mass of the Earth is actually estimated.
But instead you chose to bury your head in the sand and invent your own
numbers. Oh well...
daestrom |
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| Bret Cahill |
| Posted: Tue Mar 25, 2008 8:17 am |
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Guest
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Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Not even the right formula. ?
Next time you think you can out drink Boris Yeltsin just let me know.
Ah, that explains your posting, been trying to drink someone under the
table???
This is no chat group for bean counters.
Bret Cahill |
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| daestrom |
| Posted: Tue Mar 25, 2008 3:44 pm |
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Guest
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"Bret Cahill" <BretCahill@aol.com> wrote in message
news:c082369e-93dc-490c-996b-dfdb2d1a418d@e10g2000prf.googlegroups.com...
Quote: Before we start extracting kinetic energy from the earth's rotation
and upset anyone's 24 hr. sleep cycle, we need to double check some
calculations.
First we'll need the density, mass, volume and centroid of the
earth.
If the radius is 4000 miles or 6 million meters, then the vol. is
216,000,000,000,000,000,000 million m^3.
(Check the order of magnitude.)
According to Zarathustra the heart of the earth is of gold.
The mass is therefore, 3,000,000,000,000,000,000,000,000 kg.
(Check the order of magnitude.)
Omega = 0.00007/sec
KE = 1/2 m (R omega)^2 =
100,000,000,000,000,000,000,000,000,000 (some units maybe joules).
OK let's do it!
Not even the right formula. ?
Next time you think you can out drink Boris Yeltsin just let me know.
Ah, that explains your posting, been trying to drink someone under the
table???
This is no chat group for bean counters.
Posted from sci.energy newsgroup.
Ah so typical. You snipped the SCIENCE textbook references about the ENERGY
involved in rotating objects. Probably because they show that you were
wrong and don't know much about SCIENCE or ENERGY.
Here, I'll put them back one more time in the hope you might learn to read a
book or two about SCIENCE and ENERGY before posting your nonsense
"Applied Physics, 2nd Edition" 1978 Tippens, Paul E, McGraw-Hill
Pages 156-159
My daughter is currently using...
"College Physics, fifth edition", 2003, Wilson and Buffa, Prentice Hall.
Page 274 - 278
Or maybe just a high-school textbook would be more your speed....
"Physics, 2nd Edition" 1965 , D.C. Heath and Company, Boston
Since you can't be bothered with simple physics textbooks, I'm sure if I
were to derive the formula directly (requires calculus), it would also go
right over your head.
Quote:
And NO, I will NOT take wikipedia as as reference.
Who cares what YOU will 'take'. Just shows your closed-minded ignorance.
You might try...
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
daestrom |
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| Bret Cahill |
| Posted: Wed Mar 26, 2008 1:39 pm |
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Guest
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Quote: Next time you think you can out drink Boris Yeltsin just let me know.
Ah, that explains your posting, been trying to drink someone under the
table???
This is no chat group for bean counters.
Posted from sci.energy newsgroup.
Ah so typical. �
If you are worried about being off by anything less than several
orders of magnitude, you have no plausible solutions to the
sustainability problem.
Bret Cahill |
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