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Science Forum Index » Mechanics Forum » planetary gear ratio calculations
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| Chris W |
Posted: Sun Feb 24, 2008 1:55 pm |
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Guest
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I have been trying to figure out what the gear ratio for a planetary
gear is when the sun gear is held stationary and the input and output
are the Planet carrier and Ring gear. I think the reason I can't find
anything that talks about that specific scenario is because it is always
a 2 to 1 ratio and for that reason probably never be used. Is that
correct or does it change with different size Sun, Planet and Ring gears?
--
Chris W
KE5GIX
"Protect your digital freedom and privacy, eliminate DRM,
learn more at http://www.defectivebydesign.org/what_is_drm"
Ham Radio Repeater Database.
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| Mechanical Magic |
Posted: Sun Feb 24, 2008 1:55 pm |
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On Feb 24, 9:55 am, Chris W <1qaz...@cox.net> wrote:
Quote: I have been trying to figure out what the gear ratio for a planetary
gear is when the sun gear is held stationary and the input and output
are the Planet carrier and Ring gear. I think the reason I can't find
anything that talks about that specific scenario is because it is always
a 2 to 1 ratio and for that reason probably never be used. Is that
correct or does it change with different size Sun, Planet and Ring gears?
--
Chris W
KE5GIX
"Protect your digital freedom and privacy, eliminate DRM,
learn more athttp://www.defectivebydesign.org/what_is_drm"
Ham Radio Repeater Database.http://hrrdb.com
Chris,
The size of the planet gears is irrelevant.
The ratio is the sun gear to the ring gear.
Think of a normal series of 3 gears. Input = 3" in diameter driving a
2" gear driving a 3" diameter (output).
The ratio is 1:1
Change the middle gear, Input to output ratio never changes.
Dave |
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| Brian Whatcott |
Posted: Sun Feb 24, 2008 9:27 pm |
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On Sun, 24 Feb 2008 11:55:44 -0600, Chris W <1qazse4@cox.net> wrote:
Quote: I have been trying to figure out what the gear ratio for a planetary
gear is when the sun gear is held stationary and the input and output
are the Planet carrier and Ring gear. I think the reason I can't find
anything that talks about that specific scenario is because it is always
a 2 to 1 ratio and for that reason probably never be used. Is that
correct or does it change with different size Sun, Planet and Ring gears?
Hmmm....it's been a while.
It's easy to show that that the planet will count twice as many ring
teeth as it counts sun teeth. And then the ratio starts looking like
2 X # sun teeth / # ring gear teeth. But the extra piece in the
formula that I have often forgotten is the 1 extra turn per
revolution as the planet carrier circles the sun. ,,,,But I am too
preoccupied at present to look up this formulation, which
features a "1 plus" in there somewhere....
Sorry
Brian W |
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| Brian Whatcott |
Posted: Sun Feb 24, 2008 10:36 pm |
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On Sun, 24 Feb 2008 19:27:25 -0600, Brian Whatcott
<betwys1@sbcglobal.net> wrote:
Quote: On Sun, 24 Feb 2008 11:55:44 -0600, Chris W <1qazse4@cox.net> wrote:
I have been trying to figure out what the gear ratio for a planetary
gear is when the sun gear is held stationary and the input and output
are the Planet carrier and Ring gear. I think the reason I can't find
anything that talks about that specific scenario is because it is always
a 2 to 1 ratio and for that reason probably never be used. Is that
correct or does it change with different size Sun, Planet and Ring gears?
Hmmm....it's been a while.
It's easy to show that that the planet will count twice as many ring
teeth as it counts sun teeth. And then the ratio starts looking like
2 X # sun teeth / # ring gear teeth. But the extra piece in the
formula that I have often forgotten is the 1 extra turn per
revolution as the planet carrier circles the sun. ,,,,But I am too
preoccupied at present to look up this formulation, which
features a "1 plus" in there somewhere....
Sorry
Brian W
[Second try...]
This URL
http://auto.howstuffworks.com/automatic-transmission1.htm
offers this formula for your case:
1/ (1 + S/R) for the gear ratio
for S = # of Sun teeth
R = # of ring teeth.
Example: sun has 20 teeth, ring has 40 teeth.
Ratio as given above: 1/1.5 or 0.667 to 1 (a speed up gear train)
Sometimes expressed as (1 + S/R) or 1.5 speed multiplier (!!!!)
Brian W
Brian Whatcott Altus OK |
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| Chris W |
Posted: Mon Feb 25, 2008 3:57 am |
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I guess I wasn't clear in my question. In a planetary gear there are
three different parts of the gear that can rotate about the center of
the assembly, the sun gear, the ring gear and the planet carrier. In
order for the assembly to be useful, one of the three has to be held
stationary. So far the 2 replies have addressed the configuration where
the planet carrier is held, and the configuration where the ring gear is
held. What I want to know is what happens when the sun gear is held
stationary. From what I have read so far, my guess is that regardless
of the gears, that ratio will always be 2 to 1. Can anyone confirm that?
--
Chris W
KE5GIX
"Protect your digital freedom and privacy, eliminate DRM,
learn more at http://www.defectivebydesign.org/what_is_drm"
Ham Radio Repeater Database.
http://hrrdb.com |
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| Brian Whatcott |
Posted: Mon Feb 25, 2008 8:48 am |
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Guest
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On Mon, 25 Feb 2008 01:57:48 -0600, Chris W <1qazse4@cox.net> wrote:
Quote: I guess I wasn't clear in my question. In a planetary gear there are
three different parts of the gear that can rotate about the center of
the assembly, the sun gear, the ring gear and the planet carrier. In
order for the assembly to be useful, one of the three has to be held
stationary. So far the 2 replies have addressed the configuration where
the planet carrier is held, and the configuration where the ring gear is
held. What I want to know is what happens when the sun gear is held
stationary. From what I have read so far, my guess is that regardless
of the gears, that ratio will always be 2 to 1. Can anyone confirm that?
Hi Chris, I pointed you to a URL with an animated diagram and formula
of the sun gear fixed case. Take a look.
Brian W |
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| Chris W |
Posted: Mon Feb 25, 2008 1:25 pm |
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Guest
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Brian Whatcott wrote:
Quote: On Mon, 25 Feb 2008 01:57:48 -0600, Chris W <1qazse4@cox.net> wrote:
I guess I wasn't clear in my question. In a planetary gear there are
three different parts of the gear that can rotate about the center of
the assembly, the sun gear, the ring gear and the planet carrier. In
order for the assembly to be useful, one of the three has to be held
stationary. So far the 2 replies have addressed the configuration where
the planet carrier is held, and the configuration where the ring gear is
held. What I want to know is what happens when the sun gear is held
stationary. From what I have read so far, my guess is that regardless
of the gears, that ratio will always be 2 to 1. Can anyone confirm that?
Hi Chris, I pointed you to a URL with an animated diagram and formula
of the sun gear fixed case. Take a look.
Sorry I should have looked at your link. I had already read one page
from that web site on the topic and figured your link was to the same
page, but it is not. That is a much better page than the one I had
found earlier, it very concisely gives formulas for all three
configurations. Thanks.
--
Chris W
KE5GIX
"Protect your digital freedom and privacy, eliminate DRM,
learn more at http://www.defectivebydesign.org/what_is_drm"
Ham Radio Repeater Database.
http://hrrdb.com |
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