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sekots
Posted: Mon Sep 03, 2007 8:04 pm
Guest
We are all familiar with the classic presentation of a solenoid with an iron
core, in which the high permeability core magnifies the strength of the
inducted filed. What about a situation with a permanent magnet? If I
bring a high permeability material into contact with a very strong permanent
magnet (e.g. neodymium magnet), do I get a similar field strengthening? My
specific question regards the coupling of a neodymium magnet and a piece of
“Mu” metal. This is a metal that supposedly has a permeability 25,000 times
that of free space at 0.002 Tesla. Does this mean that I will get a field of
25,000 Tesla within the Mu metal if I place it in contact with a Neodymium
magnet with a surface field strength of 1 Tesla ? This hardly seems possible.
Don Kelly
Posted: Mon Sep 03, 2007 9:59 pm
Guest
----------------------------
"sekots" <u37146@uwe> wrote in message news:77b09cbcaaf31@uwe...
Quote:
We are all familiar with the classic presentation of a solenoid with an
iron
core, in which the high permeability core magnifies the strength of the
inducted filed. What about a situation with a permanent magnet? If I
bring a high permeability material into contact with a very strong
permanent
magnet (e.g. neodymium magnet), do I get a similar field strengthening?
My
specific question regards the coupling of a neodymium magnet and a piece
of
"Mu" metal. This is a metal that supposedly has a permeability 25,000
times
that of free space at 0.002 Tesla. Does this mean that I will get a field
of
25,000 Tesla within the Mu metal if I place it in contact with a Neodymium
magnet with a surface field strength of 1 Tesla ? This hardly seems
possible.


You are right- it is not possible. You will get 1 Tesla or a wee bit less.

The permanent magnet has a core with a reasonably high permeability and some
equivalent mmf such that if the external path has infinite permeability
(better than mu metal) , the flux density is limited to, say, 1 Tesla if
that is the point on the B-H curve at 0 external mmf. A permanent magnet
works on the "backside" of the B-H curve where an electromagnet is operated
on the "frontside" but the analysis can be made as if it was an
electromagnet (mmf in series with internal and external reluctance).

There are a number of references on the web and MIT's open course ware does
have some good information. I also have some material in the form of a pdf
which I can send on direct request.
--

Don Kelly dhky@shawcross.ca
remove the X to answer
Szczepan Biaek
Posted: Tue Sep 04, 2007 2:22 am
Guest
"sekots" <u37146@uwe> wrote news:77b09cbcaaf31@uwe...
Quote:
We are all familiar with the classic presentation of a solenoid with an
iron
core, in which the high permeability core magnifies the strength of the
inducted filed. What about a situation with a permanent magnet? If I
bring a high permeability material into contact with a very strong
permanent
magnet (e.g. neodymium magnet), do I get a similar field strengthening?

A selenoid is like magnet. But there is a small difference. Into a selenoid
you can put a core. Into a permanent magnet rather no.
S*
Quote:
My specific question regards the coupling of a neodymium magnet and a
piece of
"Mu" metal. This is a metal that supposedly has a permeability 25,000
times
that of free space at 0.002 Tesla. Does this mean that I will get a field
of
25,000 Tesla within the Mu metal if I place it in contact with a Neodymium
magnet with a surface field strength of 1 Tesla ? This hardly seems
possible.

Conservation of energy must be obeyed.
S*
sekots via NatScience.com
Posted: Tue Sep 04, 2007 9:55 am
Guest
So, what would happen if I placed a core of MU metal within a solenoid ?
Would the field strength be equal to the applied field X the permeability of
the MU metal ?

In such a situation, does the increase in field strength come with heat
production by the core, or does the solenoid current alone contribute to
Joule heating (i.e., I^2*R) ?

I am, obviously, not a professional physicist, and I appreciate very much the
assistance several of you have given me.

Thank you,

John Stokes

Don Kelly wrote:
Quote:
----------------------------
We are all familiar with the classic presentation of a solenoid with an
iron
[quoted text clipped - 13 lines]
magnet with a surface field strength of 1 Tesla ? This hardly seems
possible.

You are right- it is not possible. You will get 1 Tesla or a wee bit less.
The permanent magnet has a core with a reasonably high permeability and some
equivalent mmf such that if the external path has infinite permeability
(better than mu metal) , the flux density is limited to, say, 1 Tesla if
that is the point on the B-H curve at 0 external mmf. A permanent magnet
works on the "backside" of the B-H curve where an electromagnet is operated
on the "frontside" but the analysis can be made as if it was an
electromagnet (mmf in series with internal and external reluctance).

There are a number of references on the web and MIT's open course ware does
have some good information. I also have some material in the form of a pdf
which I can send on direct request.

--
Message posted via NatScience.com
http://www.natscience.com/Uwe/Forums.aspx/electromag/200709/1
sekots via NatScience.com
Posted: Tue Sep 04, 2007 4:09 pm
Guest
So, what would happen if I placed a core of MU metal within a solenoid ?
Would the field strength be equal to the applied field X the permeability of
the MU metal ?

In such a situation, does the increase in field strength come with heat
production by the core, or does the solenoid current alone contribute to
Joule heating (i.e., I^2*R) ?

I am, obviously, not a professional physicist, and I appreciate very much the
assistance several of you have given me.

Thank you,

John Stokes

Szczepan Bia³ek wrote:
Quote:
We are all familiar with the classic presentation of a solenoid with an
iron
[quoted text clipped - 3 lines]
permanent
magnet (e.g. neodymium magnet), do I get a similar field strengthening?

A selenoid is like magnet. But there is a small difference. Into a selenoid
you can put a core. Into a permanent magnet rather no.
S*
My specific question regards the coupling of a neodymium magnet and a
piece of
"Mu" metal. This is a metal that supposedly has a permeability 25,000
times
[quoted text clipped - 3 lines]
magnet with a surface field strength of 1 Tesla ? This hardly seems
possible.

Conservation of energy must be obeyed.
S*

--
Message posted via http://www.natscience.com
Don Kelly
Posted: Tue Sep 04, 2007 10:11 pm
Guest
----------------------------
"sekots via NatScience.com" <u37146@uwe> wrote in message
news:77b7dd17dfcb3@uwe...
Quote:
So, what would happen if I placed a core of MU metal within a solenoid ?
Would the field strength be equal to the applied field X the permeability
of
the MU metal ?

In such a situation, does the increase in field strength come with heat
production by the core, or does the solenoid current alone contribute to
Joule heating (i.e., I^2*R) ?

I am, obviously, not a professional physicist, and I appreciate very much
the
assistance several of you have given me.

Thank you,

John Stokes

Don Kelly wrote:
----------------------------
We are all familiar with the classic presentation of a solenoid with an
iron
[quoted text clipped - 13 lines]
magnet with a surface field strength of 1 Tesla ? This hardly seems
possible.

You are right- it is not possible. You will get 1 Tesla or a wee bit less.
The permanent magnet has a core with a reasonably high permeability and
some
equivalent mmf such that if the external path has infinite permeability
(better than mu metal) , the flux density is limited to, say, 1 Tesla if
that is the point on the B-H curve at 0 external mmf. A permanent magnet
works on the "backside" of the B-H curve where an electromagnet is
operated
on the "frontside" but the analysis can be made as if it was an
electromagnet (mmf in series with internal and external reluctance).

There are a number of references on the web and MIT's open course ware
does
have some good information. I also have some material in the form of a pdf
which I can send on direct request.

--
Message posted via NatScience.com
http://www.natscience.com/Uwe/Forums.aspx/electromag/200709/1

No. The maximum field would be determined by the saturation limit of
mu-metal which is typically only about 0.6T. Note that ordinary transformer
iron will saturate at nearly twice this level so would provide a stronger
magnet for the same dimensions. Even cast iron will do as well as or better
than mu-metal in this regard.
The permeability of the mu-metal would mean that, for any flux density below
saturation, the required exciting ampere-turns would be considerably lower
than that of transformer iron.

The magnetisation curve (mu-metal, transformer steel, etc) rises very
quickly with increased excitation (hence high permeability or slope of this
curve) and then flattens off drastically such that for higher excitation,
the permeability drops to near that of free space. Mu-metal is useful where
this high permeability is important but transformer steel sacrifices in
terms of permeability but has a higher "knee" on its magnetisation curve so
can carry higher flux densities at reasonable currents.

In addition, any solenoid in use doesn't stand alone- one must consider the
whole magnetic path in determing the flux density at any given excitation.
An analogy would be a battery and a lampbulb. The current depends on the
battery voltage and the total circuit resistance-not just that of the
battery.

For DC. the heating is simply Joule heating in the winding. For AC there
will be additional losses due to eddy currents and hysteresis in the metal
core. I don't have comparative data between mu-metal and more conventional
core materials with regard to this but I have vague memories of an attempt
to make a precision current transformer using a mu-metal core (because its
low exciting current reduces one cause of error).

You are looking at permeability

--

Don Kelly dhky@shawcross.ca
remove the X to answer
----------------------------


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