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Author Message
firebird
Posted: Mon Feb 05, 2007 12:45 am
Guest
Suppose a simple first order circuit has the following form:

K*(1+s*Tau_z)
-----------------
(1+s*Tau_p)

Where Tau_z and Tau_p are the zero and pole time constants,
respectively. To find these, I've read somewhere that a shortcut
method is to use the open circuit time constant method (OCTC) and the
short circuit time constant method, if the circuit follows a voltage
divider topology. Basically, to find the zero time constant, you can
open the input and short the output to ground, and find the thevenin
resistance w.r.t the relevant capacitor (Then, Tau_p = C * Rth). To
find the pole time constant, we can short the input to ground and open
the output.

Why do these tests work? I think I understand the idea of time
constants as approximate locations of zeros and poles (the locations
where a capacitor's impedance equals the Rth around it)...but why do
we open the input for the zero and short the input for the pole? Can
anyone shed light on this issue?

Thanks!
 
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