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LiGHT velocity v VARiEs, inversely, WiTH the path PARTiCLE C

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brian a m stuckless
Posted: Sat Nov 12, 2005 9:59 am
Guest
$ NEW SI GUESS iSS CODATA LaGrangian L:
L = h*fL = nL*h*c / wl = nA*{mph}*ls*c^2 / rA = m1*c^2
= E - eM - eV = eK - eV = eM - eF = [(m1*v1^2 / 2)*(m1/M1 + 1)].

You will NEED essentially in theory, a *well-defined* LaGrangian.!!

LiGHT velocity c is NOW a MATHEMATiCAL constant ..just as is, pi.!!
LiGHT velocity v VARiEs, inversely, WiTH the path PARTiCLE COUNT.!!
brian a m stuckless
[quote:66c305817e]
Bilge wrote: > > Harry: > > OK, harry. Here's a simple theory --
What do you imagine? Here's a more complete version, --

L = |D_u\phi)|^2 - a^2|\phi|^2 - |b|^2| ((\phi*)(\phi))^2 + (1/4)F.F

D_u = d_u + ieA_u
[/quote:66c305817e]
insert, HERE ..see top of PAGE.!!

[quote:66c305817e]While I would be happy to explain it to someone who is really
interested in such an answer, neither you nor mr. kennaugh are
such persons. You see, before mr. kennaugh could be interested in
such an answer, he would first have to realize the rest of his post
in which he tries to find some reason to reject relativity, is silly.
Re: A little challenge for relativists.[/quote:66c305817e]
 
 
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