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| Science Forum Index » Mechanics Forum » Link Force and Torque calculations... |
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| Chris W... |
 Posted: Mon Jul 06, 2009 9:09 am |
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Guest
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I'm trying to calculate the force and toque in a linkage system and was
wondering if someone could do a quick check and see if I did anything wrong.
You can find the diagram at the link below
http://hrrdb.com/Links.gif
Here are the constraints.
Points 1, 2, 3, and 4 are pivot points.
Point 1 is fixed in space.
Points 2 and 4 are free to move in the plane.
Point 3 can only move up and down (closer or further from point 1).
The links connecting points 1 & 2, 2 & 3, 3 & 4 and 4 & 1 are all the
same length (L).
A force (F) is applied at point 3.
What I want to know is the torque about point 1 applied by each link as
the angle (a) varies from 5 to 85 degrees.
Step 1 find the force in the links from 2 to 3 and 3 to 4 which should
be the same.
Fl = .5 * F/cos(a)
The .5 is because each of the two links (2 to 3 and 3 to 4) will have
half of the force F.
Step 2 find the perpendicular distance (Torque Arm: TA):from point 1 to
the line through points 2 and 3.
TA = L * cos(x)
x is 90 - (2 * a)
Step 3 multiply Force and arm length
Torque = FL * TA
So the full formula would be
Torque = .5 x F/cos(a) * L * cos(90 - (2 * a))
Thanks for the help.
--
Chris W
KE5GIX
"Protect your digital freedom and privacy, eliminate DRM,
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Ham Radio Repeater Database.
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