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Science Forum Index » Physics - Electromagnetic Forum » Locating a charge via attraction
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Message |
| Vince Morgan |
 Posted: Sat Dec 15, 2007 11:17 pm |
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If I were to locate hoop of charged sheet metal so that it's outer edge was
in close proximity to the inner edge of a circular array of insulated sheet
metal electrodes. And, if those elctrodes were initialy all grounded via
circuits the charge on the hoop (imagining for the sake of the exercise that
there are no other electrostatic influences on the charges induced by other
areas of the machine) should be evenly dispersed around the hoop.
If I were then to unground one of the electrodes and give it a small shot of
charge of opposite sign to the charge on the sheet and then leave that
circuit open, I imagine the charge on that sheet will move toward that
electrode. Whilst moving toward the electrode the charges on the sheet
should induce further unpaired charges on that electrode. The charges on
the hoop (some if not all) will become bound to the electrode. At this
point if I were to unground another electrode, and give it a small shot of
voltage while at the same time earthing the first electrode the charge on
the hoop should become free of the first and migrate to this second
electrode.
I know that the charges on the hoop are self repelling, and I can't yet (I
don't have the skills required) figure out how badly this would affect the
above.
More experienced and knowledgable persons with a better understanding than I
may see a flaw in the above reasoning that I cannot. At this point it is
apparent that there is no power develloped anywhere in the above(without
regard for resistance losses in the circuits).
Would the above arrangement work?
Thank you,
Vince |
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| Dave |
| Posted: Sun Dec 16, 2007 10:38 am |
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"Vince Morgan" <vinharAtHereoptusnet.com.au> wrote in message
news:47649886$0$6070$afc38c87@news.optusnet.com.au...
Quote: If I were to locate hoop of charged sheet metal so that it's outer edge
was
in close proximity to the inner edge of a circular array of insulated
sheet
metal electrodes. And, if those elctrodes were initialy all grounded via
circuits the charge on the hoop (imagining for the sake of the exercise
that
there are no other electrostatic influences on the charges induced by
other
areas of the machine) should be evenly dispersed around the hoop.
If I were then to unground one of the electrodes and give it a small shot
of
charge of opposite sign to the charge on the sheet and then leave that
circuit open, I imagine the charge on that sheet will move toward that
electrode. Whilst moving toward the electrode the charges on the sheet
should induce further unpaired charges on that electrode. The charges on
the hoop (some if not all) will become bound to the electrode. At this
point if I were to unground another electrode, and give it a small shot of
voltage while at the same time earthing the first electrode the charge on
the hoop should become free of the first and migrate to this second
electrode.
I know that the charges on the hoop are self repelling, and I can't yet (I
don't have the skills required) figure out how badly this would affect the
above.
More experienced and knowledgable persons with a better understanding than
I
may see a flaw in the above reasoning that I cannot. At this point it is
apparent that there is no power develloped anywhere in the above(without
regard for resistance losses in the circuits).
Would the above arrangement work?
Thank you,
Vince
if you are making charges move you are doing work which means you are
feeding power into the system.
would the above arrangement work to do what? |
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| Vince Morgan |
| Posted: Sun Dec 16, 2007 8:36 pm |
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Guest
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"Dave" <noone@nowhere.com> wrote in message
news:cLa9j.1108$Vg1.385@trndny04...
Quote: if you are making charges move you are doing work which means you are
feeding power into the system.
would the above arrangement work to do what?
There would be some radiation losses yes. By "power develloped" I meant
output.
Basicaly the arrangement is similar to rotary induction machines like a
Wimhurst/Pidgeon. Rather than move the charges via rotation I am trying to
figure out if it can be done using electrostatic attraction of unlike
charges via the described method.
Regards,
Vince |
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| Vince Morgan |
| Posted: Wed Jan 23, 2008 1:22 am |
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Guest
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"Vince Morgan" <vinharAtHereoptusnet.com.au> wrote in message
news:47649886$0$6070$afc38c87@news.optusnet.com.au...
Quote: If I were to locate hoop of charged sheet metal so that it's outer edge
was
in close proximity to the inner edge of a circular array of insulated
sheet
metal electrodes. And, if those elctrodes were initialy all grounded via
circuits the charge on the hoop (imagining for the sake of the exercise
that
there are no other electrostatic influences on the charges induced by
other
areas of the machine) should be evenly dispersed around the hoop.
If I were then to unground one of the electrodes and give it a small shot
of
charge of opposite sign to the charge on the sheet and then leave that
circuit open, I imagine the charge on that sheet will move toward that
electrode.
Whilst moving toward the electrode the charges on the sheet
should induce further unpaired charges on that electrode. The charges on
the hoop (some if not all) will become bound to the electrode. At this
point if I were to unground another electrode, and give it a small shot of
voltage while at the same time earthing the first electrode the charge on
the hoop should become free of the first and migrate to this second
electrode.
I know that the charges on the hoop are self repelling, and I can't yet (I
don't have the skills required) figure out how badly this would affect the
above.
More experienced and knowledgable persons with a better understanding than
I
may see a flaw in the above reasoning that I cannot. At this point it is
apparent that there is no power develloped anywhere in the above(without
regard for resistance losses in the circuits).
Would the above arrangement work?
No, it wouldn't be useful in anyway. The separation of charge on the
electrodes would mean there would be considerable voltage (relative to the
voltage on the charged hoop) to overcome. All in all it appears to be a
half brained idea, and I now wish someone else had thought of this, other
than myself.
Thank you all for not answering and blowing me off with the disdain it
deserved!
Vince |
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