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| master1729... |
 Posted: Sun Nov 01, 2009 6:26 am |
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Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729 |
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| master1729... |
| Posted: Sun Nov 01, 2009 10:42 am |
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[quote]Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
[/quote]
I said PLZ. |
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| master1729... |
| Posted: Sun Nov 01, 2009 12:01 pm |
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Virgil wrote :
[quote]In article
1699063352.149909.1257108152590.JavaMail.root at (no spam) gallium
.mathforum.org>,
master1729 <tommy1729 at (no spam) gmail.com> wrote:
Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
I said PLZ.
(46^46 - 1) /( (46+1)*(46-1)) factors into
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46^23 +
3 + 1)]
And similarly for the others.
[/quote]
sigh.
im tired of these jokes.
you people know darn well that
1) i was aware of the above trivial factorization
or should i say : " what is intended " since the above is actually wrong :
quote :
(46^46 - 1) /( (46+1)*(46-1)) factors into
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46^23 + 1)]
/
wow a number factors into a smaller number !!??!!
yes smaller because (46^23 + 1) / (46^23 + 1) = 1
so that joke is even wrong and pathetic.
2) im not a beginner at factoring , otherwise i could not have known that (46^46 - 1) /( (46+1)*(46-1)) is actually an integer.
3) thus i wanted - as you darn well know - a full factorization. and a correct one !
4) if you will reply with jokes , mistakes , nonsense and irrelevant stuff , i will too and say here : axiom of choice is wrong.
regards - assuming and hoping you will give a better reply now -
tommy1729
since this reply of virgil was rediculous ( didnt say virgil is ) , i feel the urge to quote an idiot :)
" sd354fq35f13e4f115fsd search the people " musatov. |
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| master1729... |
| Posted: Sun Nov 01, 2009 12:28 pm |
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in the meanwhile i computed that
(46^23 + 1) / 47 = prime.
tommy1729 |
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| Pubkeybreaker... |
| Posted: Sun Nov 01, 2009 12:35 pm |
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On Nov 1, 11:26�am, master1729 <tommy1... at (no spam) gmail.com> wrote:
[quote]Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
[/quote]
(1) Each of the numerators is the difference of two
squares.
Their factorization is trivial.
(2) You can find the full facorizations at Richard
Brent's website. |
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| master1729... |
| Posted: Sun Nov 01, 2009 1:17 pm |
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[quote]Blow me, you impotent puke.
[/quote]
shut up musatov , you retarded son of a german whore who married a bad smelling pokemon.
go ' search the people ' |
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| master1729... |
| Posted: Sun Nov 01, 2009 1:19 pm |
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pubkeybreaker wrote :
[quote]On Nov 1, 11:26�am, master1729 <tommy1... at (no spam) gmail.com
wrote:
Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
(1) Each of the numerators is the difference of two
squares.
Their factorization is trivial.
(2) You can find the full facorizations at Richard
Brent's website.
[/quote]
thanks.
i will look at R Brents website.
i already factored 3 out of 4.
but that last one is tricky , better use his website.
maybe it will lead to a nice conjecture.
regards
tommy1729 |
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| master1729... |
| Posted: Sun Nov 01, 2009 1:48 pm |
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[quote]pubkeybreaker wrote :
On Nov 1, 11:26�am, master1729
tommy1... at (no spam) gmail.com
wrote:
Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
(1) Each of the numerators is the difference of
two
squares.
Their factorization is trivial.
(2) You can find the full facorizations at Richard
Brent's website.
thanks.
i will look at R Brents website.
i already factored 3 out of 4.
but that last one is tricky , better use his
website.
maybe it will lead to a nice conjecture.
regards
tommy1729
[/quote]
i have trouble with .gz files for some reason.
didnt find an online program to factor , did i overlook ? |
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| master1729... |
| Posted: Sun Nov 01, 2009 1:52 pm |
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Guest
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| Virgil... |
| Posted: Sun Nov 01, 2009 3:04 pm |
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Guest
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In article
<1699063352.149909.1257108152590.JavaMail.root at (no spam) gallium.mathforum.org>,
master1729 <tommy1729 at (no spam) gmail.com> wrote:
[quote]Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
I said PLZ.
[/quote]
(46^46 - 1) /( (46+1)*(46-1)) factors into
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46^23 + 1)]
And similarly for the others. |
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| Martin M. Musatov... |
| Posted: Sun Nov 01, 2009 5:36 pm |
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| Blow me, you impotent puke. |
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| Virgil... |
| Posted: Sun Nov 01, 2009 6:22 pm |
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Guest
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In article
<968439331.150126.1257112893522.JavaMail.root at (no spam) gallium.mathforum.org>,
master1729 <tommy1729 at (no spam) gmail.com> wrote:
[quote]Virgil wrote :
In article
1699063352.149909.1257108152590.JavaMail.root at (no spam) gallium
.mathforum.org>,
master1729 <tommy1729 at (no spam) gmail.com> wrote:
Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
I said PLZ.
(46^46 - 1) /( (46+1)*(46-1)) factors into
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46^23 +
3 + 1)]
And similarly for the others.
sigh.
im tired of these jokes.
you people know darn well that
1) i was aware of the above trivial factorization
or should i say : " what is intended " since the above is actually wrong :
quote :
(46^46 - 1) /( (46+1)*(46-1)) factors into
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46^23 + 1)]
My poor proof reading, sorry.[/quote]
Should have been
[(46^46 - 1) / (46-1)] * [(46^23 + 1) / (46+ 1)]
Which is a factorization. though apparently not the COMPLETE
factorization that OP did not actually specify he wanted.
[quote]
wow a number factors into a smaller number !!??!!
yes smaller because (46^23 + 1) / (46^23 + 1) = 1
so that joke is even wrong and pathetic.
2) im not a beginner at factoring , otherwise i could not have known that
(46^46 - 1) /( (46+1)*(46-1)) is actually an integer.
3) thus i wanted - as you darn well know - a full factorization. and a
correct one !
[/quote]
If you want a FULL (or more properly, a complete) factorization, it is
not that much more difficult to say so.
[quote]
4) if you will reply with jokes , mistakes , nonsense and irrelevant stuff ,
i will too and say here : axiom of choice is wrong.
regards - assuming and hoping you will give a better reply now -
tommy1729
since this reply of virgil was rediculous ( didnt say virgil is ) , i feel
the urge to quote an idiot :)
" sd354fq35f13e4f115fsd search the people " musatov.[/quote] |
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| dan73... |
| Posted: Mon Nov 02, 2009 12:25 am |
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Guest
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[quote]Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
[/quote]
More of a challenge --
The 3 + the first 111 decimal digits of pi changed
to an integer.
3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513e+111.
Dan |
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| Martin M. Musatov... |
| Posted: Mon Nov 02, 2009 2:01 am |
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| Blow me a second time, you impotent puke. |
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| Pubkeybreaker... |
| Posted: Mon Nov 02, 2009 3:12 am |
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Guest
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On Nov 2, 5:25 am, dan73 <fasttrac... at (no spam) att.net> wrote:
[quote]Plz factor the following 4 numbers :
(46^46 - 1) /( (46+1)*(46-1))
(58^58 - 1) /( (58+1)*(58-1))
(82^82 - 1) /( (82+1)*(82-1))
(106^106 - 1) /( (106+1)*(106-1))
thank you.
regards
tommy1729
More of a challenge --
The 3 + the first 111 decimal digits of pi changed
to an integer.
3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513e+111.
Dan- Hide quoted text -
- Show quoted text -
[/quote]
Not much of a challenge. A few days computing on a single PC using
GNFS. Even less if one can
pull out a small factor or two with ECM. |
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