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Jan Burse...
Posted: Thu Jun 05, 2008 7:24 pm
Guest
~A, ~A->(B->A) |- ~B
MoeBlee...
Posted: Thu Jun 05, 2008 7:24 pm
Guest
On Jun 5, 5:24 pm, Jan Burse <janbu... at (no spam) fastmail.fm> wrote:
Quote:
   ~A, ~A->(B->A) |- ~B

Yes, intuitionistically valid.

1 ~A
2 ~A -> (B -> A)
3 B -> A ... 1, 2 {1 2}
4 B ... supposition
5 A ... 3, 4 {1 2 4}
6 ~B {1 2}

MoeBlee
Balthasar...
Posted: Fri Aug 01, 2008 3:03 pm
Guest
On Fri, 06 Jun 2008 02:24:30 +0200, Jan Burse <janburse at (no spam) fastmail.fm>
wrote:


Quote:

~A, ~A -> (B -> A) |- ~B

Provable in an intuitionistic calculus and (Johansson's) minimal

calculus by one and the same proof:

1 (1) ~A A
2 (2) ~A -> (B -> A) A
1,2 (3) B -> A 1,2 ->E
4 (4) B A
1,2,4 (5) A 3,4 ->E
1,2,4 (6) A & ~A 1,5 &I
1,2 (7) ~B 4,6 ~I


B.


--

"For every line of Cantor's list it is true that this line does not
contain the diagonal number. Nevertheless the diagonal number may
be in the infinite list." (WM, sci.logic)
 
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