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Posted: Sun May 04, 2008 10:30 am
Guest
Could somebody explain to me why the degree of freedom of graviton is
D(D-3)/2?

Thanks in advance

Youngsub
...
Posted: Mon May 05, 2008 7:28 am
Guest
On 4 Maj, 22:30, yy... at (no spam) fas.harvard.edu wrote:
Quote:
Could somebody explain to me why the degree of freedom of graviton is
D(D-3)/2?



The metric is a symmetric 2-tensor with D(D+1)/2 components.

Diffeomorphisms give D constraints. Since these constraints are
first class, they count twice (constraint + gauge fixing condition).

D(D+1)/2 - 2D = D(D-3)/2.
 
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