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Science Forum Index » Physics - Research Forum » resonance states of the neutron
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| Guest |
Posted: Mon Apr 28, 2008 7:22 am |
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Hi,
The neutron is believed to have some sort of internal structure. I'm
not up on current quark theory. The free neutron decays with a half
life of ~15 min according to:
n -> p + e + 1.29 MeV, (ignore neutrinos)
That's a lot of energy per unit mass. Fortunately the relatively long
decay time provides some kind of "get away from danger grace time".
However, in the event of a relatively high energy inelastic nuclear
collision, internal resonance states of the neutron might be excited
that might enhance the rate of decay. That would make high kinetic
energy neutrons more dangerous than might be expected from the value
of the kinetic energy alone. I'm thinking of processes that might take
place in less than a millisecond.
My questionis to any quark experts out there: Are internal resonance
states of the neutron known that might effectively 'catalyze' more
rapid release of neutron energy? |
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| Uncle Al |
Posted: Mon Apr 28, 2008 3:11 pm |
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Guest
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d.086@hotmail.com wrote:
Quote:
Hi,
The neutron is believed to have some sort of internal structure. I'm
not up on current quark theory. The free neutron decays with a half
life of ~15 min according to:
n -> p + e + 1.29 MeV, (ignore neutrinos)
That's a lot of energy per unit mass. Fortunately the relatively long
decay time provides some kind of "get away from danger grace time".
What does that mean? Look up the mean velocity of a thermal neutron.
Can you run supersonic? Compare rads with rems for beta-rays and fast
neutrons.
Quote: However, in the event of a relatively high energy inelastic nuclear
collision, internal resonance states of the neutron might be excited
that might enhance the rate of decay. That would make high kinetic
energy neutrons more dangerous than might be expected from the value
of the kinetic energy alone. I'm thinking of processes that might take
place in less than a millisecond.
High energy neutrons decay with *longer* externally observed
half-lives - Special Relativity.
Quote: My questionis to any quark experts out there: Are internal resonance
states of the neutron known that might effectively 'catalyze' more
rapid release of neutron energy?
H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2 |
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| Guest |
Posted: Tue Apr 29, 2008 1:06 pm |
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On Apr 28, 6:11 pm, Uncle Al <Uncle...@hate.spam.net> wrote:
Quote: What does that mean?
Metaphorical language.
Quote:
High energy neutrons decay with *longer* externally observed
half-lives - Special Relativity.
My questionis to any quark experts out there: Are internal resonance
states of the neutron known that might effectively 'catalyze' more
rapid release of neutron energy?
H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
We know all that. But you haven't answered the question
Let's use the device of metaphor to illuminate the question better.
Let's say you have a chemical substance that is unstable and decays
with a half life of 15 minutes at a specific temperature. At that
temperature, energy is distributed among internal degrees of freedom
and Boltzman statistics and kinetic factors controls the rate at which
molecules surmount the energy barrier and decay to product(s). When
you raise the temperature, there is a greater amount of energy
distributed amoung the internal degrees of freedom and molecules
surmount the kinetic energy barrier at a faster rate.
Now the neutron is said to have internal structure and weak force
mediated beta decay. I don't know all the details. My question is
whether it is known whether internal degrees of freedom can be excited
within the neutron by inelastic collision and increase the rate of
beta decay. This is unrelated to relativistic effects. Is there a
known quantum mechanical energy level diagram for the neutron? If so
then Boltzman statistics and kinetic theory would allow prediction of
enhanced decay rate. The nucleus is held together by the strong force
and it does have higher energy states. These higher energy states can
be accessed by inelastic collision with neutrons or charged particles,
by neutron absorbtion, by high energy EM excitation all to enhance the
rate of nuclear reactions, typically fission energy release.
Do I make myself clear? The neutron is said to have internal
structure. If so then there ought to be some expectations about its
behavior. BTW this may be controversial but there are plenty of
nuclear rate processes whose rate changes at temperatures near
ambient. There are isotopes whose rate of beta decay or electron
capture decay depend on crystal field (chemical) effects. To put my
question in the most simple terms, is the rate of neutron beta decay
temperature dependent? |
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| Uncle Al |
Posted: Thu May 01, 2008 4:39 pm |
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Guest
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d.086@hotmail.com wrote:
Quote:
On Apr 28, 6:11 pm, Uncle Al <Uncle...@hate.spam.net> wrote:
What does that mean?
Metaphorical language.
High energy neutrons decay with *longer* externally observed
half-lives - Special Relativity.
My questionis to any quark experts out there: Are internal resonance
states of the neutron known that might effectively 'catalyze' more
rapid release of neutron energy?
H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
We know all that. But you haven't answered the question
Let's use the device of metaphor to illuminate the question better.
Let's say you have a chemical substance that is unstable and decays
with a half life of 15 minutes at a specific temperature. At that
temperature, energy is distributed among internal degrees of freedom
and Boltzman statistics and kinetic factors controls the rate at which
molecules surmount the energy barrier and decay to product(s). When
you raise the temperature, there is a greater amount of energy
distributed amoung the internal degrees of freedom and molecules
surmount the kinetic energy barrier at a faster rate.
Now the neutron is said to have internal structure and weak force
mediated beta decay. I don't know all the details. My question is
whether it is known whether internal degrees of freedom can be excited
within the neutron by inelastic collision and increase the rate of
beta decay. This is unrelated to relativistic effects. Is there a
known quantum mechanical energy level diagram for the neutron? If so
then Boltzman statistics and kinetic theory would allow prediction of
enhanced decay rate. The nucleus is held together by the strong force
and it does have higher energy states. These higher energy states can
be accessed by inelastic collision with neutrons or charged particles,
by neutron absorbtion, by high energy EM excitation all to enhance the
rate of nuclear reactions, typically fission energy release.
Do I make myself clear? The neutron is said to have internal
structure. If so then there ought to be some expectations about its
behavior. BTW this may be controversial but there are plenty of
nuclear rate processes whose rate changes at temperatures near
ambient. There are isotopes whose rate of beta decay or electron
capture decay depend on crystal field (chemical) effects. To put my
question in the most simple terms, is the rate of neutron beta decay
temperature dependent?
Given substructure, where is the neutron's electric dipole moment?
Its electric quadrupole moment?
<http://minoserv.maps.susx.ac.uk/~nedm/method1.htm>
|d| < 3.0 10^(-26) e-cm
Why would fractional eV externals affect MeV nuclear chemistry?
(Except for electron capture inverse beta-decay where the kinetics are
not nuclear)
Newton was wrong. Get over it. Quantum mechanics is the proper
model.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2 |
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| Guest |
Posted: Thu May 01, 2008 4:40 pm |
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Quote: H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
H-bomb secondaries undergo disassembly within nanoseconds so any
second order correction for neutron decay rate is insignificant (at
that time scale). |
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| Guest |
Posted: Thu May 01, 2008 4:40 pm |
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On Apr 29, 4:06 pm, d....@hotmail.com wrote:
Quote: To put my
question in the most simple terms, is the rate of neutron beta decay
temperature dependent?
I don't seem to be making any progress in probing the minds of quark
experts so I'll use the metaphorical device again to rephrase the
question.
The neutron is a spin 1/2 particle and so neutron magnetic resonance
spectroscopy exists and at a field strength of 14.7 Tesla the
resonance frequency of the neutron is around 30 MHz, (IIRC). It is
known that at very low temperatures, the neutron undergoes total
reflection from the walls of many materials. So, it is possible to do
long time neutron magnetic resonance studies, except for the
complication that the neutron decays. I have no knowledge of the
magnetic resonance of unstable nuclei (it is too dangerous) so I
cannot use that for constructing another metaphor. But I do have
knowledge of electron spin resonance. In ESR one selects an electron
spin label that is long lived and one generally studies spin labeled
molecules that are long lived. However, if one's molecule or one's
spin label decays in a time of about 15 minutes then one would expect
that decay to be reflected in ESR line shape or in the time dependent
signal decay. If only one decay mechanism pertains then one would see
only monoexponential decay. If more than one decay mechanism pertains
then one would expect to observe biexponential or multiexponential
signal decay. Now the mathematical analysis of noisy multiexponential
decay is almost intractable so such analysis is almost on the
forefront of mathematics, AFAIK.
However, my rephrased metaphorical question is directed at experts in
neutron magnetic resonance. Has any multiexponential signal decay
analysis of free neutron magnetic resonance been derived? If so that
would shed some light on the question of whether neutron beta decay is
temperature dependent and on the existence of resonance states of the
neutron. That should provide some kind of validation for the quark
experts. I'm an experimentalist. So far I have not seen sufficient
experimental validation to justify me putting sufficient effort into
the mastery of quark theory. |
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| J. J. Lodder |
Posted: Thu May 01, 2008 4:40 pm |
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Guest
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<d.086@hotmail.com> wrote:
Quote: Do I make myself clear? The neutron is said to have internal
structure. If so then there ought to be some expectations about its
behavior. BTW this may be controversial but there are plenty of
nuclear rate processes whose rate changes at temperatures near
ambient. There are isotopes whose rate of beta decay or electron
capture decay depend on crystal field (chemical) effects.
That is an electron density effect, not a temperature effect.
(except indirectly)
Quote: To put my
question in the most simple terms, is the rate of neutron beta decay
temperature dependent?
To make dent in the neutron decay rate
you need -huge- electron densities.
Think white dwarf/neutron star,
Jan |
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| Uncle Al |
Posted: Sat May 03, 2008 11:20 am |
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Guest
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d.086@hotmail.com wrote:
Quote:
H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
H-bomb secondaries undergo disassembly within nanoseconds so any
second order correction for neutron decay rate is insignificant (at
that time scale).
Room temp is 0.025 eV; neutron half-life is 613.9 sec at 4 kelvins
(3.45x10^(-4) eV). Assume it is unchanged at room temp. What follows
is therefore *very* conservative.
<http://www.ornl.gov/info/ornlreview/v37_1_04/article_17.shtml>
Kinetics is exponential with temp via the Arrhenius equation
k = Ae^[-E_a/RT]
Boosting the absolute temp by a factor of 98 million (0.025 eV to 2.45
MeV) will decrease the half-life by a factor of e^(98 million) or
10^(42,560,859). Tell Uncle Al how nanoseconds are large compared
with
(613.9 seconds)/10^(42.56 million)
Uncle Al grants you a slop factor of 10^(42 million). Tell Uncle Al
how nanoseconds are large compared with
(613.9 seconds)/10^(560,859)
Still too pessimistic for possibly changing decay mechanisms? Allow a
slop factor of 10^(42.5608 million)
(613.9 seconds)/10^(59)
That is 47 orders of magnitude smaller than nanoseconds. H-bombs and
nuclear reactors (1 MeV fission neutrons must travel to repeatedly
bounce off moderator atoms) would not work by a huge margin if neutron
half-life were inversely temperature dependent. The Original Poster
is a simpleton.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2 |
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| John Park |
Posted: Sat May 03, 2008 11:20 am |
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Guest
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(d.086@hotmail.com) writes:
Quote: On Apr 29, 4:06=A0pm, d....@hotmail.com wrote:
To put my
question in the most simple terms, is the rate of neutron beta decay
temperature dependent?
I don't seem to be making any progress in probing the minds of quark
experts so I'll use the metaphorical device again to rephrase the
question.
The neutron is a spin 1/2 particle and so neutron magnetic resonance
spectroscopy exists and at a field strength of 14.7 Tesla the
resonance frequency of the neutron is around 30 MHz, (IIRC). It is
known that at very low temperatures, the neutron undergoes total
reflection from the walls of many materials. So, it is possible to do
long time neutron magnetic resonance studies, except for the
complication that the neutron decays. I have no knowledge of the
magnetic resonance of unstable nuclei (it is too dangerous) so I
cannot use that for constructing another metaphor. But I do have
knowledge of electron spin resonance. In ESR one selects an electron
spin label that is long lived and one generally studies spin labeled
molecules that are long lived. However, if one's molecule or one's
spin label decays in a time of about 15 minutes then one would expect
that decay to be reflected in ESR line shape or in the time dependent
signal decay. If only one decay mechanism pertains then one would see
only monoexponential decay. If more than one decay mechanism pertains
then one would expect to observe biexponential or multiexponential
signal decay. Now the mathematical analysis of noisy multiexponential
decay is almost intractable so such analysis is almost on the
forefront of mathematics, AFAIK.
I'm not sure how far you're taking the metaphor. To materially alter the ESR
lineshape, any decay process would have to have lifetme of the order of
nanoseconds (or maybe a large fraction of a microsecond). To follow neutron
decay by MR one would need to measure linwidths to sub-millihertz accuracy
or monitor signal intensity for an hour or so.
I haven't done neutron MR but used to work with ESR; my guess is that the
required measurements are difficult
[...]
--John Park |
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| Gerry Quinn... |
Posted: Sun May 04, 2008 10:30 am |
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Guest
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In article <481B397F.4D4CA39B at (no spam) hate.spam.net>, UncleAl0 at (no spam) hate.spam.net
says...
Quote: Kinetics is exponential with temp via the Arrhenius equation
k = Ae^[-E_a/RT]
Boosting the absolute temp by a factor of 98 million (0.025 eV to 2.45
MeV) will decrease the half-life by a factor of e^(98 million) or
10^(42,560,859). Tell Uncle Al how nanoseconds are large compared
with
Does this argument apply also to the decay of, say, Uranium or Radium?
Their nuclei, after all, are certainly capable of entering high energy
vibrational states. If not, perhaps you would care to explain why it
must apply to the decay of the neutron.
Quote: That is 47 orders of magnitude smaller than nanoseconds. H-bombs and
nuclear reactors (1 MeV fission neutrons must travel to repeatedly
bounce off moderator atoms) would not work by a huge margin if neutron
half-life were inversely temperature dependent. The Original Poster
is a simpleton.
The OP never asserted that the decay rate would be inversely dependent
on temperature - he peoposed, rather, that resonant states might be
thermally induced, and would result in an increased decay rate. I agree
that his speculation of a millisecond decay rate is implausible - even
if neutrons have accessible low energy vibrational states, which seems a
bit implausible. But you say nothing here that eliminates the
possibility of some such effect.
- Gerry Quinn |
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| ... |
Posted: Sun May 04, 2008 10:30 am |
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Guest
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On May 3, 2:20 pm, Uncle Al <Uncle... at (no spam) hate.spam.net> wrote:
Quote: d.... at (no spam) hotmail.com wrote:
H-bomb secondaries propagate without any exotic corrections for fast
(2.45 MeV for D+D, 14.1 Mev for D+T) neutron decay.
H-bomb secondaries undergo disassembly within nanoseconds so any
second order correction for neutron decay rate is insignificant (at
that time scale).
Room temp is 0.025 eV; neutron half-life is 613.9 sec at 4 kelvins
(3.45x10^(-4) eV). Assume it is unchanged at room temp. What follows
is therefore *very* conservative.
http://www.ornl.gov/info/ornlreview/v37_1_04/article_17.shtml
Kinetics is exponential with temp via the Arrhenius equation
k = Ae^[-E_a/RT]
You cannot use reductio ad absurdum to prove that the Arrhenius
equation does not apply to neutron decay. At first blush there are two
unknowns, A, the transmission factor and E_a the activation energy. So
you cannot make approximations from the equation in any meaningful
manner, unless you make assumptions about their values. At second
blush, you need to have a more sophisticated appreciation of kinetic
theory to understand the Arrhenius equation. Only over small
temperatures is it correct to approximate the transmission factor A as
a constant. One can derive a functional form for the transmission
factor from assumptions but that is not good science when you try to
apply the Arrhenius equation outside its normal domain of application.
A good scientist would try to find the functional form for the
temperature dependance of the transmission factor by fitting
experimental data to candidate functional forms. After that he might
to try to make conclusions about mechanics.
Another problem is whether the Arrhenius equation is thought to be
derived from classical or quantum statistical assumption and if the
activation energy E_a should be treated as temperature dependendent.
Avtivation energies vary with environmental factors. That is what
catalysis is all about. That is why it is meaningful to ask if a
inelastic collision can catalyze an enhanced rate of neutron decay.
Given all these unknowns, the only conclusion that can be obtained
from the Arrhenius equation is that the rate of decay will be faster
at a high temperature. How much is unknown. I don't think anyone will
disagree with that conclusion.
On the other hand if we had some idea about resonance states of the
neutron we would have some feeling for temperature dependence of
neutron decay and we would have some feeling for enhancement of decay
by inelastic collision. The problem is that the decay mechanism that
we were all taught in grade school is highly simplistic. Hence we end
up asking stupid questions and getting stupid answers in reply. |
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| Uncle Al... |
Posted: Mon May 05, 2008 7:28 am |
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Guest
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Gerry Quinn wrote:
Quote:
In article <481B397F.4D4CA39B at (no spam) hate.spam.net>, UncleAl0 at (no spam) hate.spam.net
says...
Kinetics is exponential with temp via the Arrhenius equation
k = Ae^[-E_a/RT]
Boosting the absolute temp by a factor of 98 million (0.025 eV to 2.45
MeV) will decrease the half-life by a factor of e^(98 million) or
10^(42,560,859). Tell Uncle Al how nanoseconds are large compared
with
Does this argument apply also to the decay of, say, Uranium or Radium?
Their nuclei, after all, are certainly capable of entering high energy
vibrational states. If not, perhaps you would care to explain why it
must apply to the decay of the neutron.
That is 47 orders of magnitude smaller than nanoseconds. H-bombs and
nuclear reactors (1 MeV fission neutrons must travel to repeatedly
bounce off moderator atoms) would not work by a huge margin if neutron
half-life were inversely temperature dependent. The Original Poster
is a simpleton.
The OP never asserted that the decay rate would be inversely dependent
on temperature - he peoposed, rather, that resonant states might be
thermally induced, and would result in an increased decay rate. I agree
that his speculation of a millisecond decay rate is implausible - even
if neutrons have accessible low energy vibrational states, which seems a
bit implausible. But you say nothing here that eliminates the
possibility of some such effect.
- Gerry Quinn
Gee Gerry - Uncle Al awarded you a factor of 10^40 slop in the gears
and it still wasn't enough! Why don't you engage the same enthusiasm
for volunteering a temperature-coupled mechanism for neutron half-life
decay alteration? Goodness, there are none?
No proposed pathway for stellar element synthesis couples isotope
decay half-lives to ambient temp. Temperature-dependent *reaction*
cross-sections are highly temperature dependent - collision energy.
Nuclear decay and especially neutron decay are insensitive to ambient
temperature. A pack of neutrons toodling about at 50 m/s or zipping
about at 10% of lightspeed, relative to the observer, don't change
their internals. H-bomb secondaries pop as predicted, ditto fission
of their depleted uranium casings by fast neutron capture. Reactions
proceed as modeled.
That isn't true for a pack of molecules. There are rotational,
vibrational, and electronic transitions that strongly couple to
temperature by well studied mechanisms. Neutron spherical symmetry
makes such couplings moot. Tell us what the symmetry-allowed
corresponding mechanisms are for neutrons short of particle
accelerator chemistry.
The singular exception is electron capture decay - because it is
mediated by s-electron antinode density at the nucleus. Mere
oxidation state can change decay rate by percentages. A fully ionized
nucleus would be indefinitely stable.
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2 |
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| Ulf Torkelsson... |
Posted: Fri May 30, 2008 4:37 am |
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Guest
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d.086 at (no spam) hotmail.com skrev:
[some text snipped]
Quote: Now the neutron is said to have internal structure and weak force
mediated beta decay. I don't know all the details.
The neutron consists of one up-quark (u) and two down-quarks (d).
Quote: My question is
whether it is known whether internal degrees of freedom can be excited
within the neutron by inelastic collision and increase the rate of
beta decay. This is unrelated to relativistic effects. Is there a
known quantum mechanical energy level diagram for the neutron?
There is a partially known diagram of the energies of the different
states that udd can exist in. Each one of these levels are usually
considered to be their own kind of elementary particle or resonance.
The energy differences between these different levels are typically 100s
of GeV. For instance the neutron, which is a spin 1/2 particle, has a
mass of 940 GeV, and the spin 3/2 udd particle is Delta-0, which has an
energy of 1232 GeV. The lifetime of Delta-0 is 1e-23 s.
[ Mod. note: That would be MeV instead of GeV. -ik ]
Quote: If so
then Boltzman statistics and kinetic theory would allow prediction of
enhanced decay rate.
In theory yes, but the energy gaps between the different particles
are so huge that there will not be any effect at any temperature that
can be achieved in the laboratory.
Ulf Torkelsson |
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| Richard Saam... |
Posted: Mon Jun 02, 2008 5:07 am |
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Guest
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Ulf Torkelsson wrote:
Quote: d.086 at (no spam) hotmail.com skrev:
[some text snipped]
Now the neutron is said to have internal structure and weak force
mediated beta decay. I don't know all the details.
The neutron consists of one up-quark (u) and two down-quarks (d).
My question is
whether it is known whether internal degrees of freedom can be excited
within the neutron by inelastic collision and increase the rate of
beta decay. This is unrelated to relativistic effects. Is there a
known quantum mechanical energy level diagram for the neutron?
There is a partially known diagram of the energies of the different
states that udd can exist in. Each one of these levels are usually
considered to be their own kind of elementary particle or resonance. The
energy differences between these different levels are typically 100s of
GeV. For instance the neutron, which is a spin 1/2 particle, has a mass
of 940 GeV, and the spin 3/2 udd particle is Delta-0, which has an
energy of 1232 GeV. The lifetime of Delta-0 is 1e-23 s.
[ Mod. note: That would be MeV instead of GeV. -ik ]
Back of the envelop calculation:
Assuming that the lifetime of Delta-0 1E-23 sec is a reflection of a
nuclear frequency 1/1E-23 or 1e23 /sec, then
nuclear energy quantum = h * 1E23 ~400 Mev
(close to above neutron mass 940 MeV)
nuclear wave length ~ c/1e23 ~3E-13 cm
(approximately the observed nuclear proton diameter 1.7E-13 cm)
nuclear temperature ~ h * 1E23/boltzmann = 5E12 K
It is remarkable that these extreme energies
reside (and do not normally express themselves) in our 310 K bodies.
Richard Saam
Quote:
If so
then Boltzman statistics and kinetic theory would allow prediction of
enhanced decay rate.
In theory yes, but the energy gaps between the different particles are
so huge that there will not be any effect at any temperature that can be
achieved in the laboratory.
Ulf Torkelsson
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| Tom Roberts... |
Posted: Fri Jun 06, 2008 4:34 am |
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Guest
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Richard Saam wrote:
Quote: nuclear temperature ~ h * 1E23/boltzmann = 5E12 K
It is remarkable that these extreme [temperatures]
reside (and do not normally express themselves) in our 310 K bodies.
It's not really very remarkable, because it's due to the very same
mechanism that makes atoms stable: quantum mechanics. As these systems
(nuclei and atoms) are in their ground state, they cannot radiate. Their
internal structure prevents them from absorbing thermal radiation from
their surroundings (its energy is inadequate to excite their internal
degrees of freedom). So they cannot exchange energy with their
surroundings, and thus cannot come into thermal equilibrium with them.
While there's nothing wrong with discussing the temperature of nuclei,
in most cases people consider them as point particles to which an
internal temperature cannot be assigned. Indeed in many cases this is
done for atoms as well. This is valid when their enforced isolation and
great difference in energy scales applies; it fails when either the
isolation or scale difference doesn't apply (e.g. in flames and He-Ne
lasers for atoms, thermonuclear weapons for nuclei, etc.).
Tom Roberts |
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