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Science Forum Index » Physics - Relativity Forum » Contraction re-interpretation or misrepresentation?
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| Peri of Pera |
Posted: Sat Apr 26, 2008 5:33 pm |
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Guest
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Contraction re-interpretation or misrepresentation?
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899. Einstein by 1905 had also derived the same formulas that Lorentz
and others before Lorentz had published. The original contraction
theory of Lorentz which was accepted by Einstein had the moving object
shrink and be subject to time dilation. The contraction of a moving
object was in proportion to its own speed and time dilation was the
reciprocal of this contraction. Today, these ideas have been
discarded. A two-frame ideology has been put forward. The moving
object is in one ‘frame’, an observer moving with a different speed in
the other ‘frame’. Now, the difference in the speed of the observer
and an observed object is used as the value of v in the Lorentz
contraction formula instead of the speed of the moving object. The
result is a perceived contraction which does not say anything of the
state or condition of either the observed object or the observer. And
time dilation? This is even more useless than ‘perceived’ contraction.
It does not apply to the observed object nor the observer nor anything
else even though it is still used in situations like the twin paradox,
muon life cycles and speeding clocks. Lorentz and Einstein are still
hailed as great scientists but their theories are now misrepresented
as they have been re-interpreted in a fundamental way.
Peter Riedt |
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| Bryan Olson |
Posted: Sun Apr 27, 2008 1:06 pm |
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I wrote:
Quote: Solve the Lorentz transform for t', x',
y', and z', and the resulting inverse Lorentz transform [...]
Of course that should be, "Solve the Lorentz transform for
t, x, y, and z, and the resulting inverse Lorentz transform
[...]" The Lorentz transform is already solved for t', x',
y', and z'.
--
--Bryan |
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| Peri of Pera |
Posted: Mon Apr 28, 2008 3:25 pm |
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On Apr 27, 2:15 pm, Tom Roberts <tjroberts...@sbcglobal.net> wrote:
Quote: Peri of Pera wrote:
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899.
This is just plain wrong. While they used a different vocabulary back
then, the underlying concept of inertial frame was essential. In
particular, it was not necessary to mention what everybody knew -- that
all their equations were valid only in an inertial frame. Today, knowing
the lessons of GR, we need to be more precise.
Tom Roberts
Tom,
I am as precise as is necessary. You cannot spin out of my argument.
The value of v in the Lorentz transform L'=L*sqrt(1-vv/cc) must either
be the speed of a moving body or the speed of an observer moving
relative to the body. That is a fundamental difference that pays paid
to special relativity. You cannot obscure it with generalities.
Peter Riedt |
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| Peri of Pera |
Posted: Mon Apr 28, 2008 3:38 pm |
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On Apr 27, 4:13 pm, Bryan Olson <fakeaddr...@nowhere.org> wrote:
Quote: Peri of Pera wrote:
Contraction re-interpretation or misrepresentation?
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899. Einstein by 1905 had also derived the same formulas that Lorentz
and others before Lorentz had published. The original contraction
theory of Lorentz which was accepted by Einstein had the moving object
shrink and be subject to time dilation. The contraction of a moving
object was in proportion to its own speed and time dilation was the
reciprocal of this contraction. Today, these ideas have been
discarded. A two-frame ideology has been put forward. The moving
object is in one ‘frame’, an observer moving with a different speed in
the other ‘frame’.
No, you've missed it. Both objects are in both frames, at rest
in one, moving in the other.
Now, the difference in the speed of the observer
and an observed object is used as the value of v in the Lorentz
contraction formula instead of the speed of the moving object.
Makes no difference. Solve the Lorentz transform for t', x',
y', and z', and the resulting inverse Lorentz transform
differs from the forward transform in that the sign on terms
where v appears to an odd power is flipped, and in no other
way. Thus the inverse transform is the same as what we get by
substituting -v for v in the Lorentz transform.
If the velocity of the object relative to the observer is v,
then the velocity of the observer relative to the object is
-v, and in fact which direction we define as positive and
which as negative is an arbitrary matter of labeling. Swap
the two transforms everywhere, and we get identical results.
The
result is a perceived contraction which does not say anything of the
state or condition of either the observed object or the observer. And
time dilation? This is even more useless than ‘perceived’ contraction.
It does not apply to the observed object nor the observer nor anything
else even though it is still used in situations like the twin paradox,
muon life cycles and speeding clocks. Lorentz and Einstein are still
hailed as great scientists but their theories are now misrepresented
as they have been re-interpreted in a fundamental way.
Another of Peter Riedt's attempts gets a big red X through it. He
thought he had hit upon some important distinction, but really he
simply did not understand the material well enough to know that
the theory implies the cases he distinguishes to be identical.
--
--Bryan- Hide quoted text -
- Show quoted text -
Bryan,
the calculation of the Lorentz transforms is not the question. The
question is the source of v in the formula L'=L*sqrt(1-vv/cc).
Originally it represented the speed of a moving object and identified
changes to that object. Now it represents the speed of an observer in
a different frame relative to the object and identifies nothing. I am
sure you understand that distinction just as I am sure you do not want
to admit it.
Peter Riedt |
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| Peri of Pera |
Posted: Tue Apr 29, 2008 2:42 pm |
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On Apr 27, 2:15 pm, Tom Roberts <tjroberts...@sbcglobal.net> wrote:
Quote: Peri of Pera wrote:
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899.
This is just plain wrong. While they used a different vocabulary back
then, the underlying concept of inertial frame was essential. In
particular, it was not necessary to mention what everybody knew -- that
all their equations were valid only in an inertial frame. Today, knowing
the lessons of GR, we need to be more precise.
Tom Roberts
Tom,
Your statement that special relativity applies only to inertial
systems is correct. When Einstein was confronted by criticism about
the logic of SR, he pontificated a distinction between inertial
systems and accelerated ones to get out of the difficulty. However, in
the context of my post, this is a side issue. The essential point that
I am making is an objection to the two-frame ideology of contraction
taught as of today. For Einstein, the value of v in the Lorentz
transformation formula L’=L*sqrt(1-vv/cc) was the actual speed of a
moving object (object v) but now is considered the speed of an
observer relative to the moving object (observer v). This changes the
whole meaning of special relativity. In the twin paradox, the age of
the traveling twin is no longer affected by his own speed. His
contraction and time dilation is now measured and perceived by an
observer in another frame according to the speed v of the observer. At
every different speed of the observer, the twin ages at a different
rate. How silly is that? The same goes for muons. They no longer are
subject to time dilation due to their own speed (muon v) but are only
perceived by an observer to slow down according to the observers own
speed (observer v). How silly is that? If this is not silly enough, it
will get sillier still if you argue that while contraction of an
observed object is a notional perception by an observer proportional
to the observer v, time dilation must be the effect of the own speed
of the object (object v).
With my regards,
Peter Riedt |
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| Eric Gisse |
Posted: Tue Apr 29, 2008 2:53 pm |
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On Apr 29, 4:42 pm, Peri of Pera <rie...@yahoo.co.uk> wrote:
[snip]
How long do you intend to do this, Peter? |
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| Tom Roberts |
Posted: Wed Apr 30, 2008 10:31 am |
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Peri of Pera wrote:
Quote: On Apr 27, 2:15 pm, Tom Roberts <tjroberts...@sbcglobal.net> wrote:
Peri of Pera wrote:
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899.
This is just plain wrong. While they used a different vocabulary back
then, the underlying concept of inertial frame was essential. In
particular, it was not necessary to mention what everybody knew -- that
all their equations were valid only in an inertial frame. Today, knowing
the lessons of GR, we need to be more precise.
Your statement that special relativity applies only to inertial
systems is correct.
You need to read more accurately. I never said that -- just look up
there to see what I actually said. Indeed, SR can handle non-inertial
systems just fine. What SR cannot handle is curvature in the manifold --
for that one must apply GR. This of course includes gravitation.
Quote: For Einstein, the value of v in the Lorentz
transformation formula L’=L*sqrt(1-vv/cc)
Again, you need to read more accurately. That is NOT the Lorentz
transformation. And your GUESSES of what Einstein meant are just silly....
What is silly is your attempt to discuss SR without actually
understanding anything about it.
Tom Roberts |
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| Bryan Olson |
Posted: Wed Apr 30, 2008 10:50 pm |
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Peri of Pera wrote:
Quote: On Apr 27, 4:13 pm, Bryan Olson <fakeaddr...@nowhere.org> wrote:
Peri of Pera wrote:
Contraction re-interpretation or misrepresentation?
When Michelson and Morley believed they could detect the ether with
the famous interferometer experiment (MMX), they never thought in
terms of frames. Neither did Lorentz when he tried to explain the
unexpected null result of the experiment by his contraction theory in
1899. Einstein by 1905 had also derived the same formulas that Lorentz
and others before Lorentz had published. The original contraction
theory of Lorentz which was accepted by Einstein had the moving object
shrink and be subject to time dilation. The contraction of a moving
object was in proportion to its own speed and time dilation was the
reciprocal of this contraction. Today, these ideas have been
discarded. A two-frame ideology has been put forward. The moving
object is in one ‘frame’, an observer moving with a different speed in
the other ‘frame’.
No, you've missed it. Both objects are in both frames, at rest
in one, moving in the other.
Now, the difference in the speed of the observer
and an observed object is used as the value of v in the Lorentz
contraction formula instead of the speed of the moving object.
Makes no difference. Solve the Lorentz transform for t', x',
y', and z', and the resulting inverse Lorentz transform
differs from the forward transform in that the sign on terms
where v appears to an odd power is flipped, and in no other
way. Thus the inverse transform is the same as what we get by
substituting -v for v in the Lorentz transform.
If the velocity of the object relative to the observer is v,
then the velocity of the observer relative to the object is
-v, and in fact which direction we define as positive and
which as negative is an arbitrary matter of labeling. Swap
the two transforms everywhere, and we get identical results.
The
result is a perceived contraction which does not say anything of the
state or condition of either the observed object or the observer. And
time dilation? This is even more useless than ‘perceived’ contraction.
It does not apply to the observed object nor the observer nor anything
else even though it is still used in situations like the twin paradox,
muon life cycles and speeding clocks. Lorentz and Einstein are still
hailed as great scientists but their theories are now misrepresented
as they have been re-interpreted in a fundamental way.
Another of Peter Riedt's attempts gets a big red X through it. He
thought he had hit upon some important distinction, but really he
simply did not understand the material well enough to know that
the theory implies the cases he distinguishes to be identical.
the calculation of the Lorentz transforms is not the question.
That's why I did not pretend it was the question.
Quote: The
question is the source of v in the formula L'=L*sqrt(1-vv/cc).
Originally it represented the speed of a moving object and identified
changes to that object.
No, it represented, and still represents, the velocity of a
coordinate system with respect to a reference coordinate system,
where the motion is uniform. The one major change in the theory to
date is the understanding of gravity acting on the frames.
Quote: Now it represents the speed of an observer in
a different frame relative to the object and identifies nothing.
Then, Peter, you misunderstand what matters. The speed of an object
relative to an observer is the same as the speed of the observer
relative to the object (given no significant gravitational effects).
Quote: I am
sure you understand that distinction just as I am sure you do not want
to admit it.
I am not sure -- I'm pretty sure, but not quite really sure -- that
you do *not* understand. I'm really sure that the understanding is
available.
--
--Bryan |
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