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Mehran Basti
Posted: Thu May 01, 2008 9:02 am
Guest
Quote:




This polynomial is linear in the variable t. It is
followed by the
statement "Its Riccati differential equation is
separable one" and the
fairly simple differential equation:

dif(x(t),t) = -(x(t)^2 + m x(t) + r) / (t^2 + (-2 h -
m) t - 2 k + 13
r)

The equation contains two variables m,k in addition
to those found in
the polynomial. Its integration leads to a functional
relation between
x and t that involves logarithms and square roots.

As such, the multivariate polynomial and the
differential equation are
unobjectionable; the problem now is that your
accompanying words have
no recognizable mathematical meaning:

In what sense are your "polynomials based on
Ricatti"? (Is "Ricatti"
here short for "some Ricatti differential equation"
or for "Jacopo
Francesco Riccati"?) How does your differential
equation with a
logarithmic solution "generate" your polynomial?

More genearally speaking, your comments seem to imply
some relation
between the high-order polynomial and the fairly
simple differential
equation. If that is what you mean, what use do you
think can this
relation be put to?

Martin.


Yes, both polynomials have a Riccati differential equation, representing them.

I believe I forgot to place the substitute variables into the Riccati of polynomial of degree 13 (sorry).

I will later on provide its solution.

The polynomial of degree 110 is a Riccati but not separable.

These are class polynomials, i.e. from 5 to any other degree we wish to compute.

The separable one can be simplified by maple under convert to exp, and etc. to a radical solution.

I will soon announce its solution.

Well my writings here are not edited carefully, thus it will have errors in some aspects. I write once and that is it! And post it.

Dr.M.Basti
Guest
Posted: Thu May 01, 2008 9:34 am
Dear Newsgroup:

Please find enclosed a solution of the polynomial of degree 13, as a
separable Riccati.

http://mathforum.org/kb/message.jspa?messageID=6200479&tstart=0

See its Maple input there.

Dr.M.Basti
 
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