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J. J. Lodder
Posted: Wed Apr 16, 2008 4:44 am
Guest
Hans Aberg <haberg_20080406@math.su.se> wrote:

Quote:
J. J. Lodder wrote:
The formally correct version of this equation is
F = k m a
where k is a dimension-less constant depending only on the units chosen
for measuring the physical quantities force, mass and acceleration; by
suitable choice of measurements units, it can be chosen to be equal to 1.

I don't understand this remark.
Are you implying that every physical formula
should be thought of as containing an invisible extra constant,
dimensionless and of value 1?

This is how the formulas will be, if one does not settle for a specific
set of measurement units.

Dimensions and units can in principle
be chosen independently of each other.
The need for dimensioned constants arises
when you insist on using a system of dimensions that is too rich for the
system of equations describing the physics.

A trivial example is the maximal system of dimensions,
in which every physical quantity has its own dimension.
In consequence every formula must contain a dimensioned constant
(possibly of value 1) to balance the dimensions.
This looks like what you were talking about above.

A non-trivial case occurs in practice
when people insist on using the MKSA system of dimensions
with natural units, instead of the natural system of dimensions.
(c=1, but not dimensionless)
Then the c's must be kept in the formulae,
which destroys some of the elegance of the natural units.

In such cases particle masses for example are given in GeV/c^2
The usual comprimise is to use natural units throughout
and to do this only for final results.

Quote:
You can of course think so,
but what good would that do?

In order to be formally correct, but the formulas quickly become
unreadable. As illustration:

In theoretical physics, one may set c = 1, so all lengths can be
measured in seconds. So how about buying 20 ns (nano seconds) of rope?

That's of course just what we would do,
if we could start afresh with our unit systems.
Backward compatibility does have it's claims however.
And in actual fact you are buying rope measured in nanoseconds,
it is just that you (and everybody else)
prefer to use some inconvenient numerical constants as well.

Jan
J. J. Lodder
Posted: Wed Apr 16, 2008 4:44 am
Guest
Phillip Helbig---remove CLOTHES to reply
<helbig@astro.multiCLOTHESvax.de> wrote:

Quote:
In article <1ifbvtl.4kohut1kw41ddN@de-ster.xs4all.nl>,
nospam@de-ster.demon.nl (J. J. Lodder) writes:

Hans Aberg <haberg_20080406@math.su.se> wrote:

The formally correct version of this equation is
F = k m a
where k is a dimension-less constant depending only on the units chosen
for measuring the physical quantities force, mass and acceleration; by
suitable choice of measurements units, it can be chosen to be equal to 1.

I don't understand this remark.
Are you implying that every physical formula
should be thought of as containing an invisible extra constant,
dimensionless and of value 1?

You can of course think so,
but what good would that do?

I see what he is driving at. In this case, the extra constant is
dimensionless and has value 1. However, that is because m (the
intertial mass) is DEFINED as the proportionality constant between F and
a. However, let's assume that it has previously been defined in some
other way, say as the gravitational mass m'. Wonder of wonders, it is
STILL 1 and dimensionless, i.e. m = m'. This is a great mystery in
Newtonian mechanics.

Indeed, when discussing things like the Eotvos experiment
one needs to write m_g and m_i explicitly.
For such a system of equations MKSA dimensions won't do.
It is of course quite possible
to set up a matching system of dimensions,
with M-i and m-G each having a dimension of their own.

However, those working at this level of sophistication
are mature physisists who understand their stuff,
not kiddies having to learn it.

So I don't think anyone has ever bothered
to formally set up such a system of dimensions,
for those to whom it matters can easily do without,
without making too many mistakes.

Quote:
In other cases, say gravitational attraction, we have

F = G m1 m2
-----------
r"

In this case, the constant G is neither dimensionless nor does it have
the value 1. In many cases, units are often used so that G is
dimensionless and of value 1. Such definitions are often made for many
such constants at once, and one sees notes like G = h = c = 1.

In other words, the quantity of interest (F in the examples above) is
proportional to various things we can measure (like r, or m). In
general, to make the proportionality an equality, we need a constant.

See also my reply to Hans Ahlberg for the remark
that the choices of c = 1 and [c] = [I] are independent.
The value and the dimension of c
can be chosen independently of each other.

More generally: units do not 'have' dimensions,
despite the widespread misunderstanding to the contrary.

Best,

Jan
Hans Aberg
Posted: Fri Apr 18, 2008 7:52 am
Guest
J. J. Lodder wrote:

Quote:
A trivial example is the maximal system of dimensions,
in which every physical quantity has its own dimension.

That would be the most general dimension system, in the sens that the
others arise by imposing some equivalence relations.

Quote:
In theoretical physics, one may set c = 1, so all lengths can be
measured in seconds. So how about buying 20 ns (nano seconds) of rope?

That's of course just what we would do,
if we could start afresh with our unit systems.

I think one use say the charge of the electron as basic unit.

Quote:
Backward compatibility does have it's claims however.

That is one reason. Another is the ability to measure the physical
constants. For example, mass, time and length can be measured to a
higher accuracy than the gravitational constant, making it unsuitable as
a conversion constant.

Quote:
And in actual fact you are buying rope measured in nanoseconds,
it is just that you (and everybody else)
prefer to use some inconvenient numerical constants as well.

There is another factor: even though time and length can be treated as
the same in a physical theory, they have in practical experience quite
different characteristics. So giving them different dimensions is in
line with that experience.

Hans Aberg
Hans Aberg
Posted: Fri Apr 18, 2008 7:52 am
Guest
Phillip Helbig---remove CLOTHES to reply wrote:
Quote:
The formally correct version of this equation is
F = k m a
where k is a dimension-less constant depending only on the units chosen
for measuring the physical quantities force, mass and acceleration; by
suitable choice of measurements units, it can be chosen to be equal to 1.
...


Quote:
In this case, the extra constant is
dimensionless and has value 1. However, that is because m (the
intertial mass) is DEFINED as the proportionality constant between F and
a. However, let's assume that it has previously been defined in some
other way, say as the gravitational mass m'. Wonder of wonders, it is
STILL 1 and dimensionless, i.e. m = m'. This is a great mystery in
Newtonian mechanics.

There are several issues involved here. First, assume that mass is
measured in pounds, acceleration using the Paris acceleration in vacuum,
and F using the Paris archive spring - then there is good chance that k
will not be 1, though dimensionless. - Decades ago, it was mentioned to
me somebody trying to write out all these constants, but the formulas
because unreadable.

Second, is k above always dimensionless?...

Quote:
In other cases, say gravitational attraction, we have

F = G m1 m2
-----------


In this case, the constant G is neither dimensionless nor does it have
the value 1. In many cases, units are often used so that G is
dimensionless and of value 1. Such definitions are often made for many
such constants at once, and one sees notes like G = h = c = 1.

The reason that k is dimensionless is probably because the force F was
discovered first via this equation, and defined using it. Suppose that
the gravitational equation would have been discovered first - then G
might have been made into a dimensionless constant. Doing some physical
analysis, setting [F] = F, [mi] = M, [r] = L, [G] = 1,
[F] = [(m1 m2)/r^2] = [m1][m2]/[r]^2 = M^2 L^-2
and setting [a] = A,
[F] = [k m a] = [k][m][a] = [k] M A
So
[k] = M L^-2 A^-1
If the physical dimension of time is T, then A = L T^-2, so
[k] = M T^2 L^-3

It is somewhat unusual, but I do not see a contradiction here.

Then there is the question of the equality of the inertial mass m and
the gravitation mass m' (defined by these two equations). If the
equations have constants in them, the formulation must be that for all
measured masses m, m' one has m = k' m', once physical units of
measurements have been chosen. This part is real physics, describing a
relation of measurements from seemingly different equations in different
physical context (because we have not been able to unify them as coming
from a single model).

Quote:
In other words, the quantity of interest (F in the examples above) is
proportional to various things we can measure (like r, or m). In
general, to make the proportionality an equality, we need a constant.

In order to make measurements of a physical unit, we need another
physical unit as a reference. Then the number gotten from a physical
measurement is relative that reference. And if the physical units are
not selected carefully enough, there will be various constants showing up
sr
Posted: Fri Apr 18, 2008 7:52 am
Guest
pioneer1 wrote:
Quote:
On Apr 8, 2:22=A0pm, John Forkosh <j...@please.see.sig.for.email.com
wrote:

. . . what you call data types
is what physics calls units.

I am not sure because I am trying to understand if force in F=ma is
type string or type number. Only type number has units and dimensions.
The distinction between string and number is called types too, correct?
[...]

OK, here's an attempted answer to the original question from someone
who is a C++ expert, but also knows a reasonable amount about
maths and physics...
-----------------------------------
By "string", I assume you mean "array of char" or "array of byte".
Yes, this is of different "type" than (say) int, float, etc.

Force, mass, acceleration are all distinct types. In C++, one might
represent them like this (sketch only) :

class Force; // Forward declaration.

enum Units { SI, NATURAL, ..... };

class Acceleration
{
float my_val;
Units my_units;
public:
// constructor(s), etc, .....
};

class Mass
{
float my_val;
Units my_units;
public:
// constructor(s), etc, .....

Force operator*(Acceleration const & a const;
{ return Force(....construct from <my_val>
times <a.my_val>, and
correct for respective
units....);
}
};

class Force
{
... similar....
};

Then one can write stuff like
Mass m(....);
Acceleration a(....);
Force f = m * a; // Initialization.

or

if (f == m*a)
{
.....
}
else
{
.....
}

One can of course make all this
far more sophisticated.
--------------------------

The important thing is to maintain a clear distinction
between the abstract mathematical type (e.g., real number,
sequence of octet, Lie algebra generator, Group element,
vector space, dual vector space, etc, ....) and the respective
concrete representations in terms of programming
structures. The abstract algebras/relationships in which
the abstract types may (or may not) participate in can then
be expressed in your program via C++ types and
operator overloading, etc.

Hope that helps.
Kyle
Posted: Fri Apr 18, 2008 7:52 am
Guest
Equations contain only values. To display the equation itself you
would display it as a string: "F=ma". Programmatically these would all
be floating point values.

On Mon, 7 Apr 2008 20:44:06 +0000 (UTC), pioneer1
<1pioneer1@gmail.com> wrote:

Quote:
Hi,

I submitted this question to sci.math.research but it was rejected for
being related to physics or computer science and not math perse.

I have been trying to classify data types in physics

http://www.densytics.com/wiki/index.php?title=Data_types_in_Physics

and I am confused about what is considered string (in the sense of
computer language terminology) and what is considered number or
quantity or magnitude in physics.

More specifically, looking at F in F=ma I see something like a pointer
to an address, not the address itself. Or if ma is number in a
spreadsheet cell, F is the name of that cell.

I know this is not how physicists see it. I am looking to find the
correct mathematical terminology so that I can state the problem
clearly. Do you know a field of physics or math that studies these
things?

Thank you for the help.
J. J. Lodder
Posted: Sat Apr 19, 2008 12:50 pm
Guest
Hans Aberg <haberg_20080406@math.su.se> wrote:

Quote:
Phillip Helbig---remove CLOTHES to reply wrote:
The formally correct version of this equation is
F = k m a
where k is a dimension-less constant depending only on the units chosen
for measuring the physical quantities force, mass and acceleration; by
suitable choice of measurements units, it can be chosen to be equal to 1.
..

In this case, the extra constant is
dimensionless and has value 1. However, that is because m (the
intertial mass) is DEFINED as the proportionality constant between F and
a. However, let's assume that it has previously been defined in some
other way, say as the gravitational mass m'. Wonder of wonders, it is
STILL 1 and dimensionless, i.e. m = m'. This is a great mystery in
Newtonian mechanics.

There are several issues involved here. First, assume that mass is
measured in pounds, acceleration using the Paris acceleration in vacuum,
and F using the Paris archive spring - then there is good chance that k
will not be 1, though dimensionless. - Decades ago, it was mentioned to
me somebody trying to write out all these constants, but the formulas
because unreadable.

Second, is k above always dimensionless?...

Once again: being or not being dimensionless
is NOT a property of a physical quantity,
or of a term in an equation.
It is a choice you can freely make.

In the example above you can for example
choose F to have a dimension of it's own. [F]
Then the constant in F = kma must have the dimension
[k] = [F][M]^{-1}[L]^{-1}[T]^2

Dimensional analysis has nothing to do with reality.
It is a meta-analysis, of systems of equations
that are used to describe reality.
Dimensions can be assigned in any way we please,
subject only to consistency.

Best,

Jan
J. J. Lodder
Posted: Sat Apr 19, 2008 12:50 pm
Guest
Hans Aberg <haberg_20080406@math.su.se> wrote:

Quote:
J. J. Lodder wrote:

A trivial example is the maximal system of dimensions,
in which every physical quantity has its own dimension.

That would be the most general dimension system, in the sens that the
others arise by imposing some equivalence relations.

All dimension systems are equally general.
(all are finite dimensional algebras, mathematically speaking)

It just that some have more dimensions than others.
Some are more trivial than others though.
The maximal system of dimensions
(every physical quantity its own dimension)
is as trivial as the one-dimensional system,
(every physical quantity dimensionless)
for both can't be used for anything useful.

Quote:
In theoretical physics, one may set c = 1, so all lengths can be
measured in seconds. So how about buying 20 ns (nano seconds) of rope?

That's of course just what we would do,
if we could start afresh with our unit systems.

I think one use say the charge of the electron as basic unit.

Planck did that, originally, in Planck units v1.
The disadvantage is having to many 137-s
popping up in less logical places.

Quote:
Backward compatibility does have it's claims however.

That is one reason. Another is the ability to measure the physical
constants. For example, mass, time and length can be measured to a
higher accuracy than the gravitational constant, making it unsuitable as
a conversion constant.

That's no problem, in principle.
The same situation occurred for the Ampere.
The solution adopted was to have both an absolute ampere,
and an international ampere.
The absolute ampere/international ampere
was effectively just another fundamental constant to be measured,
and to be adjusted in the overall best fit.

And to pick a nit: length can't be measured at all, nowadays.
All we can measure is time, with either a ruler or a stopwatch.
The reason is the same: time and speed (of light)
can be measured to greater accuracy than length,
so the obvious solution is to define c,
and not to measure length independently anymore.

Quote:
And in actual fact you are buying rope measured in nanoseconds,
it is just that you (and everybody else)
prefer to use some inconvenient numerical constants as well.

There is another factor: even though time and length can be treated as
the same in a physical theory, they have in practical experience quite
different characteristics. So giving them different dimensions is in
line with that experience.

It is just a choice that can be made freely,
subject only to consistency.
You are for example free to use natural units with c = 1,
both with [c] = [I] and with [c] = [L][T]^{-1}
as you find suitabl for some purpose.

Best,

Jan
Hans Aberg
Posted: Sun Apr 20, 2008 11:47 am
Guest
J. J. Lodder wrote:
Quote:
F = k m a
...
Second, is k above always dimensionless?...

Once again: being or not being dimensionless
is NOT a property of a physical quantity,
or of a term in an equation.

Right, formally, these are different physical theories.

Quote:
It is a choice you can freely make.

Or rather, a choice of physical theory - once it is fixed, the
dimensions are fixed.

Quote:
In the example above you can for example
choose F to have a dimension of it's own. [F]
Then the constant in F = kma must have the dimension
[k] = [F][M]^{-1}[L]^{-1}[T]^2

Yes. I though this was clear from the context.

Quote:
Dimensional analysis has nothing to do with reality.
It is a meta-analysis, of systems of equations
that are used to describe reality.

It is just an analysis of the chosen physical theory, which in its turn
is a modeling of the physical reality, specifically physically
measurable quantities.

Quote:
Dimensions can be assigned in any way we please,
subject only to consistency.

Different physical theories yield different dimension systems, but one
concern is the ability to measure the different quantities. For example,
the gravitational constant cannot be measured as accurately as time, mas
and length, and so cannot be used as a conversion constant.

Hans Aberg
Hans Aberg
Posted: Sun Apr 20, 2008 11:47 am
Guest
J. J. Lodder wrote:
Quote:
A trivial example is the maximal system of dimensions,
in which every physical quantity has its own dimension.
That would be the most general dimension system, in the sens that the
others arise by imposing some equivalence relations.

All dimension systems are equally general.
(all are finite dimensional algebras, mathematically speaking)

If the dimensions are part of a mathematical theory then one looses
information by equation dimensions, but if one has physical information
on how physical units change, then it can be retrieved.

Quote:
It just that some have more dimensions than others.
Some are more trivial than others though.
The maximal system of dimensions
(every physical quantity its own dimension)
is as trivial as the one-dimensional system,
(every physical quantity dimensionless)
for both can't be used for anything useful.

No. They are all equally non-trivial: in theoretical physics, one may
set c = 1, G = 1, /h = 1, and so forth, without loosing physical generality.

Quote:
And to pick a nit: length can't be measured at all, nowadays.
All we can measure is time, with either a ruler or a stopwatch.

This is just a definition of a length unit. It does not affect the
physical measurement methods of length.

Hans Aberg
Paul Danaher
Posted: Mon Apr 21, 2008 10:44 am
Guest
J. J. Lodder wrote:
...
Quote:
And to pick a nit: length can't be measured at all, nowadays.
All we can measure is time, with either a ruler or a stopwatch.
The reason is the same: time and speed (of light)
can be measured to greater accuracy than length,
so the obvious solution is to define c,
and not to measure length independently anymore.

I may have been mislead by sensationalism, but I recall a report a few
weeks ago that the various international kilogram platinum-iridium
masses have been showing an unexplained divergence when compared with
each other.
Two questions: has anybody come up with an explanation, and what's the
state of debate on what to replace the cylinders with?
pioneer1
Posted: Tue Apr 22, 2008 11:39 am
Guest
On Apr 12, 9:30am, Bossavit <bossa...@lgep.supelec.removethis.fr>
wrote:

Thanks for the references. Unfortunately, except for the first one I
couldn't find them online. Do you know if they exist online?

Quote:
H. Whitney: "The mathematics of physical quantities, Part I:
Mathematical models for measurement", Am. Math. Monthly, 75, 2 (1968),
pp. 115-38,
H. Whitney: "The mathematics of physical quantities, Part II, Quantity
structures and dimensional analysis", Am. Math. Monthly, 75, 3 (1968),
pp. 227-56

that the OP might find useful, although Whitney did not invoke "data
types" in the modern sense.

Also relevant,

M. Parkinson: "An Axiomatic Approach to Dimensions in Physics", Am. J.
Phys., 32, 3 (1964), pp. 200-5.

J.F. Price: "Dimensional analysis of models and data sets", Am. J.
Phys., 71, 5 (2003), pp. 437-47.

AB

============================================================================
Alain Bossavit
LGEP, CNRS,91192 Gif sur Yvette CEDEX, Francehttp://natrium.em.tut.fi/~bossavit/
Paul Danaher
Posted: Tue Apr 22, 2008 11:39 am
Guest
Phillip Helbig---remove CLOTHES to reply wrote:
Quote:
In article <rvPOj.58991$097.58918@newsfe21.lga>, Paul Danaher
snip
There are a few different approaches to redefining the basic measurement
references. In the case of the kilogram, it won't be replaced by a
similar reference object, but will be defined by, say, a certain number
of atoms of a certain isotope. Perhaps it will be tied to something
else, say multiply the number of electrons corresponding to a coulomb by
a certain number to get the number of electrons in a kilogram.

There are two tendencies, which sometimes compete: One is to find a
(conceptually) simple measurement. The other is to make sure that if
something else which is defined by a measurement becomes more exact in
the future, that the other quantities don't shift too much.

A while back, there was an article in the Physikalische Blätter (now
called Physik Journal---the member magazine of the German Physical
Society) which reviewed the status of the various proposals.

At http://www.ptb.de/en/wegweiser/einheiten/si/kilogramm.html one can
read:
snip


Thank you! The direct English link to "Ion Akkumulation" seems to be
broken, but the German works fine.
http://www.ptb.de/de/org/1/12/124/_index.htm
has a diagram (without error bars) which seems to show a drift, and
the German text is quite definite in stating that changes in reference
masses have been established.
The English page
http://www.ptb.de/en/org/1/12/124/_index.htm
is much briefer, but there's a useful list of publications
http://www.ptb.de/en/org/1/12/124/_index.htm.

However, these are technical (although interesting) and have no
discussion of the underlying phenomenon (if any). The BIPM has a list
of comparisons at
http://kcdb.bipm.org/AppendixB/KCDB_ApB_result.asp?cmp_idy=432&cmp_cod=APMP.M.M-K1&page=1&search=1&cmp_cod_search=&met_idy=6&bra_idy=2=
0&epo_idy=0&cmt_idy=0&ett_idy_org=0&lab_idy=0
which include a report by the UK National Physical Laboratory in 2000.
This concludes that the "drift" is within the experimental
uncertainties involved in transporting and comparing the reference bodies.

So it seems the "problem" may be the result of experimental inaccuracy.
Paul Danaher
Posted: Tue Apr 22, 2008 5:43 pm
Guest
Jonathan Thornburg [remove -animal to reply] wrote:
<snip>
Quote:
Here are 3 references with more information about this:

There was a pretty good (actually I though _excellent_ for a general
newspaper!) article about this in the Los Angeles Times last week:
http://www.latimes.com/news/nationworld/nation/la-sci-kilogram17apr17,0,7998161,print.story

physorg.com also had a pretty good short piece in 2005:
http://www.physorg.com/printnews.php?newsid=3178

Uh-oh - to quote:
"Electrical power can be related to the Planck constant, defined as
the ratio between the frequency of an electromagnetic particle such as
a photon of light and its energy. This experimental method of defining
the kilogram relies on selecting a fixed value for the Planck
constant, which is currently determined experimentally based on the
fixed value of the kilogram artifact."

The circularity is disturbing.

Quote:
There's also a nice Fermilab colloquium presentations by Richard Steiner
(NIST) on "How Measuring the Planck Constant gets to an Electronic Kilogram
Standard" on 1 Aug 2007: search for Steiner in
http://www-ppd.fnal.gov/EPPOffice-w/colloq/colloq_06_07.html


Avogadro's number looks better here ...
Hans Aberg
Posted: Wed Apr 23, 2008 11:22 am
Guest
Paul Danaher wrote:
Quote:
There was a pretty good (actually I though _excellent_ for a general
newspaper!) article about this in the Los Angeles Times last week:

http://www.latimes.com/news/nationworld/nation/la-sci-kilogram17apr17,0,7998161,print.story

physorg.com also had a pretty good short piece in 2005:
http://www.physorg.com/printnews.php?newsid=3178

Uh-oh - to quote:
"Electrical power can be related to the Planck constant, defined as the
ratio between the frequency of an electromagnetic particle such as a
photon of light and its energy. This experimental method of defining the
kilogram relies on selecting a fixed value for the Planck constant,
which is currently determined experimentally based on the fixed value of
the kilogram artifact."

The circularity is disturbing.

There are no logical circularity problems here:

The current definition of the mass and some other physical units produce
a value of the Planck constant. But the process can be reversed: fixing
the Planck constant and the other constants in order to define the mass
unit.

The problem is, using the current physical units, to get a value of the
Planck constant sufficiently exact that its fixing does not alter the
current mass unit too much. And there must be a measurement method that
can define the new mass unit at least as well as the current mass unit.

It seems me to be an interesting method of defining mass, as the Planck
constant is so fundamental in modern physics. But the main thing, for
now, is to find a measurement method that can fix the mass unit at least
as good as the current one, without reference to an artifact, but by a
generally accessible and invariant reproducible physical phenomenon.

Hans Aberg
 
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