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Science Forum Index » Geology - Meteorology Forum » P/V = NRT disproves theory of grenhouse gases
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| Author |
Message |
| Hatto von Aquitanien |
Posted: Tue Feb 05, 2008 6:48 pm |
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Guest
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Eric Gisse wrote:
Quote: On Feb 5, 12:19 pm, kdth...@yahoo.com wrote:
On Feb 5, 2:46 pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
On Feb 5, 2:40 pm, kdth...@yahoo.com wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
Harry C.
That is cute. So let's see your homework. You are only indoctrinated
with a bunch of information you can repeat. Your education gives you
no ability to review and rationally analyse problems.
So do you want to talk about my education? Just a diversion for
someone who does not understand his psuedo scientific indoctrination
and cannot discuss this very simple topic.
Oh, so when you only take the introductory courses it is enlightening,
but when you take the more advanced courses it is indoctrination?
Or are you seriously claiming you didn't learn things like PV=nkT and
Wein's law in a classroom?
[...]
I sure didn't. I learned PV=NRT in (not P/V=NRT) in a classroom. But the
rest of thermo and stat-mech I learned on my own. I have to laugh at the
knuckle-dragging goons who call themselves physicist, but cannot comprehend
the fact that the WTC was destroyed by controlled demolition.
http://books.google.com/books?id=vIw5m2XuvpIC&printsec=frontcover#PPA485,M1
--
http://www.dailymotion.com/video/x1ek5w_wtc7-the-smoking-gun-of-911-updated
http://911research.wtc7.net
http://vehme.blogspot.com
Virtus Tutissima Cassis |
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| Androcles |
Posted: Tue Feb 05, 2008 7:29 pm |
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Guest
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"Hatto von Aquitanien" <abbot@AugiaDives.hre> wrote in message
news:Kf2dnWAHrcYuejXanZ2dnUVZ_ternZ2d@speakeasy.net...
| Eric Gisse wrote:
|
| > On Feb 5, 12:19 pm, kdth...@yahoo.com wrote:
| >> On Feb 5, 2:46 pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
| >>
| >> > On Feb 5, 2:40 pm, kdth...@yahoo.com wrote:
| >>
| >> > > P/V = NRT is the perfect gas law. It is derived from the fact that
at
| >> > > low pressures, all gases obey this relationship of temperature,
| >> > > pressure and volume. In this formula, N is the number of moles.
| >>
| >> > OK, let's try this again. When you take a course in any of the hard
| >> > sciences, you either work the homework problems, or you ended up
| >> > ignorant.
| >>
| >> > I will bet you never worked any of the homework problems at the end
of
| >> > each chapter. .
| >>
| >> > Harry C.
| >>
| >> That is cute. So let's see your homework. You are only indoctrinated
| >> with a bunch of information you can repeat. Your education gives you
| >> no ability to review and rationally analyse problems.
| >>
| >> So do you want to talk about my education? Just a diversion for
| >> someone who does not understand his psuedo scientific indoctrination
| >> and cannot discuss this very simple topic.
| >
| > Oh, so when you only take the introductory courses it is enlightening,
| > but when you take the more advanced courses it is indoctrination?
| >
| > Or are you seriously claiming you didn't learn things like PV=nkT and
| > Wein's law in a classroom?
| >
| > [...]
|
| I sure didn't. I learned PV=NRT in (not P/V=NRT) in a classroom. But the
| rest of thermo and stat-mech I learned on my own. I have to laugh at the
| knuckle-dragging goons who call themselves physicist, but cannot
comprehend
| the fact that the WTC was destroyed by controlled demolition.
Well yeah, anyone that hurtles a fuel-laden airliner into a building
is controlling the demolition of that building... and themselves,
you knuckle-dragging fuckheaded cunt. |
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| Whata Fool |
Posted: Tue Feb 05, 2008 9:40 pm |
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Guest
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Hatto von Aquitanien <abbot@AugiaDives.hre> wrote:
Quote: I sure didn't. I learned PV=NRT in (not P/V=NRT) in a classroom. But the
rest of thermo and stat-mech I learned on my own. I have to laugh at the
knuckle-dragging goons who call themselves physicist, but cannot comprehend
the fact that the WTC was destroyed by controlled demolition.
That shows you are not only a whacko nut, but don't know
enough about steel skyscrapers to know that once the rivets get
red hot, they shear like taffy. |
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| Bill Ward |
Posted: Tue Feb 05, 2008 9:51 pm |
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Guest
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On Tue, 05 Feb 2008 13:19:02 -0800, kdthrge wrote:
Quote: On Feb 5, 2:46Â pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
On Feb 5, 2:40Â pm, kdth...@yahoo.com wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
Harry C.
That is cute. So let's see your homework. You are only indoctrinated with
a bunch of information you can repeat. Your education gives you no ability
to review and rationally analyse problems.
So do you want to talk about my education? Just a diversion for someone
who does not understand his psuedo scientific indoctrination and cannot
discuss this very simple topic.
What do you want to discuss next, Aristotle. Philosophy, exsitentialism,
moral authority of scientists, the benefits of buying a $100,000 dollar
piece of paper called a diploma, which you can hang on a wall but gives
you no capability to discuss this simple problem which shows your
indoctrination to be incompletely invalid and useless??
The laboratory facts are this:
A gas injected into a container will bring the substance of the container
to it's temperature.
If a metal container is injected with N2 gas, the container will come to
the temperature of the gas. At this time, the outside surface of the
container has a quantity of energy leaving it's surface according to
Boltzman Stefan, 5.67E-5 ergs, cm-2, sec-1, degK-4.
THESE ARE FACTS. THE QUANTITY LEAVING THE SURFACE OF A HEATED BODY IS
DEFINED BY BOLTZMAN STEFAN.
This energy is a quantity and is always in compliance with the law of the
conservation of energy.
IT IS IMPOSSIBLE THAT THIS ENERGY IS TRANSFERED BY MERE COLLISIONS OR
CONDUCTION OF THE MOLECULES. ALTHOUGH THIS IS ABSOLUTELY ESSENTIAL TO THE
THEORY OF GRENHOUSE GASES.
If the temperature of the gas entering the container is increased but it
is allowed to expand, the pressure remains the same.
It's easier for me to think about it as the gas being held at constant
pressure, such as with a weighted frictionless piston at the top of a
cylinder. Then when the gas is heated, the piston rises, doing mechanical
work without changing pressure.
Quote: The collective energy
of the collisions of the molecules is therfore the same. However, energy
leaving the surface of the outside of the container increases as a
fourth power to temperature. From 300K to 1000K, this is a 12,226%
increase in energy.
KD, when the gas and container system radiates energy away, it cools,
unless an equal amount of energy is supplied to the system from outside
the system boundary. |
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| Whata Fool |
Posted: Tue Feb 05, 2008 10:01 pm |
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Guest
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Army1987 <army1987@NOSPAM.it> wrote:
Quote: You don't get it. CO2 is transparent to visible light, but not to
infrared. So the 6000 K black body radiation from the sun can enter the
atmosphere almost unaffected, but significant part of the 300 K radiation
from the Earth is absorbed by the atmosphere. So the equilibrium
temperature is higher than if the atmosphere was completely transparent.
That is a moronic assumption if N2 and O2 do not radiate
much in the infra-red.
Since half of all atmospheric radiation is upward, isn't
it obvious that without GHGs, the N2 and O2 atmosphere would
be much warmer.
Quote: The more CO2 is there, the stronger the effect is. Why else would Venus be
so much hotter than Mercury?
Venus also has much more N2 than Earth, and the latest
images show weather on Venus something like that on Earth,
with very dense clouds that seem to play a big role in the
temperature extremes. |
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| Whata Fool |
Posted: Tue Feb 05, 2008 11:32 pm |
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Guest
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klonq <mathieu@moloney.name> wrote:
Quote: On Feb 6, 1:01 pm, Whata Fool <wh...@fool.ami> wrote:
That is a moronic assumption if N2 and O2 do not radiate
much in the infra-red.
Thats just they thing - N2 and O2 do radiate IR, everything on this
planet, save light bulbs and anything over about 5000K does radiate
IR. The frequency of radiation is dependant on temp
The last I heard the average temperature of the troposphere
was less than 300K.
Quote: Since half of all atmospheric radiation is upward, isn't
it obvious that without GHGs, the N2 and O2 atmosphere would
be much warmer.
Without GHG's they'd be colder.
How, if N2 and O2 don't radiate much IR?
Try to think things through instead of just accepting the
accepted ideas.
Quote: The more CO2 is there, the stronger the effect is.
Didn't you know that water vapor is many times the
GHG that CO2 is, and clouds radiate broadband in IR,
which radiates away all the latent heat carried upward
in evaporated surface water.
Quote: Mercury has no atmosphere - that's why its frozen - no greenhouse - no
oxygen - no ozone - no nothing.
I don't think it is "frozen".
Quote: Venus also has much more N2 than Earth, and the latest
images show weather on Venus something like that on Earth,
with very dense clouds that seem to play a big role in the
temperature extremes.
I think you should check this out - the only similarities between
erath and venus is that the both have atmosphere, both have volcanos,
both have ground to tread but that where it stops. Venus has an
atmosphere made predominately of sulpher dioxide due to large scale
volcanic activity - the atmosphere is covered in cloud and it wasn't
till they sent robots there that they realised it had lightning. But
that doesn't make it like earth.
I read Aviation Week, and it has the latest news about
such things, at least giving a clue what to search for. |
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| Guest |
Posted: Tue Feb 05, 2008 11:48 pm |
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On Feb 5, 7:05 pm, Army1987 <army1...@NOSPAM.it> wrote:
Quote: kdthrge wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
[...]
You don't get it. CO2 is transparent to visible light, but not to
infrared. So the 6000 K black body radiation from the sun can enter the
atmosphere almost unaffected, but significant part of the 300 K radiation
from the Earth is absorbed by the atmosphere. So the equilibrium
temperature is higher than if the atmosphere was completely transparent.
The more CO2 is there, the stronger the effect is. Why else would Venus be
so much hotter than Mercury?
--
Army1987 (Replace "NOSPAM" with "email")
Like this driveling use of terms you cannot define is not foregone?
Let's see the correct distribution for 6000K.
Here is one of the few proper graphs of incoming solar energy and it's
absorption by the atmosphere. Notice the absorption troughs begin at
1um, and by 2um some of the troughs are completely opaque.
http://science.nasa.gov/headlines/images/sunbathing/sunspectrum.htm
Notice that the sun, which is entirely gaseous, obeys Planck's
radiation Law. The vertical scale is logrithmic, which means this
curve which is linear is actually a square to the frequency. The
horizontal scale is directly proportional to frequency in nanometers
which is inversly proportional.
Notice that the sun radiates all through the infrared. Although the
distribution peak is different than for earth, and intensity is
diminshed by the distance to the sun, the sun still radiates more
infrared energy that the earth in frequencies to about 6 or 7 um.
Facts which your fantasy use of words you cannot define must omit from
your so-called 'science'.
Your piss poor use of terms to distinguish solar radiation as not
affected by atmospheric gases, is just the semantics of fools and
superstitious dweebs who wish only to believe in their scaremongering
derived from the charlatans of 19th century classical theory.
Your other assumption, which you make and then which you build your
house of assumption upon, is the 'transparency' of the N2 and O2
atmosphere. THIS IS THE VERY POINT THAT THE DEMONSTRATION OF THE N2
GAS PROVES TO BE INVALID.
The outlined proof is that N2 is not 'transparent' to infrared. If it
can be shown in direct laboratory demonstration that energy is
transfered by N2 gas, and controls are put into place to prove that
the energy being transfered cannot possibly be from direct radiation
absorption and emission from any of the solid surfaces, then it proves
this assumption of 'transparency' of N2 to be invalid.
Although you may very much enjoy your semantics and use of illdefined
phrases, science is the application of means to establish facts.
The fact that can be established, is that N2 gas absorbs and emits all
the frequencies of the infrared, and therefore has it's temperature.
This is proved by the laboratory demonstration of energy transfered to
solid substances by the gas in which it is proved that this energy is
not transfered by direct radiation, or by the molecular motions and
collisions of the molecules.
SEE YOU IN COURT. BRING YOUR LITTLE AGW DICTIONARY ALONG WITH YOUR
AGWKOOK HANDBOOK.
KD |
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| Guest |
Posted: Wed Feb 06, 2008 12:09 am |
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On Feb 5, 7:51 pm, Bill Ward <bw...@REMOVETHISix.netcom.com> wrote:
Quote: On Tue, 05 Feb 2008 13:19:02 -0800, kdthrge wrote:
On Feb 5, 2:46 pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
On Feb 5, 2:40 pm, kdth...@yahoo.com wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
Harry C.
That is cute. So let's see your homework. You are only indoctrinated with
a bunch of information you can repeat. Your education gives you no ability
to review and rationally analyse problems.
So do you want to talk about my education? Just a diversion for someone
who does not understand his psuedo scientific indoctrination and cannot
discuss this very simple topic.
What do you want to discuss next, Aristotle. Philosophy, exsitentialism,
moral authority of scientists, the benefits of buying a $100,000 dollar
piece of paper called a diploma, which you can hang on a wall but gives
you no capability to discuss this simple problem which shows your
indoctrination to be incompletely invalid and useless??
The laboratory facts are this:
A gas injected into a container will bring the substance of the container
to it's temperature.
If a metal container is injected with N2 gas, the container will come to
the temperature of the gas. At this time, the outside surface of the
container has a quantity of energy leaving it's surface according to
Boltzman Stefan, 5.67E-5 ergs, cm-2, sec-1, degK-4.
THESE ARE FACTS. THE QUANTITY LEAVING THE SURFACE OF A HEATED BODY IS
DEFINED BY BOLTZMAN STEFAN.
This energy is a quantity and is always in compliance with the law of the
conservation of energy.
IT IS IMPOSSIBLE THAT THIS ENERGY IS TRANSFERED BY MERE COLLISIONS OR
CONDUCTION OF THE MOLECULES. ALTHOUGH THIS IS ABSOLUTELY ESSENTIAL TO THE
THEORY OF GRENHOUSE GASES.
If the temperature of the gas entering the container is increased but it
is allowed to expand, the pressure remains the same.
It's easier for me to think about it as the gas being held at constant
pressure, such as with a weighted frictionless piston at the top of a
cylinder. Then when the gas is heated, the piston rises, doing mechanical
work without changing pressure.
The collective energy
of the collisions of the molecules is therfore the same. However, energy
leaving the surface of the outside of the container increases as a
fourth power to temperature. From 300K to 1000K, this is a 12,226%
increase in energy.
'> KD, when the gas and container system radiates energy away, it
cools,
'> unless an equal amount of energy is supplied to the system from
outside
'> the system boundary.
That is exactly the point. If N2 gas is heated, and then by slight
pressure moved through the metal container which has an outlet hose,
it brings the container to temperature. At lower temperatures, the
ambient temperature is near to the metal temperature and energy
leaving the surface is not so easy to distinguish.
But if one increases the temperature to near 1000K, or conducts the
entire demonstration in controlled ambient temperature, it can be
clearly demonstrated that if the metal maintains this temperature, the
quantity of energy defined by Boltzman Stefan is constanly leaving
this surface. This energy travels at c, and is no longer in the system
of the metal container and the gas within. This energy is quantified
in Joules or calories or ergs.
This energy must come from someplace in order for it to be constantly
leaving the surface of the metal container.
The N2 gas is heated and delivered to the interior of the container
through tubing or pipes. If at first the gas is not pushed through the
system, the container does not reach temperature. This proves the
energy is not transfering simply through the gas by collsions or
transfer by conduction.
As the gas is pushed lightly through the container, one can find the
minimum rate the gas must be pushed through in order to bring the
metal container to temperature. AT this point, the tubing bringing the
gas, and the container will all reach near the same temperature.
The infrared energy is absorbed and emited by the N2 molecules at the
velocity of light. Therefore, the gas in this small volume would lose
it's energy quickly. Within the tubing bringing the gas, this energy
is absorbed by the walls and delivered back into the gas. But if the
gas did not absorb and contain this radiation as it were being
delivered into the container, the energy has no means to arrive inside
the container, where it is absorbed by the interior of the container,
transfered to the exterior by conduction, where it is radiated away
and out of the system.
The point where the tubing enters the container does not have
sufficient surface area to be responsible for the energy being
absorbed by the interior surface area of the container. Radiation from
surface to surface is not therefore the means that energy is
transfered.
The only means that the energy is transfered from the heat source to
the interiour of the container, and then transfered to the
environment, is by the absorption and emission of the infrared
radiation energy of the continous spectrum of the infrared by the N2
gas. This total energy per second, must be of sufficient quantity and
is therefore near to the same distribution as the energy leaving the
surface of the metal container, or 5.67E-5 ergs, cm-2, sec-1, degK-4.
All proper considerations of the Law of the Conservation of Energy is
in place.
Vibrating molecules or particles, cannot deliver energy into emissions
without absorbing this energy, and then losing this energy into the
emission. This concept seems to be difficult for those trained without
proper understanding of the law of conservation of energy.
KD |
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| Hatto von Aquitanien |
Posted: Wed Feb 06, 2008 12:09 am |
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Guest
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Eric Gisse wrote:
Quote: On Feb 5, 1:48 pm, Hatto von Aquitanien <ab...@AugiaDives.hre> wrote:
Eric Gisse wrote:
On Feb 5, 12:19 pm, kdth...@yahoo.com wrote:
On Feb 5, 2:46 pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
On Feb 5, 2:40 pm, kdth...@yahoo.com wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that
at low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end
of each chapter. .
Harry C.
That is cute. So let's see your homework. You are only indoctrinated
with a bunch of information you can repeat. Your education gives you
no ability to review and rationally analyse problems.
So do you want to talk about my education? Just a diversion for
someone who does not understand his psuedo scientific indoctrination
and cannot discuss this very simple topic.
Oh, so when you only take the introductory courses it is enlightening,
but when you take the more advanced courses it is indoctrination?
Or are you seriously claiming you didn't learn things like PV=nkT and
Wein's law in a classroom?
[...]
I sure didn't. I learned PV=NRT in (not P/V=NRT) in a classroom. But
the
rest of thermo and stat-mech I learned on my own. I have to laugh at the
knuckle-dragging goons who call themselves physicist, but cannot
comprehend the fact that the WTC was destroyed by controlled demolition.
"fact"
A curious word to use for the repeatedly disproven and now comical
assertion that the WTC was destroyed by "controlled demolition."
This is the proof:
http://en.wikipedia.org/wiki/Liouville's_theorem_(Hamiltonian)
http://vehme.blogspot.com/2007/12/glaring-proof-of-something-hotter-than.html
--
http://www.dailymotion.com/video/x1ek5w_wtc7-the-smoking-gun-of-911-updated
http://911research.wtc7.net
http://vehme.blogspot.com
Virtus Tutissima Cassis |
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| Talk-n-Dog |
Posted: Wed Feb 06, 2008 12:21 am |
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Guest
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Whata Fool wrote:
Quote: Hatto von Aquitanien <abbot@AugiaDives.hre> wrote:
I sure didn't. I learned PV=NRT in (not P/V=NRT) in a classroom. But the
rest of thermo and stat-mech I learned on my own. I have to laugh at the
knuckle-dragging goons who call themselves physicist, but cannot comprehend
the fact that the WTC was destroyed by controlled demolition.
That shows you are not only a whacko nut, but don't know
enough about steel skyscrapers to know that once the rivets get
red hot, they shear like taffy.
I saw a new story of a local parking garage(concrete) that collapsed
kinda like the WTC... the weight from the floor above hitting the one
below worked like dominoes and it all went straight down like WTC.
They weld and bolt more than riveting these days. Riveting went out a
number of years ago.
Toss a piece of steel rebar in a fire, after a while you can bend it
like a pretzel. I had an OutDoor wood burning Boiler I built and the
logs would bend the rebar I made the wood log rack out of... I had to
use some scrap stainless bar to take the heat. It was that or Cast iron
which holds it's shape when hot. |
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| Guest |
Posted: Wed Feb 06, 2008 1:49 am |
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On Feb 5, 7:51 pm, Bill Ward <bw...@REMOVETHISix.netcom.com> wrote:
Quote: On Tue, 05 Feb 2008 13:19:02 -0800, kdthrge wrote:
On Feb 5, 2:46 pm, "hhc...@yahoo.com" <hhc...@yahoo.com> wrote:
On Feb 5, 2:40 pm, kdth...@yahoo.com wrote:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
Harry C.
That is cute. So let's see your homework. You are only indoctrinated with
a bunch of information you can repeat. Your education gives you no ability
to review and rationally analyse problems.
So do you want to talk about my education? Just a diversion for someone
who does not understand his psuedo scientific indoctrination and cannot
discuss this very simple topic.
What do you want to discuss next, Aristotle. Philosophy, exsitentialism,
moral authority of scientists, the benefits of buying a $100,000 dollar
piece of paper called a diploma, which you can hang on a wall but gives
you no capability to discuss this simple problem which shows your
indoctrination to be incompletely invalid and useless??
The laboratory facts are this:
A gas injected into a container will bring the substance of the container
to it's temperature.
If a metal container is injected with N2 gas, the container will come to
the temperature of the gas. At this time, the outside surface of the
container has a quantity of energy leaving it's surface according to
Boltzman Stefan, 5.67E-5 ergs, cm-2, sec-1, degK-4.
THESE ARE FACTS. THE QUANTITY LEAVING THE SURFACE OF A HEATED BODY IS
DEFINED BY BOLTZMAN STEFAN.
This energy is a quantity and is always in compliance with the law of the
conservation of energy.
IT IS IMPOSSIBLE THAT THIS ENERGY IS TRANSFERED BY MERE COLLISIONS OR
CONDUCTION OF THE MOLECULES. ALTHOUGH THIS IS ABSOLUTELY ESSENTIAL TO THE
THEORY OF GRENHOUSE GASES.
If the temperature of the gas entering the container is increased but it
is allowed to expand, the pressure remains the same.
It's easier for me to think about it as the gas being held at constant
pressure, such as with a weighted frictionless piston at the top of a
cylinder. Then when the gas is heated, the piston rises, doing mechanical
work without changing pressure.
The collective energy
of the collisions of the molecules is therfore the same. However, energy
leaving the surface of the outside of the container increases as a
fourth power to temperature. From 300K to 1000K, this is a 12,226%
increase in energy.
'> KD, when the gas and container system radiates energy away, it
cools,
'> unless an equal amount of energy is supplied to the system from
outside
'> the system boundary.
This statement really makes no sense, Bill.
The gas and container radiate energy continually. If the input or
recieved radiation is greater than that which is radiated away, the
temperature is increasing as the overall quantity of energy within the
system is increasing, and thus the density of the energy within the
system is increasing.
An object "cools", when the influx of energy becomes less than the
outgoing energy. At this point it does not take very long for the
radiation field to diminish since radiation travels at the velocity of
light. When the density of energy of the radiation field in the system
diminishes, the kinetic energy of the motions of the molecules,
(linear, rotational and vibrational), is no longer sustained. The
energy stored as kinetic energy in these motions begins to be
converted and lost as radiation energy. This is the quantity of energy
which is heat capacity.
Your contemporary schooling is very inadequate. Within theoretical
science, the push to blend QM with the scaremongering of AGW is
virtually complete. But with this goes any adequate theory of
thermodynamics or energy, and the grossly invalid precepts of
classical theory are readopted. You personally refered some Tyndell,
and showed your inability to distinguish his described 'parlor
tricks', from actual scientific determination.
The best way to understand, 'heat', 'energy', and 'temperature', is
with the theoretical blackbody oven.
This oven loses no heat through it's walls and has an aperture that
can be opened and closed and varied. It is heated by some means in
which input energy can be perfectly monitored. Within the oven, energy
is absorbed and reflected until it is uniform, Energy entering through
the open aperture, is absorbed and reflected within the oven so that
it does not affect the distribution in the outgoing radiation leaving
the aperture which is studied.
If at first heat energy is inducted into the oven and the aperture is
open, after a time a stable temperature will be reached, whatever that
is. At this point where temperature is not changing in the theoretical
oven, energy leaving the aperture is equal to energy being inducted
into the oven.
At this point, temperature can be increased in two ways. By increasing
input energy. This would increase the quantity of energy in the system
and thus increase the density of the radiation field. This greater
density would increase the amount of energy leaving through the
aperature although it is still the same size until again equilibrium
between input energy and output energy is achieved and temperature
stabalizes. Therefore the density of the energy leaving through the
aperture increases.
The aperture could also be closed partially. At this point, energy
leaving the system is no longer equal to energy input into the system.
Energy in the system increases which causes the density of the energy
in the system to increase. The density of the energy leaving through
the aperture increases. AT the point that the density of the energy
leaving through the aperture increases to the point that the same
amount of energy leaves through the smaller area, the temperature will
again stabalize and stop changing. The input energy is not changed. At
stable temperature, outgoing energy is equivelent to input energy.
Same energy is exiting through smaller area, because the density of
the energy is greater.
This energy is defined by Boltzman for quantity of energy passing
through the plane of 1 sq cm, per second at the velocity of light.
This denisity of the energy diminishes as an inverse square to
distance. Whatever the particular distribution of energy at each
frequency, Botzman defines this density in relation to Stefans Law
which states that total energy, (or energy density), increases as a
fourth power to temperature.
KD |
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| Guest |
Posted: Wed Feb 06, 2008 8:08 am |
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On Feb 6, 7:44 am, Kurt Lochner <kurt_loch...@DONOTSPAMhotmail.com>
wrote:
So you cannot discuss the means that the energy is transfered through
the N2 gas. This is much more proof of ineptitude than a simple
structure of an equation.
All of this is words. The important thing is the direct laboratory
documentation of the transfer of energy from the heat source to the
exterior of the metal container by the N2 gas, and the presentation in
a courtroom which is dedicated to the establishment of actual facts to
the rhetoric and dogma of the BELIEVERS and Kooks of AGW and climate
catastrophe.
This is a simple misplacement of characters of an equation. Pressure
and volume are inversly proportional.
So now you have the means to ignore the fact that it can be directly
proved in a courtroom that N2 gas is not transparent to infrared
radiation. N2 gas absorbs and emits in the continous spectrum of the
infrared. This can be absolutely proved by direct science.
The contentions of AGW and grenhouse theory cannot be directly proved
by any direct science.
This entirely negates the most basic premise of AGW. This entirely
proves that the assumption that minute quantities of specific gases do
not have the effect upon temperature or climate that is claimed.
This has nothing to do with myself, unless of course it is myself that
is making the case in any particular courtroom. So enjoy your mental
masturbation in the meantime.
It is not my profession to rend theoretical science. The scientists
wishing to promote these postulates upon society do make it their
profession. To prove absolutely their invalidity,as it is possible to
do upon this one specific tenet of their theoretical conjecture,
therefore also PROVES a very serious crime of fraud, and the fact that
although this is their profession, they are entirely invalid and
devoid of any actual science.
But since you and your comrades are dishonest and have no interest in
the truth, these facts will blow right over your head as you pursue
your insane obsession with affecting other people's lives according to
your provably false theoretical surmise.
HAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHAHA
HAHAHAHAHAHAHhahahahahHAHAHAHAHAHAHAhahahah
hahahahhahahahahahah
KD
The ship of fools of the BELIEVERS in anthropogenic global warming
sails on,
Next stop, the marina on No Paddle Island, up Shit Creek |
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| David |
Posted: Wed Feb 06, 2008 9:38 am |
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Guest
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Hatto von Aquitanien wrote:
....the WTC was destroyed by controlled demolition.
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| Kurt Lochner |
Posted: Wed Feb 06, 2008 9:44 am |
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Guest
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kdthrge@Dial1.StLouis1.Level3.net babbled almost incoherently with:
Quote:
"bile wad" <bward@socal.res.rr.com> sniveled something else:
kdthrge@Dial1.StLouis1.Level3.net was smoking something toxic:
Harry C. wrote back correcting:
kdthrge@Dial1.StLouis1.Level3.net screwed the pooge yet again:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
That is cute. So let's see your homework. You are only indoctrinated with
a bunch of information you can repeat. Your education gives you no ability
to review and rationally analyse problems.
*>LOL!<* You shouldn't be casting stones right now, death-rage..
By the way, it's "pV = nRT"
http://www.oup.com/uk/orc/bin/0199271836/atkins_echem_ch01.pdf
Quote: So do you want to talk about my education?
Nope, it's obvious that you don't have one..
--But, keep telling on yourself. I find it amusing.. |
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Posted: Wed Feb 06, 2008 9:58 am |
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On Feb 6, 7:44 am, Kurt Lochner <kurt_loch...@DONOTSPAMhotmail.com>
wrote:
Quote: kdth...@Dial1.StLouis1.Level3.net babbled almost incoherently with:
"bile wad" <bw...@socal.res.rr.com> sniveled something else:
kdth...@Dial1.StLouis1.Level3.net was smoking something toxic:
Harry C. wrote back correcting:
kdth...@Dial1.StLouis1.Level3.net screwed the pooge yet again:
P/V = NRT is the perfect gas law. It is derived from the fact that at
low pressures, all gases obey this relationship of temperature,
pressure and volume. In this formula, N is the number of moles.
OK, let's try this again. When you take a course in any of the hard
sciences, you either work the homework problems, or you ended up
ignorant.
I will bet you never worked any of the homework problems at the end of
each chapter. .
That is cute. So let's see your homework. You are only indoctrinated with
a bunch of information you can repeat. Your education gives you no ability
to review and rationally analyse problems.
*>LOL!<* You shouldn't be casting stones right now, death-rage..
By the way, it's "pV = nRT"
http://www.oup.com/uk/orc/bin/0199271836/atkins_echem_ch01.pdf
So do you want to talk about my education?
Nope, it's obvious that you don't have one..
--But, keep telling on yourself. I find it amusing..- Hide quoted text -
- Show quoted text -
Any way you may write the perfect gas law, it is based upon simple
mechanics which are determined by experiment. Just to clearly describe
these;
If a sample of gas is kept at constant volume and the temperature is
increased, it's pressure increases as a direct proportion to
temperature.
If the volume of a gas is increased, the pressure and temperature
decrease directly proportional. If the gas remains in the same ambient
temperature, it regains the initial temperature but at a lower
pressure which is of the inverse proportion to the greater volume.
If the temperature of a gas is increased and it is allowed to expand,
it retains the same pressure as the volume increases directly
proportional to temperature.
If the gas is compressed, the pressure increases and the temperature
increase as a direct proportion. If it remains in the same ambient
temperature, the temperature returns to the intitial temperature, but
the gas remains at the higher pressure in the lower volume.
Dalton's basic principles show that these basic facts in these basic
proportions holds for all gases. At low pressures, gases cannot be
differentiated by these relative values of pressure, temperature and
volume.
1 liter of hydrogen gas, mixed with 1 liter of CO2, at the same
temperature and pressure, result in exactly 2 liters of gas at the
same temperature and pressure. This means that there is no difference
between the gases in their occupation of the volume, which is
determined by the number of molecules. Therefore partial pressure is
according to the pressure of this percentage of the gas in the total
volume area.
A mole is a specific number of molecules and is the fundamental means
that any chemical or thermodynamic processes can be evaluated.
KD |
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