"Szczepan Bialek" <sz.bialek@wp.pl> wrote in message
news:fa9uie$knm$1@node1.news.atman.pl...

"FrediFizzx"

No, before the trip an experiment must be devised and performed that
shows that there is no displacement current.

It would be no problem with devising. But who perform such?
S*
Take a look at "Conduction current and the magnetic field in a circular
capcitor" D. F. Bartlett, Am. J. Physics 58, 1168-1172 (1990) for a
discussion of the futile attempts to observe the magnetic fields
supposedly "caused" by Displacement Current.

There are many others.

"maxwell" <s...@shaw.ca> wrote in message

news:1187632190.804009.205220@i38g2000prf.googlegroups.com...



On Aug 19, 11:04 am, "Szczepan Bialek" <sz.bia...@wp.pl> wrote:
"maxwell"

Coulomb's Law is a
quasi-static 'law' that has never been demonstrated for electrons
because the damn things won't stay still

Electrons are not marked. You can make a thought (and real)
experiments with
the gradient of electrons. No matter which one is in given place.

- it was just Coulomb's

theoretical effort to produce an analogue of Newton's gravitational
law.

What was the result?
S*
The realist view (in contrast to the Positivists) is that the world
carries on very nicely whether we humans try to observe or measure
it. Since we can't theoretically solve the two-electron problem
'classically' (i.e. just using Maxwell's theory), never mind with QED,
then how can you say we can confirm Coulomb's 'Law' with even 2
electrons? (see my reply to Fred above). If you have to ask your last
question then you didn't finish high school physics.

I can't seem to find your reply to me. ??? Electrons are QED objects;
Coulomb's law does not work for them exactly. Coulomb's law only works
in an ideal static case (nothing is entirely static) and I believe only
for extended charge density.

Best,

Fred Diether
Moderator sci.physics.foundations