'The accordance between revealed 4He and produced energy
seems to be a clear signature of a nuclear process
occurring in condensed matter.'

On 11 Mar, 20:19, "scerir" <sce...@libero.it> wrote:
'The accordance between revealed 4He and produced energy
seems to be a clear signature of a nuclear process
occurring in condensed matter.'

The bottom line is how can we get a temperature high enough - at least
10^7K to cause fusion.The paper at

http://lenr-canr.org/acrobat/DeNinnoAexperiment.pdf

suggests that the temperature can be lower because a plasma of d
electrons from palladium lowers the coulomb barrier ( presumably the
plasma is caused by the
high temperature generated in a small volume by the saturation of
palladium with deuterium atoms ).An electric current passes through
the palladium.Now this could raise the temperature a bit more by
frictional heating,but if there are cavities in palladium

http://lenr-canr.org/acrobat/DeNinnoAexperiment.pdf

perhaps hydrogen is turned into an ultraviolet laser

( but where would the relativistic electrons this document mentions
come from in the experimental setup we are dealing with).

of their candidacy examinations. I recall one question that makes
me
shudder to this day. It simply asked to calculate the height of the
ocean
tides. There wasn't a single candidate who took that exam who had
any idea
how to do this on the back of an envelope.

G = gravitational constant
Me = earth mass 5.97E+27 g
Mn = moon mass 7.35E+25 g
Re = earth radius 6.371315E+08 cm
Rem = distance between moon and earth 3.844E+10 cm
T = tide height
Wm = water test mass

Gravity works on a water test mass
with force from earth and moon:

G*Me*Wm/Re^2 = G*Me*Wm/(Re+T)^2 + G*Wm*Mm/(Rem)^2

On Mar 6, 8:55 pm, Richard Saam <rds...@att.net> wrote:

of their candidacy examinations. I recall one question that makes

me

shudder to this day. It simply asked to calculate the height of the

ocean

tides. There wasn't a single candidate who took that exam who had

any idea

how to do this on the back of an envelope.

G = gravitational constant
Me = earth mass 5.97E+27 g
Mn = moon mass 7.35E+25 g
Re = earth radius 6.371315E+08 cm
Rem = distance between moon and earth 3.844E+10 cm
T = tide height
Wm = water test mass

Gravity works on a water test mass
with force from earth and moon:

G*Me*Wm/Re^2 = G*Me*Wm/(Re+T)^2 + G*Wm*Mm/(Rem)^2


Why not 0 = the two weihts? What has the Me--Wm attraction to do with
them?

On Mar 6, 8:55 pm, Richard Saam <rds...@att.net> wrote:

of their candidacy examinations. I recall one question that makes

me

shudder to this day. It simply asked to calculate the height of the

ocean

tides. There wasn't a single candidate who took that exam who had

any idea

how to do this on the back of an envelope.

G = gravitational constant
Me = earth mass 5.97E+27 g
Mn = moon mass 7.35E+25 g
Re = earth radius 6.371315E+08 cm
Rem = distance between moon and earth 3.844E+10 cm
T = tide height
Wm = water test mass

Gravity works on a water test mass
with force from earth and moon:

G*Me*Wm/Re^2 = G*Me*Wm/(Re+T)^2 + G*Wm*Mm/(Rem)^2


Why not 0 = the two weihts? What has the Me--Wm attraction to do with
them?

Look at it this way: