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Science Forum Index » Electronics - Basics Forum » Can 1.5 V battery kill you?
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| Polyman |
 Posted: Mon Jan 29, 2007 1:58 pm |
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Guest
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With the correct gearing ratio, a 1.5 V battery could move a house.
Suppose if you were in the path in the wrong place at the wrong time,
effectively, the 1.5 V battery could kill you.
Quote: Archimedes wrote:
Hello All
I am just starting out in electronics as a hobby. I learnt Ohms law
i.e. V=I * R
Now just say I had a 1.5 Volt battery (AA cell) and an 1 ohm resistor
So given Ohms law - to find the current
I = V / R
I = 1.5 / 1
I = 1.5 amps
So can a 1.5 V battery kill you will a 1 Ohm resistor ?
Regards,
Shelton.
Your question seems to focus on direct contact with the battery and
several thoughtful answers have been provided by others.
Although not directly discussed, it may be possible to electrocute using
the energy available from a 1.5 volt battery indirectly. The voltage
would have to be increased enough to cause a current of >5 mA through
normal skin resistance, and a sufficient amount of charge would have to
be stored in a capacitor to maintain that current flow for the necessary
duration.
Common camera flash circuits achieve sufficient voltage, but would
probably need additional capacitance to provide sufficient energy for
electrocution. Each flash drains only a fraction of the battery's
capacity, but if all the capacity were stored in a high-voltage
capacitor, discharging it through your body could be fatal.
So the answer is yes, but not simply by touching the battery.
Chuck
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| notbob |
| Posted: Mon Jan 29, 2007 2:13 pm |
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On 2007-01-28, Archimedes <shelton.dcruz@gmail.com> wrote:
Quote: So can a 1.5 V battery kill you will a 1 Ohm resistor ?
If you impart enough velocity on it.
nb |
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| Jon Slaughter |
| Posted: Mon Jan 29, 2007 2:56 pm |
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"Bob Myers" <nospamplease@address.invalid> wrote in message
news:YNrvh.538$gM5.259@news.cpqcorp.net...
Quote:
"Polyman" <polyman@cox.net> wrote in message
news:45be35a4.3975506@news.west.cox.net...
With the correct gearing ratio, a 1.5 V battery could move a house.
OK, kids, for extra credit:
1. Calculate the amount of energy required to move the average house
a significant distance - let's say, at least a foot or so.
2. Now let's calculate the total energy available in any of the
standard 1.5V cells (AAA, AA, C, D - your choice).
Well, I suppose here is your mistake bob. Polyman didn't specifically talk
about the type of battery. Its very easy to move a house using a 1.5V
battery. Ofcourse the battery would probably be just as big as the house
but I guess that is besides the point? |
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| Bob Myers |
| Posted: Mon Jan 29, 2007 3:20 pm |
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"Polyman" <polyman@cox.net> wrote in message
news:45be35a4.3975506@news.west.cox.net...
Quote: With the correct gearing ratio, a 1.5 V battery could move a house.
OK, kids, for extra credit:
1. Calculate the amount of energy required to move the average house
a significant distance - let's say, at least a foot or so.
2. Now let's calculate the total energy available in any of the
standard 1.5V cells (AAA, AA, C, D - your choice).
3. Compare these two numbers.
Bob M. |
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| Bob Myers |
| Posted: Mon Jan 29, 2007 6:12 pm |
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"Jon Slaughter" <Jon_Slaughter@Hotmail.com> wrote in message
news:mrrvh.56898$wc5.54983@newssvr25.news.prodigy.net...
Quote: Well, I suppose here is your mistake bob. Polyman didn't specifically talk
about the type of battery. Its very easy to move a house using a 1.5V
battery. Ofcourse the battery would probably be just as big as the house
but I guess that is besides the point?
I suppose. The pedant in me forces me to note that you're
unlikely to find ANY 1.5V "batteries" of ANY size; if it
puts out 1.5V, most likely it would be a "cell."
Bob M. |
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| Polyman |
| Posted: Mon Jan 29, 2007 6:30 pm |
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On Mon, 29 Jan 2007 18:56:18 GMT, "Jon Slaughter"
<Jon_Slaughter@Hotmail.com> wrote:
Quote:
"Bob Myers" <nospamplease@address.invalid> wrote in message
news:YNrvh.538$gM5.259@news.cpqcorp.net...
"Polyman" <polyman@cox.net> wrote in message
news:45be35a4.3975506@news.west.cox.net...
With the correct gearing ratio, a 1.5 V battery could move a house.
OK, kids, for extra credit:
1. Calculate the amount of energy required to move the average house
a significant distance - let's say, at least a foot or so.
2. Now let's calculate the total energy available in any of the
standard 1.5V cells (AAA, AA, C, D - your choice).
Well, I suppose here is your mistake bob. Polyman didn't specifically talk
about the type of battery. Its very easy to move a house using a 1.5V
battery. Ofcourse the battery would probably be just as big as the house
but I guess that is besides the point?
Nor did the original poster ask if it would be the voltage that would
ultamately kill you. What if the 1.5V was used to "pull a pin" as it
were to a Grenade? In that case I certainly would not want to be on
the south side of 1.5V. |
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| Homer J Simpson |
| Posted: Mon Jan 29, 2007 10:21 pm |
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"notbob" <notbob@nothome.com> wrote in message
news:a-adnWruh87bpCPYnZ2dnUVZ_uidnZ2d@comcast.com...
Quote: So can a 1.5 V battery kill you will a 1 Ohm resistor ?
If you impart enough velocity on it.
Shotgun?
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| John Popelish |
| Posted: Mon Jan 29, 2007 10:58 pm |
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Bob Myers wrote:
Quote: "Polyman" <polyman@cox.net> wrote in message
news:45be35a4.3975506@news.west.cox.net...
With the correct gearing ratio, a 1.5 V battery could move a house.
OK, kids, for extra credit:
1. Calculate the amount of energy required to move the average house
a significant distance - let's say, at least a foot or so.
Up or sideways? If sideways, it is all about the bearings
and time.
Quote: 2. Now let's calculate the total energy available in any of the
standard 1.5V cells (AAA, AA, C, D - your choice).
3. Compare these two numbers.
Bob M.
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| ehsjr |
| Posted: Tue Jan 30, 2007 1:21 am |
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John Popelish wrote:
Quote: Bob Myers wrote:
"Polyman" <polyman@cox.net> wrote in message
news:45be35a4.3975506@news.west.cox.net...
With the correct gearing ratio, a 1.5 V battery could move a house.
OK, kids, for extra credit:
1. Calculate the amount of energy required to move the average house
a significant distance - let's say, at least a foot or so.
Up or sideways? If sideways, it is all about the bearings and time.
I think you're still defeated by F=MA, even if we assume
*NO* friction. You'd need other unrealistic conditions.
You just can't get the house moving fast enough.
You can make up fantasy scenarios like a bijillion ampere
hour source or a tiny house fired as a projectile or
something equally "imaginative".
Ed
Quote:
2. Now let's calculate the total energy available in any of the
standard 1.5V cells (AAA, AA, C, D - your choice).
3. Compare these two numbers.
Bob M.
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