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Geronimo Stempovski
Posted: Wed Feb 07, 2007 5:07 am
Guest
I just read an interesting paper about high-speed I/O's power dissipation.
Unfortunately there is an equation I don't quite understand. Maybe someone
is in the mood for discussing and explaining the correctness of the equation
to me.
The formula I am talking about is (1) in the paper [
http://www.ee.ucla.edu/faculty/papers/yang-ckk_ieeeTransCircSystems2_nov2006.pdf ]

For high-common mode signaling (which standard would that be, anyway? TTL?
CMOS? SSTL?) it is assumed
P = V*Vswing/Z0 = V*Vrx/Z0*H(f)

For low-common mode signaling (LVDS? CML? LVPECL?) it states
P = Vswing^2/2*Z0 = Vrx^2/2*Z0*H(f)^2

What I don't understand is the factor 2 (2*Z0) in the calculation of the
low-common mode signaling. Furthermore I'm not sure if the H(f)^2 is
correct.

Any help is highly appreciated! Thanks a lot in advance!

Regards, Gero
operator jay
Posted: Wed Feb 07, 2007 6:41 am
Guest
"Geronimo Stempovski" <geronimo.stempovski@arcor.de> wrote in message
news:45c996d0$0$30311$9b4e6d93@newsspool1.arcor-online.net...
Quote:
I just read an interesting paper about high-speed I/O's power
dissipation.
Unfortunately there is an equation I don't quite understand. Maybe
someone is in the mood for discussing and explaining the correctness
of the equation to me.
The formula I am talking about is (1) in the paper [
http://www.ee.ucla.edu/faculty/papers/yang-ckk_ieeeTransCircSystems2_nov2006.pdf ]

For high-common mode signaling (which standard would that be,
anyway? TTL? CMOS? SSTL?) it is assumed
P = V*Vswing/Z0 = V*Vrx/Z0*H(f)

For low-common mode signaling (LVDS? CML? LVPECL?) it states
P = Vswing^2/2*Z0 = Vrx^2/2*Z0*H(f)^2

What I don't understand is the factor 2 (2*Z0) in the calculation of
the low-common mode signaling. Furthermore I'm not sure if the
H(f)^2 is correct.

Any help is highly appreciated! Thanks a lot in advance!

Regards, Gero


I don't know the topic or the equation in question, however,

P = Vpeak/sqrt(2) * Vpeak/sqrt(2) / R = Vpeak^2 / 2 * R
would give power for a simple AC voltage applied to an R. Here the
factor of 2 is 'changing' the voltages to their RMS values. Could it
be similar in the equation you are looking at?
Geronimo Stempovski
Posted: Wed Feb 07, 2007 6:49 am
Guest
"operator jay" <none@none.none> schrieb im Newsbeitrag
news:D2iyh.66715$sE7.14995@newsfe21.lga...
Quote:

factor of 2 is 'changing' the voltages to their RMS values. Could it be
similar in the equation you are looking at?

Thank you, Jay. Unforutnately not. Could I mail you the paper and you have a
look at it? What's your email adress? My email adress is valid, by the way.
Jim Granville
Posted: Wed Feb 07, 2007 2:52 pm
Guest
Geronimo Stempovski wrote:
Quote:
I just read an interesting paper about high-speed I/O's power dissipation.
Unfortunately there is an equation I don't quite understand. Maybe someone
is in the mood for discussing and explaining the correctness of the equation
to me.
The formula I am talking about is (1) in the paper [
http://www.ee.ucla.edu/faculty/papers/yang-ckk_ieeeTransCircSystems2_nov2006.pdf ]

For high-common mode signaling (which standard would that be, anyway? TTL?
CMOS? SSTL?) it is assumed
P = V*Vswing/Z0 = V*Vrx/Z0*H(f)

For low-common mode signaling (LVDS? CML? LVPECL?) it states
P = Vswing^2/2*Z0 = Vrx^2/2*Z0*H(f)^2

What I don't understand is the factor 2 (2*Z0) in the calculation of the
low-common mode signaling. Furthermore I'm not sure if the H(f)^2 is
correct.

Any help is highly appreciated! Thanks a lot in advance!

That does seem mangled.
When in doubt, check the dimensions of the answer ?

Normally where frequency is used in power calcs, it is of the form
of power dissipation capacitance : W = Fo * Cp * Vcc^2

-jg
Terry Given
Posted: Wed Feb 07, 2007 4:37 pm
Guest
Jim Granville wrote:
Quote:
Geronimo Stempovski wrote:

I just read an interesting paper about high-speed I/O's power
dissipation.
Unfortunately there is an equation I don't quite understand. Maybe
someone is in the mood for discussing and explaining the correctness
of the equation to me.
The formula I am talking about is (1) in the paper [
http://www.ee.ucla.edu/faculty/papers/yang-ckk_ieeeTransCircSystems2_nov2006.pdf
]

For high-common mode signaling (which standard would that be, anyway?
TTL? CMOS? SSTL?) it is assumed
P = V*Vswing/Z0 = V*Vrx/Z0*H(f)

For low-common mode signaling (LVDS? CML? LVPECL?) it states
P = Vswing^2/2*Z0 = Vrx^2/2*Z0*H(f)^2

What I don't understand is the factor 2 (2*Z0) in the calculation of
the low-common mode signaling. Furthermore I'm not sure if the H(f)^2
is correct.

Any help is highly appreciated! Thanks a lot in advance!


That does seem mangled.
When in doubt, check the dimensions of the answer ?

Normally where frequency is used in power calcs, it is of the form
of power dissipation capacitance : W = Fo * Cp * Vcc^2

-jg


it looks like its analagous to an RMS calculation, but made on an
unknown dataset of a particular (hardware) flavour. its a mere proof by
blatant assertion, so it'd take a fair bit of digging or maths to figure
out where it came from.

ya gotta love professional comics.

Cheers
Terry
 
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