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fourth moment of normal variable

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oercim
Posted: Fri Dec 09, 2005 10:41 am
Guest
Hello, let X is normaly distributed random variable with E(X)=0
and VAR(X)=S^2. According to an essay E(X^4)=S^4. There is not a proof
of this equality in the article. Is this equality realy true? How?
Thanks a lot.
 
Robert Vienneau
Posted: Sat Dec 10, 2005 3:33 am
Guest
In article <1134142860.406171.66790@f14g2000cwb.googlegroups.com>,
"oercim" <oercim@yahoo.com> wrote:

[quote:9bba785d2e]Hello, let X is normaly distributed random variable with E(X)=0
and VAR(X)=S^2. According to an essay E(X^4)=S^4. There is not a proof
of this equality in the article. Is this equality realy true? How?
[/quote:9bba785d2e]
I don't recall whether that's true. But in looking this up, one might
find it useful to know that the third moment about the mean is called
"skewness" and the fourth moment around the mean is called "kurtosis".
I think I recall that the kurtosis of a Gaussian-distributed random
variable is a constant.

--
Mostly economics: <http://www.dreamscape.com/rvien/#PublicationsForFun>
r c
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e a e of a man is a question fit perhaps to be discussed by
n e . slaves in the hearing of their masters, but highly
@ r c m unbecoming to reasonable and free men in search of
d o the truth. -- Rousseau
 
sinister
Posted: Wed Dec 14, 2005 6:30 am
Guest
"oercim" <oercim@yahoo.com> wrote in message
news:1134142860.406171.66790@f14g2000cwb.googlegroups.com...
[quote:72dfdff7f6]Hello, let X is normaly distributed random variable with E(X)=0
and VAR(X)=S^2. According to an essay E(X^4)=S^4. There is not a proof
of this equality in the article. Is this equality realy true? How?
[/quote:72dfdff7f6]
I don't have a proof on paper, but presumably a scaling argument would show
that
E(X^4) = C*S^4
for some constant C. (Scaling argument---just write down the integral, and
use the method of substitution to "get the S out".)

Then all one has to do is compute C in the case of S=1.

[quote:72dfdff7f6]Thanks a lot.
[/quote:72dfdff7f6]
 
 
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