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| kurt krueckeberg... |
 Posted: Sun Nov 08, 2009 1:35 am |
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Guest
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I want to change all occurances of
<FONT SIZE=3>some text goes here</FONT>
to
some text goes here</FONT>
Preferrably to just:
some text goes here
How do I compose a non-greedy regular expression to find "<FONT
SIZE=3>"? I've tried
:%s/<FONT\(.*\)\{-1}>//g
But the eliminates the entire line.
thanks. |
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| Peter Gordon... |
| Posted: Sun Nov 08, 2009 6:16 am |
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kurt krueckeberg <kkruecke at (no spam) gmail.com> wrote in news:e75a9ba1-2614-480f-
9ec8-2a09aaec72a9 at (no spam) p35g2000yqh.googlegroups.com:
Quote: FONT SIZE=3>some text goes here</FONT
If the opening & closing anchors are guaranteed to be on the
same line, the RE below will do it.
s%<FONT SIZE=3>\(.*\)</FONT>%\1% |
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| Christian Brabandt... |
| Posted: Sun Nov 08, 2009 1:01 pm |
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On 2009-11-08, kurt krueckeberg <kkruecke at (no spam) gmail.com> wrote:
Quote: I want to change all occurances of
FONT SIZE=3>some text goes here</FONT
to
some text goes here</FONT
Preferrably to just:
some text goes here
How do I compose a non-greedy regular expression to find "<FONT
SIZE=3>"? I've tried
:%s/<FONT\(.*\)\{-1}>//g
But the eliminates the entire line.
Why are you posting here and in the vim_use mailinglist?
regards,
Christian |
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| Tim Roberts... |
| Posted: Tue Nov 10, 2009 12:22 pm |
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kurt krueckeberg <kkruecke at (no spam) gmail.com> wrote:
Quote: I want to change all occurances of
FONT SIZE=3>some text goes here</FONT
to
some text goes here</FONT
Preferrably to just:
some text goes here
How do I compose a non-greedy regular expression to find "<FONT
SIZE=3>"? I've tried
:%s/<FONT\(.*\)\{-1}>//g
But the eliminates the entire line.
Think about it in words. You want <FONT followed by any number of things
that aren't >, followed by >.
:%s/<FONT[^>]*>//
--
Tim Roberts, timr at (no spam) probo.com
Providenza & Boekelheide, Inc. |
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