Hi All,

My goal is to get the oldest file using mtime.to_i then delete it.
However my
puts stats.to_a.max does not seem to print out the oldest mtime
data/file, rather its printing out the 2nd to oldest file;
prod_db_bkup_Tue2009-10-271455.gz

Correct me please and show me the code.

thx!

snip
d=Date.today
t=Time.now
require 'enumerator'
stats = Hash.new
DB_BKUP1.each do |dbfile|
stats[dbfile] = [File.stat(dbfile).mtime.to_i]
end
puts stats.to_a,"\n\n"
puts stats.to_a.max
end
prod_DB_OS_bkup.rb: 90 lines, 2627 characters.
[root at (no spam) vixxxxx /usr/local/vrep/OS_scripts]# ruby prod_DB_OS_bkup.rb
/usr/local/vrep/prod_db_bkup_Thr2009-10-29110.gz
1256828444
/usr/local/vrep/prod_db_bkup_Thr2009-10-291054.gz
1256828056
/usr/local/vrep/prod_db_bkup_Fri2009-10-301042.gz
1256913745
/usr/local/vrep/prod_db_bkup_Thr2009-10-291052.gz
1256827961
/usr/local/vrep/prod_db_bkup_Tue2009-10-271455.gz
1256669730
/usr/local/vrep/prod_db_bkup_Tue2009-10-271642.gz
1256676168


/usr/local/vrep/prod_db_bkup_Tue2009-10-271642.gz
1256676168

puts stats.sort {|x,y| x[1] <=> y[1]}.max

This explicitly sorts by the 2nd value in the to_a array, which is the
mtime.

Why do you convert the mtime (a Time object) to an integer? Time
objects are comparable. Try to omit the ".to_i" and compare the
Time objects that represent the mtimes.

Regards,
Daniel