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| Nick Bo... |
 Posted: Sat Sep 13, 2008 3:25 am |
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I am working on this assignment and this is the first class I have used
ruby with so please forgive if some of these questions seem elementary.
Basically the job is to take a string with characters "a-zA-Z0-9" and
then turn it into an array using the .split method. Then do an "each
do" loop that will run through each array of the character array and
find the ASCII value. my issue is I dont know how to take the character
and convert it into ASCII.
Here is a copy of what i got so far:
#set up first array
characters = 'a b c d e f g h i j k l m n o p q r s t u v w x y z A B C
D E F ...G ...H I J K L M N O P Q R S T U V W X Y Z 0 1 2 3 4 5 6 7 8
9'
characterArray = characters.split
#set up next array by using a loop to determine the ASCII value of each
...character
characterArray.each do |ascii|
print "#{ascii} \n"
end
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| James Gray... |
| Posted: Sat Sep 13, 2008 4:40 am |
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On Sep 12, 2008, at 5:25 PM, Nick Bo wrote:
Quote: my issue is I dont know how to take the character
and convert it into ASCII.
In Ruby 1.8 you can just index into the String and Ruby will return
the character value:
Hope that helps and welcome to Ruby!
James Edward Gray II |
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| Todd Benson... |
| Posted: Sat Sep 13, 2008 5:20 am |
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On Fri, Sep 12, 2008 at 6:40 PM, James Gray <james at (no spam) grayproductions.net> wrote:
Quote: On Sep 12, 2008, at 5:25 PM, Nick Bo wrote:
my issue is I dont know how to take the character
and convert it into ASCII.
In Ruby 1.8 you can just index into the String and Ruby will return the
character value:
"a"[0]
=> 97
Hope that helps and welcome to Ruby!
Also, if you are required to iterate, you can do String#each_byte
after an Array#join, but I don't think that's what you are looking
for, but I couldn't resist (I know I'm a clown)...
[('a'..'z'),('A'..'Z'),('0'..'9')].inject([]){|s,i|s+i.map}.join.each_byte{|b|p
b}
If you need to do an each/do, you should probably do as James suggests.
Todd |
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| Nick Bo... |
| Posted: Thu Sep 18, 2008 6:17 am |
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Thanks for all the help but with a little more research i found this to
be the easiest solution for my beginner knowledge thanks for all the
help.
#set up first array
characters = 'a b c d e f g h i j k l m n o p q r s t u v w x y z A B C
D E F G ...H I J K L M N O P Q R S T U V W X Y Z 0 1 2 3 4 5 6 7 8 9'
characterArray = characters.split
#set up next array by using a loop to determine the ASCII value of each
...character
ascii=""
characterArray.each do |a|
ascii << "#{a.to_s[0]} \t"
end
#take the ascii string and then do a .split in order to build another
array.
asciiArray = ascii.split
#start the table format
print "Character \t ASCII \n"
#initialize i as 0 in order to go through each array and print the
character ...and ascii value.
i=0
#print each value and keep doing it until there is no more arrays for
...asciiArray (would work for characterArray as well)
asciiArray.each do
print "#{characterArray[i]} \t \t #{asciiArray[i]} \n"
i=i+1
end
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| Rajinder Yadav... |
| Posted: Fri Oct 30, 2009 5:17 am |
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Aaron Burgess wrote:
Quote: This is much easier and more efficient than of the suggestions on this
site. You should not have to index anything.
letters =
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
character = letters.split(//)
ascii=[]
character.each do |a|
ascii << "#{a} \t #{a[0]}"
end
puts ascii
- aaron burgess
You could also reduce the number of loops from 2xO(n) to O(n) with
word="hello world!"
letters=[]
for i in 0...word.size # note use of 3 dots for exclusive range
letters << word[i].chr
end
p letters
=>["h", "e", "l", "l", "o", " ", "w", "o", "r", "l", "d", "!"]
--
Kind Regards,
Rajinder Yadav
http://DevMentor.org
Do Good! - Share Freely, Enrich and Empower people to Transform their lives. |
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| Greg Barozzi... |
| Posted: Fri Oct 30, 2009 5:17 am |
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Trick Nick wrote:
Quote: Thanks for all the help but with a little more research i found this to
be the easiest solution for my beginner knowledge thanks for all the
help.
This way works as well and is shorter:
# set up the array
arr = (('0'..'9').map + ('A'..'Z').map + ('a'..'z').map).flatten
# convert the array to a string
str = arr.to_s
# print the ascii table
str.length.times do |i|
puts "#{str[i,1]} \t #{str[i]}"
end
Welcome to Ruby! 
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| Aaron Burgess... |
| Posted: Fri Oct 30, 2009 5:17 am |
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Guest
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This is much easier and more efficient than of the suggestions on this
site. You should not have to index anything.
letters =
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
character = letters.split(//)
ascii=[]
character.each do |a|
ascii << "#{a} \t #{a[0]}"
end
puts ascii
- aaron burgess
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